Elements of Chemical Reaction Engineering (5th Edition) (Prentice Hall International Series in the Physical and Chemical Engineering Sciences)
5th Edition
ISBN: 9780133887518
Author: H. Scott Fogler
Publisher: Prentice Hall
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Question
Chapter 18, Problem 18.15P
(a)
Interpretation Introduction
Interpretation:
The curve that corresponds to the highest peclet number in the given
Concept introduction:
The number that is utilized in the calculation which includes convective heat transfer is known as peclet number. This number is dimensionless. This number represents the ratio of convected thermal energy to the fluid and to the conducted thermal energy of the fluid.
(b)
Interpretation Introduction
Interpretation:
The curve that corresponds to the highest dispersion coefficient in the given
Concept introduction:
The coefficient that is usually represented as the function of distance corresponding to the weather stability is known as dispersion coefficient. It is denoted by
(c)
Interpretation Introduction
Interpretation:
The curve that corresponds to the largest number of T-I-S in the given
Concept introduction:
A model that is used to explain the behavior of the electrolytic flow within the electrochemical reactor’s tank which is continuously stirred is known as tank-in-series model.
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Example (6):
An evaporator is concentrating F kg/h at
311K of a 20wt% solution of NaOH to 50wt
%. The saturated steam used for heating is
at 399.3K. The pressure in the vapor space
of the evaporator is 13.3 KPa abs. The
5:48
O
Transcribed Image Text: Example (7): Determine the
14.9. A forward feed double-effect vertical
evaporator, with equal heating areas in
each effect, is fed with 5 kg/s of a liquor
of specific heat capacity of 4.18 kJ/kg K.
and with no boiling point rise, so that 50
per cent of the feed liquor is evaporated.
The overall heat transfer coefficient in the
second effect is 75 per cent of that in the
first effect. Steam is fed at 395 K and the
boiling point in the second effect is 373 K.
The feed is heated by an external heater to
the boiling point in the first effect.
It is decided to bleed off 0.25 kg/s of
vapour from the vapour line to the second
effect for use in another process. If the
feed is still heated to the boiling point of
the first effect by external means, what
will be the change in steam consumption
of the evaporator unit? For the purpose of
calculation, the latent heat of the vapours
and of the steam may both be taken as
2230 kJ/kg
Example(3):
It is desired to design a double effect
evaporator for concentrating a certain
caustic soda solution from 12.5wt% to
40wt%. The feed at 50°C enters the first
evaporator at a rate of 2500kg/h. Steam
at atmospheric pressure is being used
for the said purpose. The second effect
is operated under 600mmHg vacuum. If
the overall heat transfer coefficients of
the two stages are 1952 and 1220kcal/
m2.h.°C. respectively, determine the heat
transfer area of each effect. The BPR will
be considered and present for the both
effect
5:49
Chapter 18 Solutions
Elements of Chemical Reaction Engineering (5th Edition) (Prentice Hall International Series in the Physical and Chemical Engineering Sciences)
Ch. 18 - The second-order liquid-phase reaction AB+C is to...Ch. 18 - The elementary liquid-phase reaction...Ch. 18 - Prob. 18.5PCh. 18 - Use the data in Example 16-2 to make the following...Ch. 18 - A tubular reactor has been sized to obtain 98%...Ch. 18 - Prob. 18.11PCh. 18 - Prob. 18.13PCh. 18 - Prob. 18.14PCh. 18 - Prob. 18.15PCh. 18 - Consider the following system in Figure P18-16C...
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Similar questions
- العنوان ose only Q Example (7): Determine the heating surface area 개 required for the production of 2.5kg/s of 50wt% NaOH solution from 15 wt% NaOH feed solution which entering at 100 oC to a single effect evaporator. The steam is available as saturated at 451.5K and the boiling point rise (boiling point evaluation) of 50wt% solution is 35K. the overall heat transfer coefficient is 2000 w/m²K. The pressure in the vapor space of the evaporator at atmospheric pressure. The solution has a specific heat of 4.18kJ/ kg.K. The enthalpy of vaporization under these condition is 2257kJ/kg Example (6): 5:48 An evaporator is concentrating F kg/h at 311K of a 20wt% solution of NaOH to 50wt %. The saturated steam used for heating is at 399.3K. The pressure in the vapor space of the evaporator is 13.3 KPa abs. The 5:48 1 J ۲/۱ ostrarrow_forwardExample 8: 900 Kg dry solid per hour is dried in a counter current continues dryer from 0.4 to 0.04 Kg H20/Kg wet solid moisture content. The wet solid enters the dryer at 25 °C and leaves at 55 °C. Fresh air at 25 °C and 0.01Kg vapor/Kg dry air is mixed with a part of the moist air leaving the dryer and heated to a temperature of 130 °C in a finned air heater and enters the dryer with 0.025 Kg/Kg alry air. Air leaving the dryer at 85 °C and have a humidity 0.055 Kg vaper/Kg dry air. At equilibrium the wet solid weight is 908 Kg solid per hour. *=0.0088 Calculate:- Heat loss from the dryer and the rate of fresh air. Take the specific heat of the solid and moisture are 980 and 4.18J/Kg.K respectively, A. =2500 KJ/Kg. Humid heat at 0.01 Kg vap/Kg dry=1.0238 KJ/Kg. "C. Humid heat at 0.055 Kg/Kg 1.1084 KJ/Kg. "C 5:42 Oarrow_forwardQ1: From the Figure below for (=0.2 find the following 1. Rise Time 2. Time of oscillation 3. Overshoot value 4. Maximum value 5. When 1.2 which case will be? 1.6 1.4 1.2 12 1.0 |=0.8- 0.6 0.4 0.8 0.2- 0.6 0.4 0.2 1.2 = 1.0 0 2 4 6 8 10 10 t/Tarrow_forward
- A system, in a closed container, consists of an unknown number of components and three phases. You are told that the system is fully defined by giving you only one mole fraction! What is the number components that is present? 3 1 2 The question is ill-posed.arrow_forwardA mixture of 2 components in 2 phases are present. You are given the temperature and mole fraction. How many additional variables can be specified before the system is completely determined? none 2 the system is overspecified 1 3arrow_forwardAt a Pressure of 600 mm Hg, match the substance with the boiling temperature. 54.69°C 1. n-Pentane 49.34°C 2. n-Hexane 3. Acetone 29.32°C く 61.40°C 4. Chloroformarrow_forward
- A mixture of oil and gas flows through a horizontal pipe with an inside diameter of 150 mm. The respective volumetric flow rates for the oil and gas are 0.015 and 0.29 m³s-1. Determine the gas void frac- tion and the average velocities of the oil and gas. The friction factor may be assumed to be 0.0045. The gas has a density of 2.4 kgm³ and viscosity of 1 x 10-5 Nsm-2. The oil has a density of 810 kgm³ and density of 0.82 Nsm². Answer: 0.79, 20.8 ms-1, 4 ms-1arrow_forward4. An experimental test rig is used to examine two-phase flow regimes in horizontal pipelines. A particular experiment involved uses air and water at a temperature of 25°C, which flow through a horizontal glass tube with an internal diameter of 25.4 mm and a length of 40 m. Water is admitted at a controlled rate of 0.026 kgs at one end and air at a rate of 5 x 104 kgs in the same direction. The density of water is 1000 kgm³, and the density of air is 1.2 kgm3. Determine the mass flow rate, the mean density, gas void fraction, and the superficial velocities of the air and water. Answer: 0.02605 kgs 1, 61.1 kgm³, 0.94, 0.822 ms-1, 0.051 ms-1arrow_forward1. Determine the range of mean density of a mixture of air in a 50:50 oil-water liquid phase across a range of gas void fractions. The den- sity of oil is 900 kgm³, water is 1000 kgm³, and gas is 10 kgm³. 2. Describe, with the use of sketches, the various flow regimes that can exist in a vertical pipe carrying two-phase flow (liquid and gas).arrow_forward
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