Explanation The given inequality is x 2 − 6 x − 7 x + 5 > 0 . The numerator x 2 − 6 x − 7 is first factored as follows. x 2 − 6 x − 7 = x ( x − 7 ) + 1 ( x − 7 ) = ( x + 1 ) ( x − 7 ) The inequality is rewritten as follows. ( x + 1 ) ( x − 7 ) ( x + 5 ) > 0 Setting each factors of denominator and numerator equal to zero the critical values are found as follows. ( x − 7 ) = 0 implies x = 7 , ( x + 1 ) =0 implies x = − 1 and ( x + 5 ) = 0 implies x = − 5 The critical values are x = − 7 , x = − 1 and x = − 5 . Therefore, we determine the sign of the given function for each of the intervals x < − 5 , − 5 < x < − 1 , − 1 < x < 7 and x > 7 . The sign of the function for corresponding intervals are tabulated as follows

Basic Technical Mathematics with Calculus (11th Edition)

11th Edition

ISBN: 9780134437736

Author: Allyn J. Washington, Richard Evans

Publisher: PEARSON

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Chapter 17.3, Problem 19E

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Chapter 17.3, Problem 18E

Chapter 17.3, Problem 20E

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(a) Test the hypothesis. Consider the hypothesis test Ho = : against H₁o < 02. Suppose that the sample sizes aren₁ = 7 and n₂ = 13 and that $² = 22.4 and $22 = 28.2. Use α = 0.05. Ho is not ✓ rejected. 9-9 IV (b) Find a 95% confidence interval on of 102. Round your answer to two decimal places (e.g. 98.76).

Let us suppose we have some article reported on a study of potential sources of injury to equine veterinarians conducted at a university veterinary hospital. Forces on the hand were measured for several common activities that veterinarians engage in when examining or treating horses. We will consider the forces on the hands for two tasks, lifting and using ultrasound. Assume that both sample sizes are 6, the sample mean force for lifting was 6.2 pounds with standard deviation 1.5 pounds, and the sample mean force for using ultrasound was 6.4 pounds with standard deviation 0.3 pounds. Assume that the standard deviations are known. Suppose that you wanted to detect a true difference in mean force of 0.25 pounds on the hands for these two activities. Under the null hypothesis, 40 = 0. What level of type II error would you recommend here? Round your answer to four decimal places (e.g. 98.7654). Use a = 0.05. β = i What sample size would be required? Assume the sample sizes are to be equal.…

= Consider the hypothesis test Ho: μ₁ = μ₂ against H₁ μ₁ μ2. Suppose that sample sizes are n₁ = 15 and n₂ = 15, that x1 = 4.7 and X2 = 7.8 and that s² = 4 and s² = 6.26. Assume that o and that the data are drawn from normal distributions. Use απ 0.05. (a) Test the hypothesis and find the P-value. (b) What is the power of the test in part (a) for a true difference in means of 3? (c) Assuming equal sample sizes, what sample size should be used to obtain ẞ = 0.05 if the true difference in means is - 2? Assume that α = 0.05. (a) The null hypothesis is 98.7654). rejected. The P-value is 0.0008 (b) The power is 0.94 . Round your answer to four decimal places (e.g. Round your answer to two decimal places (e.g. 98.76). (c) n₁ = n2 = 1 . Round your answer to the nearest integer.

Chapter 17 Solutions

Basic Technical Mathematics with Calculus (11th Edition)

Ch. 17.1 - For −6 < 3, determine the inequality if 1. 8 is...Ch. 17.1 - Prob. 2PE Ch. 17.1 - For the inequality −6 < 3, state the inequality...Ch. 17.1 - Prob. 4PE Ch. 17.1 - Prob. 5PE Ch. 17.1 - In Exercises 1–4, make the given changes in the...Ch. 17.1 - Prob. 2E Ch. 17.1 - Prob. 3E Ch. 17.1 - Prob. 4E Ch. 17.1 - In Exercises 5–12, for the inequality 4 < 9, state...

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