Explanation The given inequality is x 2 + 3 x ≥ 0 . Factor the inequality as follows. x 2 + 3 x ≥ 0 x ( x + 3 ) ≥ 0 Setting each factors equal to zero the critical values are found as follows. x ( x + 3 ) = 0 implies x = 0 , x = − 3 The critical values are x = 0 and x = − 3 . Therefore, we determine the sign of the given function for each of the intervals x < − 3 , − 3 < x < 0 , and x > 0 . The sign of the function for corresponding intervals are tabulated as follows. Interval Test value x ( x + 3 ) Sign x < − 3 ( − ∞ , − 3 ) − 4 ( − ) ( − ) +

Basic Technical Mathematics with Calculus (11th Edition)

11th Edition

ISBN: 9780134437736

Author: Allyn J. Washington, Richard Evans

Publisher: PEARSON

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Chapter 17.3, Problem 4E

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Chapter 17 Solutions

Basic Technical Mathematics with Calculus (11th Edition)

Ch. 17.1 - For −6 < 3, determine the inequality if 1. 8 is...Ch. 17.1 - Prob. 2PE Ch. 17.1 - For the inequality −6 < 3, state the inequality...Ch. 17.1 - Prob. 4PE Ch. 17.1 - Prob. 5PE Ch. 17.1 - In Exercises 1–4, make the given changes in the...Ch. 17.1 - Prob. 2E Ch. 17.1 - Prob. 3E Ch. 17.1 - Prob. 4E Ch. 17.1 - In Exercises 5–12, for the inequality 4 < 9, state...

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