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- In what way(s) does the carbon-group-bonded-to metal of an organometallic compound behave? Select one: ⒸA Oxidizing agent O O B. Acid (proton donor) C. Base (proton acceptor) D. Carbon nucleophile E. Carbon electrophile Both C and D Which of the following is NOT an organometallic compound?9.) Explain why NaNH2 favors the enolate ion in the following reaction, but NaOH favors an equilibrium. (B: represents the base – either NANH, or NaOH). You'll need to consider acid/base strength (pKa values). B: + BH enolate ion6. Provide the structure for the major product in the following reactions. b. P f. OH g. Lia * Oia ملی CI 1. SOCI₂, pyr. 2. to Br 2 1. LIAIH4 (xs) 2. H₂O 1. LIAI(OR) 3H 2. H₂O 2. NH₂ Et₂CuLi 1. EtMgBr (xs) 2. H₂O 1. Mg 2. CO₂ 3. H* 4. SOCI₂, pyr 1. [H], NaBH3CN, EtNH₂ CI pyridine
- Which option is correct and which option is incorrect, Give all options solution. Don't use AI.O E. .4. Draw the organic products formed in each of the following reactions. il b. C. 1₂ (excess) -OH CE .CO₂Et [1] LDA CHz(CO,Et)2 [2] CH₂CH₂Br [3] H₂O+, A [1] NaOEt [2] CH₂CH₂Br [1] NaOEt [2] CHSCH₂Cl (3) H₂O*, A d. 'OEI [1] NaOE1 [2] CH₂CH₂CH₂CH₂Br [3] H₂O*, A [1] LDA [2] CH₂CH₂Br
- Which option is correct and which option is incorrect, Give all options solution. Don't use AI. Give tipping format solution.Draw the major organic product for each of the hydroboration‑oxidation reactions. Disregard stereochemistry.6. Provide reagents and intermediates in the indicated boxes to complete the reaction scheme. + H NaBH3CN, HCI (two steps, no acidic hydrolysis, from one product) 016H (w/o heat) 1. MeLi (xs) 2. HCI, H₂O NH₂ 1. Saponification 2. A 0 1. MeMgBr (xs) 2. HCI, H₂O 018 Me NH₂ 1. Dibal H, 2. H3O+ POCk3, pyr or + 1. LIAIH(O'Bu)3 (XS) 2. acidic workup
- 5. Predict the major product, which will be formed under the depicted reaction conditions. Be sure to indicate stereocher clearly when relevant. d. HN, pyr е. Nao (cat.) OEt НО f. HCI, H20 HCI, H20 Ph heat HCI, NH3 H. then NaCN1. Reaction of excess methyllithium with ethyl acetate (CH3CO2C2H5) produces, after acid work-up, ___. 2. Reaction of excess ethyl magnesium bromide with ethyl benzoate (C6H5CO2C2H5) produces, after acid work-up, ___. 3. Reaction of excess ethyl magnesium iodide with ethyl acetate (CH3CO2C2H5) produces, after acid work-up, ___.Organic Chemistry 1. Can you please explain all three answer choices ? Why is it ! and III, and not II ? Thank you