PKG ORGANIC CHEMISTRY
5th Edition
ISBN: 9781259963667
Author: SMITH
Publisher: MCG
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Chapter 17, Problem 17.69P
Although benzene itself absorbs at
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An unknown compound has a molecular formula of C,H,O. Its IR spectrum shows prominent absorptions at 2980, 2960, and 1718 cm . It exhibits the
following signals in its H NMR spectrum (ppm): 1.06 (triplet, 3H), 2.12 (singlet, 3H), 2.45 (quartet, 2H); and the following signals in its ¹3C NMR spectrum (
ppm): 7.6, 29.5, 36.8, 208.8.
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Compound A has molecular formula C7H7X. Its 1H-NMR spectrum shows a singlet at 2.26 ppm and two doublets, one at 6.95 ppm and one at 7.28 ppm. The singlet has an integral of three and the doublets each have an integral of two. Its 13C-NMR shows five signals. The mass spectrum of A shows a peak at m/z = 170 and another peak at m/z = 172; the relative height of the two peaks is 1:1 respectively.
- Identify what atom X is, explaining your reasoning
- Identify Compound A, explaining your reasoning
Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The 1H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively.
- Identify compound B, explaining your reasoning
Compound B is treated with sodium ethoxide to generate compound C. The 1H-NMR spectrum of C shows…
Thymol (molecular formula C10H14O) is the major component of the oil ofthyme. Thymol shows IR absorptions at 3500–3200, 3150–2850, 1621, and1585 cm−1. The 1H NMR spectrum of thymol is given below. Propose apossible structure for thymol.
Chapter 17 Solutions
PKG ORGANIC CHEMISTRY
Ch. 17 - Prob. 17.1PCh. 17 - Problem 17.2 What orbitals are used to form the...Ch. 17 - Problem-17.3. Give the IUPAC name for each...Ch. 17 - Prob. 17.4PCh. 17 - Problem-17.5 What is the structure of propofol,...Ch. 17 - Problem 17.6 What is the structure of a compound...Ch. 17 - Problem 17.7 How many NMR signals does each...Ch. 17 - Prob. 17.8PCh. 17 - Prob. 17.9PCh. 17 - Prob. 17.10P
Ch. 17 - Prob. 17.11PCh. 17 - Prob. 17.12PCh. 17 - Prob. 17.13PCh. 17 - Problem 17.14 Januvia, the trade name for...Ch. 17 - Prob. 17.15PCh. 17 - Problem 17.16 Rank the following compounds in...Ch. 17 - Problem 17.17 Draw the seven resonance structures...Ch. 17 - Prob. 17.18PCh. 17 - Prob. 17.19PCh. 17 - Prob. 17.20PCh. 17 - Prob. 17.21PCh. 17 - Problem 17.22 How many NMR signals does ...Ch. 17 - 17.23 Name each compound and state how many lines...Ch. 17 - Prob. 17.24PCh. 17 - Prob. 17.25PCh. 17 - Prob. 17.26PCh. 17 - 17.27 Give the IUPAC name for each compounds.
a....Ch. 17 - 17.28 Draw a structure corresponding to each...Ch. 17 - 17.29 a. Draw the 14 constitutional isomers of...Ch. 17 - Prob. 17.30PCh. 17 - Prob. 17.31PCh. 17 - Prob. 17.32PCh. 17 - 17.33 Label each compound as aromatic,...Ch. 17 - Prob. 17.34PCh. 17 - 17.35 Pentalene, azulene, and heptalene are...Ch. 17 - 17.36 The purine heterocycle occurs commonly in...Ch. 17 - Prob. 17.37PCh. 17 - 17.38
How many electrons does C contain?
How...Ch. 17 - Prob. 17.39PCh. 17 - 17.40 Explain the observed rate of reactivity of...Ch. 17 - 17.41 Draw a stepwise mechanism for the following...Ch. 17 - Prob. 17.42PCh. 17 - 17.43 Draw additional resonance structures for...Ch. 17 - Prob. 17.44PCh. 17 - Prob. 17.45PCh. 17 - 17.46 Which compound in each pair is the stronger...Ch. 17 - 17.47 Treatment of indene with forms its...Ch. 17 - Prob. 17.48PCh. 17 - 17.49 Draw the conjugate bases of pyrrole and...Ch. 17 - 17.50 a. Explain why protonation of pyrrole occurs...Ch. 17 - Prob. 17.51PCh. 17 - Prob. 17.52PCh. 17 - 17.53 How many signals does each compound...Ch. 17 - 17.54 Which of the diethylbenzene isomers (ortho,...Ch. 17 - 17.55 Propose a structure consistent with each...Ch. 17 - 17.56 Propose a structure consistent with each...Ch. 17 - 17.57 Thymol (molecular formula ) is the major...Ch. 17 - 17.58 You have a sample of a compound of molecular...Ch. 17 - 17.59 Explain why tetrahydrofuran has a higher...Ch. 17 - 17.60 Rizatriptan (trade name Maxalt) is a...Ch. 17 - 17.61 Zolpidem (trade name Ambien) promotes the...Ch. 17 - 17.62 Answer the following questions about...Ch. 17 - 17.63 Stanozolol is an anabolic steroid that...Ch. 17 - Prob. 17.64PCh. 17 - 17.65 Use the observed data to decide whether C...Ch. 17 - Prob. 17.66PCh. 17 - Prob. 17.67PCh. 17 - Prob. 17.68PCh. 17 - 17.69 Although benzene itself absorbs at in its ...
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- A hydrocarbon, compound B, has molecular formula C6H6, and gave an NMR spectrum with two signals: delta 6.55 pm and delta 3.84 pm with peak ratio of 2:1. When warmed in pyridine for three hr, compound B quantitatively converts to benzene. Mild hydrogenation of B yielded another compound C with mass spectrum of m/z 82. Infrared spectrum showed no double bonds; NMR spectrum showed one broad peak at delta 2.34 ppm. With this information, address the following questions. a) How many rings are in compound C? b) How many rings are probably in B? How many double bonds are in B? c) Can you suggest a structure for compounds B and C? d) In the NMR spectrum of B, the up-field signal was a quintet, and the down field signal was a triplet. How must you account for these splitting patterns?arrow_forwardCompound A has molecular formula C7H7X. Its ¹H-NMR spectrum shows a singlet at 2.26 ppm and two doublets, one at 6.95 ppm and one at 7.28 ppm. The singlet has an integral of three and the doublets each have an integral of two. Its 13C- NMR shows five signals. The mass spectrum of A shows a peak at m/z 170 and another peak at m/z = 172; the relative height of the two peaks is 1:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoning Compound A is treated with a mixture of nitric and sulfuric acids to generate Compound B. The ¹H-NMR spectrum of B shows two singlets, one at 2.52 pm and one at 8.13 ppm. The 13C-NMR spectrum of B shows five signals. The mass spectrum of B shows a peak at m/z = 260 and another peak at m/z = 262; the relative height of the two peaks is 1:1 respectively. - Identify compound B, explaining your reasoning Compound B is treated with sodium ethoxide to generate compound C. The ¹H-NMR spectrum of C shows…arrow_forwardCompound A has molecular formula C7H7X. Its 1H-NMR spectrum shows a singlet at 2.25 ppm and two doublets, one at 7.28 ppm and one at 7.39 ppm. The singlet has an integral of three and the doublets each have an integral of two. The mass spectrum of A shows a peak at m/z = 126 and another peak at m/z = 128; the relative height of the two peaks is 3:1 respectively. - Identify what atom X is, explaining your reasoning - Identify Compound A, explaining your reasoningarrow_forward
- Identify products A and B from the given 1H NMR data. Treatment of CH2=CHCOCH3 with one equivalent of HCl forms compound A. A exhibits the following absorptions in its 1H NMR spectrum: 2.2 (singlet, 3H), 3.05 (triplet, 2 H), and 3.6 (triplet, 2 H) ppm. What is the structure of A?arrow_forwardKetones undergo a reduction when treated with sodium borohydride, NaBH4. What is the structure of the compound produced by reaction of 2-butanone with NaBH4 if it has an IR absorption at 3400 cm-1 and M+=74 in the mass spectrum?arrow_forwardAn aromatic hydrocarbon with a molecular formula of C13H20 has an 1H NMR spectrum with a signal at ~7 ppm that integrates to 5H. It also has twosinglets; one of the singlets has 1.5 times the area of the second. What is the structure of the aromatic hydrocarbon?arrow_forward
- The ¹H NMR spectrum of a compound with the molecular formula C7H₁5Cl exhibits signals with relative integration 9:3:2:1. Propose a structure for this compound. 4-chloroheptane 3-chloro-2,2-dimethylpentane 3-chloro-2,4-dimethylpentane O2-chloro-2,3,3-trimethylbutanearrow_forwardPhenacetin is an analgesic compound having molecular formula C10H13NO2. Once a common component in over-the-counter pain relievers such as APC (aspirin, phenacetin, caffeine), phenacetin is no longer used because of its liver toxicity. Deduce the structure of phenacetin from its 1H NMR and IR spectra.arrow_forwardA and B are isomeric dicarbonyl compounds of the molecular formula C5H&O2. The 'H NMR spectrum of A contains a singlet at 2.05 ppm and another singlet at 5.40 ppm. The 'H NMR spectrum of B contains three signals: a singlet at 2.3 ppm, a triplet at 1.10 ppm and a quartet at 2.70 ppm. Suggest structures for A and B and draw them in their respective boxes below. 1st attemptarrow_forward
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