a) (Z)-2-Ethyl-2-buten-1-ol Interpretation: To draw the structure of (Z)-2-ethyl-2-buten-1-ol. Concept introduction: The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group. E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned. To draw: The structure of (Z)-2-ethyl-2-buten-1-ol.

Question

5. Compressibility (6 points total). The isothermal compressibility is a measure of how hard/easy it is to compress an object (how squishy is it?) at constant temperature. It is др defined as Br=-()=-(200²)T' (a) You might wonder why there is a negative sign in this formula. What does it mean when this quantity is positive and what does it mean when this quantity is negative? (b) Derive the formula for the isothermal compressibility of an ideal gas (it is very simple!) (c) Explain under what conditions for the ideal gas the compressibility is higher or lower, and why that makes sense.

Answer 1

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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5. Compressibility (6 points total). The isothermal compressibility is a measure of how hard/easy it is to compress an object (how squishy is it?) at constant temperature. It is др defined as Br=-()=-(200²)T' (a) You might wonder why there is a negative sign in this formula. What does it mean when this quantity is positive and what does it mean when this quantity is negative? (b) Derive the formula for the isothermal compressibility of an ideal gas (it is very simple!) (c) Explain under what conditions for the ideal gas the compressibility is higher or lower, and why that makes sense.

19. (3 pts) in Chapter 7 we will see a reaction of halocyclohexanes that requires that the halogen occupy an axial position with this in mind, would you expect cis-1-bromo-3-methylcyclohexane or trans-1-bromo-3-methylcyclohexane to be more reactive in this reaction? Briefly explain your choice using structures to support your answer. Mere-eries-cecleone) The tran-i-browse-3-methylcyclohexione

Please help me calculate the undiluted samples ppm concentration. My calculations were 280.11 ppm. Please see if I did my math correctly using the following standard curve. Link: https://mnscu-my.sharepoint.com/:x:/g/personal/vi2163ss_go_minnstate_edu/EVSJL_W0qrxMkUjK2J3xMUEBHDu0UM1vPKQ-bc9HTcYXDQ?e=hVuPC4

Answer 2

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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Answer 3

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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Answer 4

Question

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

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Answer 5

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

Answer 6

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Answer 7

Chapter 17.1, Problem 2P

Interpretation Introduction

a)(Z)-2-Ethyl-2-buten-1-ol

Interpretation:

To draw the structure of (Z)-2-ethyl-2-buten-1-ol.

Concept introduction:

The longest continuous carbon chain which contains the hydroxyl group and any other functional group present is chosen. The chain is numbered from the end that gives the lowest number to the carbon with –OH group.

E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.

To draw:

The structure of (Z)-2-ethyl-2-buten-1-ol.

Answer 8

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Answer 9

Interpretation Introduction

b)3-Cyclohexene-1-ol

Interpretation:

To draw the structure of 3-cyclohexene-1-ol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of 3-cyclohexene-1-ol.

Answer 10

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Answer 11

Interpretation Introduction

c) trans-3-Chlorocycloheptanol

Interpretation:

To draw the structure of trans-3-chlorocycloheptanol.

Concept introduction:

In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.

To draw:

The structure of trans-3-chlorocycloheptanol.

Answer 12

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Answer 13

Interpretation Introduction

d) 1, 4-Pentanediol

Interpretation:

To draw the structure of 1, 4-pentanediol.

Concept introduction:

Alcohols are named as derivatives of the parent alkane using the suffix –ol. The longest carbon chain containing the hydroxyl group is chosen and the parent name is derived by replacing the ending –e with –ol. He alkane chain is numbered beginning at the end nearer to the hydroxyl group. The substituents are numbered according to their position on the chain. The name is written listing the substituents in the alphabetical order and indicating the position to which –OH is bonded.

To draw:

The structure of 1, 4-pentanediol.

Answer 14

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Answer 15

Interpretation Introduction

e) 2, 6-Dimethylphenol

Interpretation:

To draw the structure of 2, 6-dimethylphenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of 2, 6-dimethylphenol.

Answer 16

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

Answer 17

Interpretation Introduction

f) o-(2-hydroxyethyl) phenol.

Interpretation:

To draw the structure of o-(2-hydroxyethyl) phenol.

Concept introduction:

Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.

To draw:

The structure of o-(2-hydroxyethyl) phenol.

Answer 18

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Answer 19

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Ch. 17.1 - Give IUPAC names for the following compounds:Ch. 17.1 - Prob. 2P Ch. 17.2 - The following data for isomeric four-carbon...Ch. 17.2 - Rank the following substances in order of...Ch. 17.2 - Prob. 5P Ch. 17.3 - Prob. 6P Ch. 17.4 - What reagent would you use to accomplish each of...Ch. 17.4 - Prob. 8P Ch. 17.5 - Prob. 9P Ch. 17.5 - Prob. 10P

Chapter 17 Solutions