a)(Z)-2-Ethyl-2-buten-1-ol
Interpretation:
To draw the structure of (Z)-2-ethyl-2-buten-1-ol.
Concept introduction:
The longest continuous carbon chain which contains the hydroxyl group and any other
E-Z notation is used to represent the arrangement of different groups around the double bond. Applying the sequence rules the groups attached to the double bond are ranked as either higher or lower. If the groups of similar ranking on each carbon are arranged on the same side of the double bond then Z configuration is assigned. If the groups of similar rankings on each carbon are arranged on the opposite sides of the double bond then E configuration is assigned.
To draw:
The structure of (Z)-2-ethyl-2-buten-1-ol.
b)3-Cyclohexene-1-ol
Interpretation:
To draw the structure of 3-cyclohexene-1-ol.
Concept introduction:
In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.
To draw:
The structure of 3-cyclohexene-1-ol.
c) trans-3-Chlorocycloheptanol
Interpretation:
To draw the structure of trans-3-chlorocycloheptanol.
Concept introduction:
In naming cyclic alcohols the parent name is derived from the cycloalkene ring by replacing –e of the cycloalkene with –ol. The ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbons in the double bond.
To draw:
The structure of trans-3-chlorocycloheptanol.
d) 1, 4-Pentanediol
Interpretation:
To draw the structure of 1, 4-pentanediol.
Concept introduction:
Alcohols are named as derivatives of the parent
To draw:
The structure of 1, 4-pentanediol.
e) 2, 6-Dimethylphenol
Interpretation:
To draw the structure of 2, 6-dimethylphenol.
Concept introduction:
Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituents also, the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.
To draw:
The structure of 2, 6-dimethylphenol.
f) o-(2-hydroxyethyl) phenol.
Interpretation:
To draw the structure of o-(2-hydroxyethyl) phenol.
Concept introduction:
Hydroxybenzenes are named as derivatives of phenol. If the ring contains other substituent also the ring is numbered from the carbon with –OH in such a way that lowest number possible is given to the carbon with the substituent. While writing the name the substituents are arranged in the alphabetical order.
To draw:
The structure of o-(2-hydroxyethyl) phenol.
Trending nowThis is a popular solution!
Chapter 17 Solutions
Organic Chemistry - With Access (Custom)
- Q4: Draw the Lewis structures for the cyanate ion (OCN) and the fulminate ion (CNO). Draw all possible resonance structures for each. Determine which form for each is the major resonance contributor.arrow_forwardIn the following molecule, indicate the hybridization and shape of the indicated atoms. CH3 N CH3 HÖ: H3C CI: ::arrow_forwardQ3: Draw the Lewis structures for nitromethane (CH3NO2) and methyl nitrite (CH3ONO). Draw at least two resonance forms for each. Determine which form for each is the major resonance contributor.arrow_forward
- Q1: Draw a valid Lewis structures for the following molecules. Include appropriate charges and lone pair electrons. If there is more than one Lewis structure available, draw the best structure. NH3 Sulfate Boron tetrahydride. C3H8 (linear isomer) OCN NO3 CH3CN SO2Cl2 CH3OH2*arrow_forwardQ2: Draw all applicable resonance forms for the acetate ion CH3COO. Clearly show all lone pairs, charges, and arrow formalism.arrow_forwardPlease correct answer and don't used hand raitingarrow_forward
- 9. The following reaction, which proceeds via the SN1/E1 mechanisms, gives three alkene products (A, B, C) as well as an ether (D). (a) Show how each product arises mechanistically. (b) For the alkenes, determine the major product and justify your answer. (c) What clues in the reaction as shown suggest that this reaction does not go by the SN2/E2 mechanism route? (CH3)2CH-CH-CH3 CH3OH 1 Bl CH3OH ⑧· (CH3)2 CH-CH=CH2 heat H ⑥③ (CH3)2 C = C = CH3 © СнЗ-С-Снаснз сна (CH 3 ) 2 C H G H CH 3 оснзarrow_forwardPlease Don't used hand raitingarrow_forward7. For the following structure: ← Draw structure as is - NO BI H H Fisher projections (a) Assign R/S configuration at all chiral centers (show all work). Label the chiral centers with an asterisk (*). (b) Draw an enantiomer and diastereomer of the above structure and assign R/S configuration at all chiral centers (again, show all work). (c) On the basis of the R/S system, justify your designation of the structures as being enantiomeric or diastereomeric to the original structure.arrow_forward
- Don't used Ai solutionarrow_forward1. For the following reactions, predict the major product. Show stereochemistry where appropriate. неу b) 7 HBr XV ROOR H₂504 c) N/ H20 H+2 d) ~ Pt c) f. MCPBA -> сна сла (solvent) (1)BH 3-THE (3) Надрон B177 H20 9)arrow_forwardFor the following reactions, predict the major product. Show stereochemistry where approarrow_forward
- ChemistryChemistryISBN:9781305957404Author:Steven S. Zumdahl, Susan A. Zumdahl, Donald J. DeCostePublisher:Cengage LearningChemistryChemistryISBN:9781259911156Author:Raymond Chang Dr., Jason Overby ProfessorPublisher:McGraw-Hill EducationPrinciples of Instrumental AnalysisChemistryISBN:9781305577213Author:Douglas A. Skoog, F. James Holler, Stanley R. CrouchPublisher:Cengage Learning
- Organic ChemistryChemistryISBN:9780078021558Author:Janice Gorzynski Smith Dr.Publisher:McGraw-Hill EducationChemistry: Principles and ReactionsChemistryISBN:9781305079373Author:William L. Masterton, Cecile N. HurleyPublisher:Cengage LearningElementary Principles of Chemical Processes, Bind...ChemistryISBN:9781118431221Author:Richard M. Felder, Ronald W. Rousseau, Lisa G. BullardPublisher:WILEY