K p and K c has to be compared when more moles of products and less moles of reactants are present in the system. Concept Introduction: The equilibrium constant in terms of concentration K c and in terms of partial pressure K p are related by an equation given below. K p = K c ( RT ) Δn gas Where, K p = equilibrium constant in terms of pressure K c = equilibrium constant in terms of concentration Δn gas = number of moles gaseous products - number of moles gaseous reactants R = universal gas constant When number of moles of gaseous product equals to number of moles of gaseous reactants then Δn gas will become zero. Hence, K p will be equal to K c . All other cases when number of gas molecules of reactant and product are different K p and K c will be having different values.
K p and K c has to be compared when more moles of products and less moles of reactants are present in the system. Concept Introduction: The equilibrium constant in terms of concentration K c and in terms of partial pressure K p are related by an equation given below. K p = K c ( RT ) Δn gas Where, K p = equilibrium constant in terms of pressure K c = equilibrium constant in terms of concentration Δn gas = number of moles gaseous products - number of moles gaseous reactants R = universal gas constant When number of moles of gaseous product equals to number of moles of gaseous reactants then Δn gas will become zero. Hence, K p will be equal to K c . All other cases when number of gas molecules of reactant and product are different K p and K c will be having different values.
Kp and Kc has to be compared when more moles of products and less moles of reactants are present in the system.
Concept Introduction:
The equilibrium constant in terms of concentration Kc and in terms of partial pressure Kp are related by an equation given below.
Kp = Kc(RT)Δngas
Where,
Kp= equilibrium constant in terms of pressureKc= equilibrium constant in terms of concentrationΔngas= number of moles gaseous products - number of moles gaseous reactantsR = universal gas constant
When number of moles of gaseous product equals to number of moles of gaseous reactants then Δngas will become zero. Hence, Kp will be equal to Kc.
All other cases when number of gas molecules of reactant and product are different Kp and Kc will be having different values.
(b)
Interpretation Introduction
Interpretation:
Relative size of Kp and Kc for any gaseous equilibrium has to be compared.
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.