Concept explainers
(a)
Interpretation: The structure of given compounds has to be drawn.
ethylacetoacetate
Concept introduction: The
Carboxylate ion with a carbonyl group at the 3-position loses
(a)
Answer to Problem 48P
The structure of ethyl acetoacetae is,
Explanation of Solution
The name given compound ethyl acetoacetate ends with ate. This means the given compound must contain an ester group. The name of compound starts with ethyl group, this means ethyl group is attached to the oxygen of an ester group. The acetone group is attached with the carbonyl carbon of an ester group. The structure of ethyl acetoacetae is,
(b)
Interpretation: The structure of given compounds has to be drawn.
α-methylmalonicacid
Concept introduction: The
Carboxylate ion with a carbonyl group at the 3-position loses
(b)
Answer to Problem 48P
The structure of α-methylmalonic acid is,
Explanation of Solution
The structure of malonic acid is two
(c)
Interpretation: The structure of given compounds has to be drawn.
β-keto ester
Concept introduction: The
Carboxylate ion with a carbonyl group at the 3-position loses
(c)
Answer to Problem 48P
The structure of β-keto ester is,
Explanation of Solution
The given compound β-keto ester contains a keto group and an ester group. The structure of β-keto ester is,
(d)
Interpretation: The structure of given compounds has to be drawn.
The carboxylic acid obtained from malonic ester synthesis when the
Concept introduction: The
Carboxylate ion with a carbonyl group at the 3-position loses
(d)
Answer to Problem 48P
The structure of enol form of cyclopentanone is,
Explanation of Solution
The compound cyclopentanone contain a keto group. After the keto enol tautomerism the keto compound converted into an alcohol and a double bond. The structure of enol form of cyclopentanone is,
(e)
Interpretation: The structure of given compounds has to be drawn.:
The structure of enol form of cyclopentanone
Concept introduction: The
Carboxylate ion with a carbonyl group at the 3-position loses
(e)
Answer to Problem 48P
The structure of the carboxylic acid obtained from malonic ester synthesis by using propyl bromide is,
Explanation of Solution
The proton removed from the alpha carbon of malonic ester by the base. Then, there is a nucleophilic substitution reaction takes place between the propyl bromide and carbanion of malonic ester. The third step is acidic hydrolysis of an ester to form carboxylic acid. The fourth step is decarboxylation of the compound to form the desired product. The reaction and structure of given compound is,
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Chapter 17 Solutions
Student's Study Guide and Solutions Manual for Organic Chemistry
- 14.50 Explain why methyl vinyl ether (CH2=CHOCH 3) is not a reactive dienophile in the Diels-Alder reaction.arrow_forwardShow work with explanation needed. don't give Ai generated solutionarrow_forward14.49 From what you have learned about the reaction of conjugated dienes in Section 14.10, predict the products of each of the following electrophilic additions. a. H₂O H2SO4 Br2 b. H₂Oarrow_forward
- 14.46 Draw a stepwise mechanism for the following reaction. HBr ROOR Br + Brarrow_forwardShow work..don't give Ai generated solution....arrow_forward14.47 Addition of HCI to alkene X forms two alkyl halides Y and Z. exocyclic C=C X HCI CI Y + CI Z a. Label Y and Z as a 1,2-addition product or a 1,4-addition product. b.Label Y and Z as the kinetic or thermodynamic product and explain why. c. Explain why addition of HCI occurs at the indicated C=C (called an exocyclic double bond), rather than the other C=C (called an endocyclic double bond).arrow_forward
- 14.44 Ignoring stereoisomers, draw all products that form by addition of HBr to (E)-hexa-1,3,5-triene.arrow_forwardInclude stereochemistry Leven though the solutions manual does 14.43 Draw the products formed when each compound is treated with one not) equivalent of HBr. a. b. C.arrow_forward14.41 Label each pair of compounds as stereoisomers, conformations, or constitutional isomers: (a) A and B; (b) A and C; (c) A and D; (d) C and D. A B C Darrow_forward
- Steps and detailed explanation for work. Thanks!arrow_forward14.39 Draw the structure of each compound. a. (Z)-penta-1,3-diene in the s-trans conformation b. (2E,4Z)-1-bromo-3-methylhexa-2,4-diene c. (2E,4E,6E)-octa-2,4,6-triene d. (2E,4E)-3-methylhexa-2,4-diene in the s-cis conformationarrow_forwardPLEASE ANSWER ALL PARTS!!arrow_forward
- Chemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning