
Concept explainers
(a)
Interpretation: The validation for the presence of a
Concept introduction: Maltose is a disaccharide and it is also known as malt sugar. It is commonly found in baby foods and malted milk. Two glucose units are present in maltose joined together by
(b)
Interpretation: The validation for the presence of a
Concept introduction: Like maltose, cellobiose is a disaccharide and it contains two monosaccharide units of D-glucose joined together by
(c)
Interpretation: The validation for the presence of a
Concept introduction: Lactose is a disaccharide and it contains two monosaccharide units, D-galactose and D-glucose which are joined together by
(d)
Interpretation: The validation for the presence of a
Concept introduction: Sucrose is a disaccharide and it contains two monosaccharide units, Fructose and Glucose. These monosaccharide units are joined together by

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Chapter 18 Solutions
General, Organic, and Biological Chemistry Seventh Edition
- A mixture of C7H12O2, C9H9OCl, biphenyl and acetone was put together in a gas chromatography tube. Please decide from the GC resutls which correspond to the peak for C7,C9 and biphenyl and explain the reasoning based on GC results. Eliminate unnecessary peaks from Gas Chromatography results.arrow_forwardIs the molecule chiral, meso, or achiral? CI .CH3 H₂C CIarrow_forwardPLEASE HELP ! URGENT!arrow_forward
- Identify priority of the substituents: CH3arrow_forwardHow many chiral carbons are in the molecule? OH F CI Brarrow_forwardA mixture of three compounds Phen-A, Acet-B and Rin-C was analyzed using TLC with 1:9 ethanol: hexane as the mobile phase. The TLC plate showed three spots of R, 0.1 and 0.2 and 0.3. Which of the three compounds (Phen-A; Acet-B or Rin-C) would have the highest (Blank 1), middle (Blank 2) and lowest (Blank 3) spot respectively? 0 CH: 0 CH, 0 H.C OH H.CN OH Acet-B Rin-C phen-A A A <arrow_forward
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