Chapter 17, Problem 39E

Interpretation Introduction

Interpretation:

The standard free energy and free energy at nonstandard pressure conditions is to be calculated. Also, the spontaneity of the reaction at the room temperature is to be explained.

Concept introduction: The standard free energy, $\Delta G°$ , of the reaction is calculated by the formula,

$\text{Standard}\text{free}\text{energy}\text{of}\text{the}\text{reaction}=\left(\begin{array}{l}\text{Standard}\text{free}\text{energy}\text{of}\text{formation}\text{of}\text{product}\\ -\text{Standard}\text{free}\text{energy}\text{of}\text{formation}\text{of}\text{reactant}\end{array}\right)$

The free energy, $\Delta G$ , of the reaction is calculated by the formula,

$\Delta G=\Delta G°+\text{Absolute}\text{temperature}\times \text{Gas}\text{constant}\times \ln \frac{\text{Partial}\text{pressure}\text{of}\text{product}}{\text{Partial}\text{pressure}\text{of}\text{reactant}}$

To determine:The standard free energy, free energy at nonstandard pressure conditions and the explanation for the spontaneity of the reaction at the room temperature.