GENETIC ANALYSIS: AN INTEG. APP. W/MAS
2nd Edition
ISBN: 9781323142790
Author: Sanders
Publisher: Pearson Custom Publishing
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Textbook Question
Chapter 17, Problem 7P
Using animal models of human diseases can lead to insights into the cellular and genetic bases of the diseases. Duchenne muscular dystrophy (DMD) is the consequence of an X-linked recessive allele.
How would you make a mouse model of DMD?
How would you make a Drosophila model of DMD?
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For the first experiment ever on Drosophila mutations. Answer the following questions.
a. What is the title of the first published paper explained the experiment and what is the name of the Author?
b. What is the first mutation discovered in Drosophila?
c. Explain the changes in the Drosophila yellow mutant (Y)compared to wild type.
provide one example from the Drosophila AP toolkit for "Toolkit genes can be classified according to the phenotypes caused by their mutation. Similar mutant phenotypes often reflect genes that function in a single developmental pathway. Distinct pathways exist for the generation of body axes, for example, and for the formation and identity of fields."
In addition to C. elegans and Drosophila, Zebrafish are also another model organism - and have a spine. We're interested in two phenotypes, a curved spine and a gene that
causes skin tumors to form on the fish's skin. We'd like to know if we could use the curved spine as an indicator if a fish may develop tumors (if the genes are linked). We'll
assume that each of these traits is controlled by a single gene where:
a curved spine is the result of a dominant allele S (and a normal spine is the result of recessive alleless),
⚫ and tumor growth is the result of a recessive allele t (and no tumor growths are a dominant T allele).
A testcross is performed with a fish that is heterozygous for both genes and the resulting progeny are given below.
TtSs x ttss
curved spine & no tumors
curved spine & tumors
normal spine & no tumors
27
45
normal spine & tumors
30
SUN
50
Are these two genes following Mendelian inheritance patterns? Use Chi-Squared analysis to test them. x2 = (0-6)²
1. X2 value:…
Chapter 17 Solutions
GENETIC ANALYSIS: AN INTEG. APP. W/MAS
Ch. 17 - 15.1 What purpose do the bla and lacZ genes serve...Ch. 17 - The human genome is 3109 bp in length. How many...Ch. 17 - 15.3 Ligase catalyzes a reaction between the...Ch. 17 - You have constructed four different libraries: a...Ch. 17 - Using the genomic libraries in Problem 4, you wish...Ch. 17 - The human genome is 3109bp. You wish to design a...Ch. 17 - 15.7 Using animal models of human diseases can...Ch. 17 - 15.8 Compare methods for constructing homologous...Ch. 17 - 15.9 Chimeric genefusion products can be used for...Ch. 17 - 15.10 Why are diseases of the blood simpler...
Ch. 17 - Injection of double-stranded RNA can lead to gene...Ch. 17 - Compare and contrast methods for making transgenic...Ch. 17 - 15.13 It is often desirable to insert cDNAs into a...Ch. 17 - 15.14 A major advance in the s was the development...Ch. 17 - 15.15 The bacteriophage lambda genome can exist in...Ch. 17 - 15.16 The restriction enzymes Xho and Sal cut...Ch. 17 - 15.17 The bacteriophage has a single-stranded DNA...Ch. 17 - 15.20 You have identified a cDNA clone that...Ch. 17 - You have isolated a genomic clone with an EcoR I...Ch. 17 - 15.18 To further analyze the CRABS CLAW gene (see...Ch. 17 - 15.21 You have isolated another cDNA clone of the...Ch. 17 - 15.22 You have identified five genes in S....Ch. 17 - You have generated three transgenic lines of maize...Ch. 17 - 15.24 Bacterial Pseudomonas species often possess...Ch. 17 - 15.25 Two complaints about some transgenic plants...Ch. 17 - 15.26 In Drosophila, lossoffunction Ultrabithorax...Ch. 17 - Prob. 27PCh. 17 - The highlighted sequence shown below is the one...Ch. 17 - The RAS gene encodes a signaling protein that...Ch. 17 - Vitamin E is the name for a set of chemically...Ch. 17 - 15.31 You have cloned a gene for an enzyme that...
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- In Drosophila subobscura, the presence of a recessive gene called grandchildless (gs) causes the offspring of homozygous females, but not those of homozygous males, to be sterile. Can you offer an explanation as to why females and not males are affected by the mutant gene?arrow_forwardCertain genes determine sex, fertility, and viability in Drosophila, and mutations in these genes affect the two sexes differently. Classify the descriptions below based on their occurrence in XY or XX flies. Some descriptions may be used in both categories. The expressed form of Dsx activates maleness genes and represses femaleness genes. XY XX Null mutations in the dsx gene result in an intersex phenotype. Loss-of-function mutations in the tra gene have no effect on phenotype. Sxl is expressed in early embryogenesis from the establishment promoter. Flies that produce Fru-M in brain cells from a transgene perform a mating dance and specifically court females. Loss-of-function mutations in the fru gene result in flies who court both males and females. Sxl regulates splicing of its own RNA to produce a functional protein. The expressed form of Dsx activates femaleness genes and represses maleness genes. Loss-of-function mutations in the Sxl gene have no effect on phenotype. Resetarrow_forwardDuchenne Muscular Dystrophy (DMD) is a disease that manifests in muscle weakness. It exhibits X-linked recessive inheritance pattern. The dystrophin gene is large and can have many different mutations along the DNA. From the following mutations between the gene sequence (DNA template strand) of a healthy male and an affected brother determine if they would affect the production of mRNA or the sequence of the protein. Base your analysis on the position of the mutation in the transcription unit, and the impact of the change on the codons. Mutation 1: Position -6 Healthy individual A Affected brother C Group of answer choices A. Normal mRNA, normal protein B. No mRNA produced (promoter affected) C. Abnormal mRNA, affected protein D. Normal mRNA, affected protein Base your analysis on the position of the mutation in the transcription unit, and the impact of the change on the codons.arrow_forward
- How would you devise a screen to identify recessive mutations in Drosophila that result in embryo lethality? How would you propagate the recessive mutant alleles?arrow_forwardCompare and contrast the experimental advantages and disadvantages of Drosophila, C. elegans, mammals, and Arabidopsis.arrow_forwardIn Drosophila sex determination (Check all that apply.) A) XY individuals transcribe the Sxl gene early but not late. B XX individuals carry the Sxl gene, XY individuals do not. XX individuals transcribe the Sxl gene, XY individuals do not. XX individuals express the Sxl protein, XY individuals do not. E) The Sxl transcript (Pre-MRNA) is spliced differently in XX compared to XY individuals.arrow_forward
- Researchers have exploited Minute mutations in orderto study the phenotypes associated with recessive lethal mutations (l−) that decrease the rate of cell divisionand thus make only very tiny homozygous mutant clones that are difficult to analyze. Many differentstrains of Drosophila carry dominant loss-of-functionMinute (M) mutations in a variety of genes encodingribosomal protein subunits. The M genes are haploinsufficient; flies with only one wild-type M+ gene copyhave a slower pace of cell division, and thus prolongeddevelopment and subtle morphological abnormalities.To circumvent the tiny clone problem, researchersgenerate GFP-marked homozygous l−/ l− clones thatare also M+/ M+, in flies that are l−/ l+ and M−/ M+.The loss of the Minute mutation only in cells withinthe clone gives the l−/ l− cells a growth advantageover their neighbors, enabling the mutant clone togrow large enough to study. Diagram chromosomesthat could be used to generate such clonesarrow_forwardFollowing a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. Which is the genotype of the rhythmic flies resulting from the testcross? Select only one answer 1. C/C d/d 2. C/c D/d 3. C/c d/d 4. c/c…arrow_forwardFollowing a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. Using the number of flies expected for the Parental and the Recombinant genotypes and the formula that defines recombination frequency, what is the recombination…arrow_forward
- Following a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. Comparing the number of flies expected for the Parental and the Recombinant genotypes, what can be concluded about the C and D loci? Select only one answer. 1. The…arrow_forwardFollowing a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. What is the genotype of the F1 (progeny of Females 3 x Males 4). Select only one answer. 1. C/c D/d 2. C/C d/d 3. C/C D/D 4. c/c D/d…arrow_forwardFollowing a mutagenesis experiment to identify novel genes affecting the circadian clock in Drosophila melanogaster you discover several mutants. You start considering two of those mutants that you call c and d. The two homozygous c/c and d/d are arrhythmic (arrhythmic is the definition of their phenotype), whereas the two heterozygous C/c and D/d are rhythmic (rhythmic is the definition of their phenotype) with a 24h period. You make two true-breeding stocks: stock 3 homozygous for c and stock 4 homozygous for d. You cross them in both directions and in both cases you observe complementation with no difference between males and females. Then you take the progeny of one cross, for instance the F1 of Females 3 x Males 4, and you perform a Testcross. Out of 1000 flies resulting from the Testcross only 125 are rhythmic. What is the genotype of Males 4? Select only one answer. 01. C/C D/D O 2. C/C D/d O3. C/C d/d O 4. C/C D/D O 5. c/c D/d O 6. C/cd/d 07. c/c D/D O 8. C/C D/d O 9. c/cd/d Karrow_forward
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