Student's Study Guide and Solutions Manual for Organic Chemistry

8th Edition

ISBN: 9780134066585

Author: Paula Yurkanis Bruice

Publisher: PEARSON

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Textbook Question

Chapter 17, Problem 58P

In the presence of excess base and excess halogen, a methyl ketone is converted to a carboxylate ion. The reaction is known as the haloform reaction because one of the products is haloform (chloroform, bromoform, or iodoform). Before spectroscopy became a routine analytical tool, the haloform reaction served as a test for methyl ketones: the formation of iodoform, a bright yellow compound, signaled that a methyl ketone was present. Why do only methyl ketones form a haloform?

Chapter 17, Problem 58P, In the presence of excess base and excess halogen, a methyl ketone is converted to a carboxylate

Definition Definition Organic compounds that have a carbonyl group, C = O, as their functional group. The carbonyl group in ketones is placed somewhere in the middle of the molecular structure, which means, the C=O is attached to two alkyl groups or benzene rings. Just like all other homologous series, the naming of ketones is done using a common suffix “-one”. The general molecular formula is C n H 2n O. Functional group of a ketone

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Chapter 17, Problem 57P

Chapter 17, Problem 59P

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Chapter 17 Solutions

Student's Study Guide and Solutions Manual for Organic Chemistry

Ch. 17.1 - Prob. 1P Ch. 17.1 - Prob. 2P Ch. 17.1 - Prob. 3P Ch. 17.1 - Prob. 4P Ch. 17.1 - Rank the compounds in each of the following groups...Ch. 17.2 - Explain why 92% of 2,4-pemtanedione exists as the...Ch. 17.3 - Draw the enol tautomers for each of the following...Ch. 17.3 - Prob. 8P Ch. 17.4 - Prob. 9P Ch. 17.4 - Prob. 10P

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