Chapter 17, Problem 60P

Interpretation Introduction

(a)

Interpretation:

The structure of amide formed by the reaction of propylamine ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{}{\text{NH}}_{\text{2}}\text{}$ with propanoic acid ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}\text{COOH}\text{}$ should be determined.

Concept Introduction:

Functional groups are the groups of atoms or atoms which are bonded with parent carbon chain in the organic molecule and are responsible for the physical and chemical properties of the compound. In organic chemistry, there are different functional groups such as carboxylic acid, alcohol, ester, or amide.

Amines are the organic compounds with general chemical formula of R-NH₂ or R-NH-R whereas carboxylic acids are the organic molecules with R-COOH as general chemical formula.

Answer to Problem 60P

The propanoic acid ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}\text{COOH}\text{}$ reacts with propylamine ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{}{\text{NH}}_{\text{2}}\text{}$ to form ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CONHCH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{}{\text{CH}}_{\text{3}}\text{}$ (N-propylpropanamide).

Explanation of Solution

The reaction of carboxylic acid with ammonia or amines forms amide molecules. It involves the formation of water molecule. In this reaction the amine nitrogen atom react with carbonyl carbon atom of carboxylic acid to form amide.

In the reaction of ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{}{\text{NH}}_{\text{2}}\text{}$ with ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}\text{COOH}\text{}$ , the −COOH and −NH₂ group take part to form water and amide molecule as given below;

  $\begin{array}{l}{\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{COOH + CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}\text{}{\text{NH}}_{\text{2}}\text{}\stackrel{}{\to }{\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{CONHCH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{3}}\text{}{\text{+H}}_{\text{2}}\text{O}\\ \text{Propanoic acid + Propylamine }\stackrel{}{\to }\text{ N-propylpropanamide + water}\end{array}$

Interpretation Introduction

(b)

Interpretation:

The structure of amide formed by the reaction of ${\text{CH}}_{\text{3}}{{\text{(CH}}_{\text{2}}\text{)}}_{\text{10}}\text{COOH}$ with ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{NH}}_{\text{2}}$ should be determined.

Concept Introduction:

Functional groups are the groups of atoms or atoms which are bonded with parent carbon chain in the organic molecule and are responsible for the physical and chemical properties of the compound. In organic chemistry, there are different functional groups such as carboxylic acid, alcohol, ester, or amide.

Amines are the organic compounds with general chemical formula of R-NH₂ or R-NH-R whereas carboxylic acids are the organic molecules with R-COOH as general chemical formula.

Answer to Problem 60P

The Dodecanoic acid ${\text{CH}}_{\text{3}}{{\text{(CH}}_{\text{2}}\text{)}}_{\text{10}}\text{COOH}$ reacts with ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{NH}}_{\text{2}}$ to form ${\text{CH}}_{\text{3}}{{\text{(CH}}_{\text{2}}\text{)}}_{\text{10}}{\text{COHNCH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{3}}$ (N-propyldodecanamide).

Explanation of Solution

The reaction of carboxylic acid with ammonia or amines forms amide molecules. It involves the formation of water molecule. In this reaction the amine nitrogen atom react with carbonyl carbon atom of carboxylic acid to form amide.

In the reaction of ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{NH}}_{\text{2}}$ with ${\text{CH}}_{\text{3}}{{\text{(CH}}_{\text{2}}\text{)}}_{\text{10}}\text{COOH}$ , the −COOH and −NH₂ group take part to form water and amide molecule as given below;

  $\begin{array}{l}{\text{CH}}_{\text{3}}{{\text{(CH}}_{\text{2}}}_{\text{)}}{\text{COOH + CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{NH}}_{\text{2}}\stackrel{}{\to }{\text{CH}}_{\text{3}}{{\text{(CH}}_{\text{2}}}_{\text{)}}{\text{CONHCH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{3}}{\text{+H}}_{\text{2}}\text{O}\\ \text{Dodecanoic acid + propylamine }\stackrel{}{\to }\text{ N-propyldodecanamide + water}\end{array}$

Interpretation Introduction

(c)

Interpretation:

The structure of amide formed by the reaction of $\text{HCOOH}$ with ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{NH}}_{\text{2}}$ should be determined.

Concept Introduction:

Functional groups are the groups of atoms or atoms which are bonded with parent carbon chain in the organic molecule and are responsible for the physical and chemical properties of the compound. In organic chemistry, there are different functional groups such as carboxylic acid, alcohol, ester, or amide.

Amines are the organic compounds with general chemical formula of R-NH₂ or R-NH-R whereas carboxylic acids are the organic molecules with R-COOH as general chemical formula.

Answer to Problem 60P

The formic acid $\text{HCOOH}$ reacts with ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{NH}}_{\text{2}}$ to form N-propylmethanamide.

Explanation of Solution

The reaction of carboxylic acid with ammonia or amines forms amide molecules. It involves the formation of water molecule. In this reaction the amine nitrogen atom react with carbonyl carbon atom of carboxylic acid to form amide.

In the reaction of ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{NH}}_{\text{2}}$ with $\text{HCOOH}$ , the −COOH and −NH₂ group take part to form water and amide molecule as given below;

  $\begin{array}{l}{\text{HCOOH + CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{NH}}_{\text{2}}\stackrel{}{\to }{\text{HCONCH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{3}}{\text{+ H}}_{\text{2}}\text{O}\\ \text{Formic acid + Propylamine }\stackrel{}{\to }\text{ N-propylmethanamide + water}\end{array}$

Interpretation Introduction

(d)

Interpretation:

The structure of amide formed by the reaction of p-methoxybenzoic acid with ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{NH}}_{\text{2}}$ should be determined.

Concept Introduction:

Functional groups are the groups of atoms or atoms which are bonded with parent carbon chain in the organic molecule and are responsible for the physical and chemical properties of the compound. In organic chemistry, there are different functional groups such as carboxylic acid, alcohol, ester, or amide.

Amines are the organic compounds with general chemical formula of R-NH₂ or R-NH-R whereas carboxylic acids are the organic molecules with R-COOH as general chemical formula.

Answer to Problem 60P

The p-methoxybenzoic acid reacts with ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{NH}}_{\text{2}}$ to form N-propyl p-methoxybenzamide.

Explanation of Solution

The reaction of carboxylic acid with ammonia or amines forms amide molecules. It involves the formation of water molecule. In this reaction the amine nitrogen atom react with carbonyl carbon atom of carboxylic acid to form amide.

In the reaction of ${\text{CH}}_{\text{3}}{\text{CH}}_{\text{2}}{\text{CH}}_{\text{2}}{\text{NH}}_{\text{2}}$ with p-methoxybenzoic acid, the −COOH and −NH₂ group take part to form water and amide molecule as given below;