The value of Δ G ° and K p at the temperature of 298 K is to be calculated. The reaction is spontaneous or not is to be predicted. The value of Δ G ° is to be calculated at the temperature of 2000 K . The reaction become spontaneous with increasing temperature or not is to be predicted. Concept introduction: The reaction will be spontaneous if the value of Gibbs free energy is negative and the reaction will be non-spontaneous if the value of Gibbs fee energy is positive. To determine: The value of Δ G ° and K p at the temperature of 298 K and whether the reaction is spontaneous or not. The value of Δ G ° at the temperature of 2000 K and whether the reaction become spontaneous with increasing temperature or not.

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Chapter 17, Problem 51E

Interpretation Introduction

Interpretation:

The value of ΔG° and Kp at the temperature of 298 K is to be calculated. The reaction is spontaneous or not is to be predicted.
The value of ΔG° is to be calculated at the temperature of 2000 K . The reaction become spontaneous with increasing temperature or not is to be predicted.

Concept introduction:The reaction will be spontaneous if the value of Gibbs free energy is negative and the reaction will be non-spontaneous if the value of Gibbs fee energy is positive.
To determine:The value of ΔG° and Kp at the temperature of 298 K and whether the reaction is spontaneous or not.
The value of ΔG° at the temperature of 2000 K and whether the reaction become spontaneous with increasing temperature or not.

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