Chapter 17, Problem 46E

Interpretation Introduction

Interpretation:

The value of $\Delta G_{\text{rxn}}$ for the given reaction at standard conditions, at equilibrium and at given partial pressures is to be calculated.

Concept introduction: The energy available for doing a useful work is known as Gibbs free energy. The free energy change of a reaction under nonstandard conditions is expressed by the relation,

$\Delta G=\Delta G^{\text{ο}}+\text{R}T\ln Q$

At equilibrium, the value of $\text{R}T\ln Q$ is always equal in magnitude but opposite in sign to the value of $\Delta G^{\text{ο}}$ . Therefore, the change in Gibbs free energy is equal to zero.

To determine:The value of $\Delta G_{\text{rxn}}$ for the given reaction at standard conditions, at equilibrium and at given partial pressures.