Products for given reactions has to be drawn. Concept introduction: Given reactions are alkylation at the β carbon of the α , β − unsaturated compound. An α , β − unsaturated compound can react with a β -diketone, β -diester, β -keto nitrile, or β -ketoester. The reaction is called Michael reaction.

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Chapter 17.9, Problem 18P

(a)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

(b)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

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Technetium is the first element in the periodic chart that does not have any stable isotopes. Technetium-99m is an especially interesting and valuable isotope as it emits a gamma ray with a half life ideally suited for medical tests. It would seem that the decay of technetium should fit the treatment above with the result In(c/c) = -kt. The table below includes data from the two sites: http://dailymed.nlm.nih.gov/dailymed/druginfo.cfm?id=7130 http://wiki.medpedia.com/Clinical: Neutrospec_(Technetium_(99m Tc)_fanolesomab). a. b. C. Graph the fraction (c/c.) on the vertical axis versus the time on the horizontal axis. Also graph In(c/c.) on the vertical axis versus time on the horizontal axis. When half of the original amount of starting material has hours fraction remaining disappeared, c/c = ½ and the equation In(c/c.) = -kt becomes In(0.5) = -kt1/2 where t₁₂ is the half life (the time for half of the material to decay away). Determine the slope of your In(c/c.) vs t graph and…

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1. a) Assuming that an atom of arsenic has hydrogen-like atomic orbitals, sketch the radial probability plots for 4p and 4d orbitals of S atom. Indicate angular and radial nodes in these orbitals. (4 points) b) Calculate Zeff experienced by and electron in 4p AO's in a arsenic atom. Use Slater rules that were discussed in lecture. (3 points)

Answer 2

Question

Chapter 17.9, Problem 18P

(a)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

(b)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

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Answer 3

Question

Chapter 17.9, Problem 18P

(a)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

(b)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

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Answer 4

Question

Chapter 17.9, Problem 18P

(a)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

(b)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

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Answer 5

Chapter 17.9, Problem 18P

(a)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

(b)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

Answer 6

Chapter 17.9, Problem 18P

(a)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

Answer 7

Chapter 17.9, Problem 18P

(a)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

Answer 8

(b)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

Answer 9

(b)

Interpretation Introduction

Interpretation: Products for given reactions has to be drawn.

Concept introduction: Given reactions are alkylation at the β carbon of the α,β− unsaturated compound. An α,β− unsaturated compound can react with a β-diketone, β-diester, β-keto nitrile, or β-ketoester. The reaction is called Michael reaction.

Answer 10

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Answer 13

Ch. 17.1 - Prob. 1P Ch. 17.1 - Prob. 2P Ch. 17.1 - Prob. 3P Ch. 17.1 - Prob. 4P Ch. 17.1 - Rank the compounds in each of the following groups...Ch. 17.2 - Explain why 92% of 2,4-pemtanedione exists as the...Ch. 17.3 - Draw the enol tautomers for each of the following...Ch. 17.3 - Prob. 8P Ch. 17.4 - Prob. 9P Ch. 17.4 - Prob. 10P

Solution Summary: The author explains that products for given reactions have to be drawn.

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