Delmar's Standard Textbook Of Electricity
7th Edition
ISBN: 9781337900348
Author: Stephen L. Herman
Publisher: Cengage Learning
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Chapter 18, Problem 11PP
In an R-L parallel circuit,
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With the aid of a phasor diagram show that the active
power and power factor of a balanced three-phase load
can be measured by two wattmeters.
For a certain load, one wattmeter indicated 20 kW
and the other 5 kW after the voltage circuit of this
wattmeter had been reversed. Calculate the active
power and the power factor of the load.
ANS:
15 kW, 0.327
State the advantages to be gained by raising the power
factor of industrial loads.
A 400 V, 50 Hz, three-phase motor takes a line
current of 15.0 A when operating at a lagging power
factor of 0.65. When a capacitor bank is connected
across the motor terminals, the line current is reduced
to 11.5 A. Calculate the rating (in kVA) and the capa
citance per phase of the capacitor bank for: (a) star
connection; (b) delta connection. Find also the new
overall power factor.
ANS:
3.81 kvar, 70.5 µF, 23.5 µF, 0.848 lagging
A single wattmeter is used to measure the total active
power taken by a 400 V, three-phase induction motor.
When the output power of the motor is 15 kW, the
efficiency is 88 per cent and the power factor is 0.84
lagging. The current coil of the wattmeter is connected
in the yellow line. With the aid of a phasor diagram,
calculate the wattmeter indication when the voltage
circuit is connected between the yellow line and (a) the
red line, (b) the blue line. Show that the sum of the two
wattmeter indications gives the total active power taken
by the motor. Assume the phase sequence to be R–Y–B.
ANS: 11.7 kW, 5.33 kW
Chapter 18 Solutions
Delmar's Standard Textbook Of Electricity
Ch. 18 - 1. When an inductor and a resistor are connected...Ch. 18 - 2. An inductor and resistor are connected in...Ch. 18 - 3. What is the impedance of the circuit in...Ch. 18 - 4. What is the power factor of the circuit in...Ch. 18 - How many degrees out of phase are the current and...Ch. 18 - 6. In the circuit shown in Figure 18-1, the...Ch. 18 - 7. A resistor and an inductor are connected in...Ch. 18 - The R-L parallel circuit shown in Figure 18-1 has...Ch. 18 - The R-L parallel circuit shown in Figure 18-1 has...Ch. 18 - How many degrees out of phase are the total...
Ch. 18 - Incandescent lighting of 500 W is connected in...Ch. 18 - You are working on a residential heat pump. The...Ch. 18 - Assume that the circuit shown in Figure 18-1 is...Ch. 18 - Assume that the current flow through the resistor,...Ch. 18 - Assume that the circuit in Figure 18-1 has an...Ch. 18 - Assume that the circuit in Figure 18-1 has a power...Ch. 18 - In an R-L parallel circuit, R=240 and XL=360. Find...Ch. 18 - In an R-L parallel circuit, IT=0.25 amps, IR=0.125...Ch. 18 - In an R-L parallel circuit, ET=120 volts,...Ch. 18 - In an R-L parallel circuit, ET=48 volts, IT=0.25...Ch. 18 - In an R-L parallel circuit, ET=240 volts, R=560 R...Ch. 18 - In an R-L parallel circuit, ET=240 volts, R=560,...Ch. 18 - In an R-L parallel circuit, ET=208 volts, R=2.4k,...Ch. 18 - In an R-L parallel circuit, ET=480 volts, R=16,...Ch. 18 - In an R-L parallel circuit, IT=1.25 amps, R=1.2k,...Ch. 18 - In an R-L parallel circuit, true power =4.6 watts...Ch. 18 - An R-L parallel circuit is connected to 240 volts...Ch. 18 - An R-L parallel circuit has an applied voltage of...
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