
Concept explainers
(a)
Interpretation:
Need to write the cell reaction for the
Concept introduction:
Since the electrolysis of AgNO3 takes in aqueous solution, reduction of Ag+ was done by the electrons obtained by the oxidation of water. Mass of the metal produced was given, from that number of moles of Ag produced can be calculated. For the reduction of one moles of Ag+ ion, one mole of electron was need. So the number of mole of silver produced is equal to the number of moles of electrons needed. The coulomb of charges can be attained by the multiplication of moles of electron with Faraday constant.
To find: Cell reaction of the electrolysis of AgNO3 in aqueous solution and number of charges need to deposit 0.67g of silver.
(b)
Interpretation:
Need to write the cell reaction for the electrolysis of aqueous AgNO3 solution and calculate the amount of charges used to deposit 0.67g of silver.
Concept introduction:
Since the electrolysis of AgNO3 takes in aqueous solution, reduction of Ag+ was done by the electrons obtained by the oxidation of water. Mass of the metal produced was given, from that number of moles of Ag produced can be calculated. For the reduction of one moles of Ag+ ion, one mole of electron was need. So the number of mole of silver produced is equal to the number of moles of electrons needed. The coulomb of charges can be attained by the multiplication of moles of electron with Faraday constant.
To find: Cell reaction of the electrolysis of AgNO3 in aqueous solution and number of charges need to deposit 0.67g of silver.
(c)
Interpretation:
Need to write the cell reaction for the electrolysis of aqueous AgNO3 solution and calculate the amount of charges used to deposit 0.67g of silver.
Concept introduction:
Since the electrolysis of AgNO3 takes in aqueous solution, reduction of Ag+ was done by the electrons obtained by the oxidation of water. Mass of the metal produced was given, from that number of moles of Ag produced can be calculated. For the reduction of one moles of Ag+ ion, one mole of electron was need. So the number of mole of silver produced is equal to the number of moles of electrons needed. The coulomb of charges can be attained by the multiplication of moles of electron with Faraday constant.
To find: Cell reaction of the electrolysis of AgNO3 in aqueous solution and number of charges need to deposit 0.67g of silver.

Want to see the full answer?
Check out a sample textbook solution
Chapter 18 Solutions
GEN COMBO CHEMISTRY: ATOMS FIRST; ALEKS 360 2S ACCESS CARD CHEMISTRY:ATOMS FIRST
- Part 1. Draw monomer units of the following products and draw their reaction mechanism (with arrow pushing) Temporary cross-linked polymer Using: 4% polyvinyl alcohol+ methyl red + 4% sodium boratearrow_forwardcan you please answer both these questions and draw the neccesaryarrow_forwardcan you please give the answer for both these pictures. thankyouarrow_forward
- Part 1. Draw monomer units of the following products and draw their reaction mechanism (with arrow pushing) | Bakelite like polymer Using: Resorcinol + NaOH + Formalinarrow_forwardQuestion 19 0/2 pts 3 Details You have a mixture of sodium chloride (NaCl) and potassium chloride (KCl) dissolved in water and want to separate out the Cl- ions by precipitating them out using silver ions (Ag+). The chemical equation for the net ionic reaction of NaCl and KCl with silver nitrate, AgNO3, is shown below. Ag+(aq) + Cl(aq) → AgCl(s) The total mass of the NaCl/KCl mixture is 1.299 g. Adding 50.42 mL of 0.381 M solution precipitates out all of the Cl-. What are the masses of NaCl and KCl in the mixture? Atomic masses: g: Mass of NaCl g: Mass of KCL Ag = 107.868 g mol- 1 Cl = 35.453 g mol- 1 K = 39.098 g mol- N = 14.007 g mol−1 Na = 22.99 g mol−1 0 = 15.999 g mol 1 Question Help: ✓ Message instructor Submit Questionarrow_forwardPart 1. Draw monomer units of the following products and draw their reaction mechanism (with arrow pushing) Polyester fiber Using a) pthalic anhydride + anhydrous sodium acetate + ethylene glycol B)pthalic anhydride + anhydrous sodium acetate + glycerolarrow_forward
- Identify the missing starting materials/ reagents/ products in the following reactions. Show the stereochemistry clearly in the structures, if any. If there is a major product, draw the structures of the major product with stereochemistry clearly indicated where applicable. Show only the diastereomers (you do not have to draw the pairs of enantiomers). If you believe that multiple products are formed in approximately equal amounts (hence neither is the major product), draw the structures of the products, and show the detailed mechanism of these reactions to justify the formation of the multiple products. If you believe no product is formed, explain why briefly. (6 mark for each, except f and g, which are 10 mark each)arrow_forward3. What starting material would you use to synthesize 3-hydroxypentanoic acid using a NaBH4 reduction?arrow_forward1. Give stereochemical (Fischer projection) formulas for all (but no extras) the stereoisomers that could theoretically form during the reduction of a. the carbonyl group of 2-methyl-3--pentanone b. both carbonyl groups of 2,4-pentanedione (careful!) 2. Predict the products of the reduction of O=CCH2CH2CH2C=O with a. LiAlH4 b. NaBH4 CH3 OHarrow_forward
- Chemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningChemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning
- Principles of Modern ChemistryChemistryISBN:9781305079113Author:David W. Oxtoby, H. Pat Gillis, Laurie J. ButlerPublisher:Cengage LearningChemistry: Matter and ChangeChemistryISBN:9780078746376Author:Dinah Zike, Laurel Dingrando, Nicholas Hainen, Cheryl WistromPublisher:Glencoe/McGraw-Hill School Pub Co



