Bundle: Principles Of Geotechnical Engineering, Loose-leaf Version, 9th + Mindtap Engineering, 2 Terms (12 Months) Printed Access Card
Bundle: Principles Of Geotechnical Engineering, Loose-leaf Version, 9th + Mindtap Engineering, 2 Terms (12 Months) Printed Access Card
9th Edition
ISBN: 9781337583817
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
Question
Book Icon
Chapter 17, Problem 17.1P
To determine

Find the area ratio for each case and appropriate sample for the given soil characterization tests.

Expert Solution & Answer
Check Mark

Answer to Problem 17.1P

The area ratio for tube 1 is 5.06%_.

The area ratio for tube 2 is 4.47%_.

The area ratio for tube 3 is 4.98%_.

Explanation of Solution

Given information:

The outside diameter (Do) for sample 1 is 50.8mm.

The outside diameter (Do) for sample 2 is 76.2mm.

The outside diameter (Do) for sample 3 is 127mm.

The wall thickness (t) for sample 1 is 1.24mm.

The wall thickness (t) for sample 2 is 1.65mm.

The wall thickness (t) for sample 3 is 3.05mm.

Calculation:

Calculate the inside diameter (Di) for tube 1 using the relation as follows:

(Di)=Dot (1)

Substitute 50.8mm for (Do) and 1.24mm for t in Equation (1).

(Di)=50.81.24=49.56mm

Find the area ratio for (Ar) tube 1 using the Equation as follows:

Ar(%)=Do2Di2Di2×100 (2)

Here, Di inside diameter of sample 1.

Substitute 50.8mm for Do and 49.56mm for Di in Equation (2).

Ar(%)=50.8249.56249.562×100=2,580.642,456.192,456.19×100=124.442,456.19×100=5.06%10%

Thus, the area ratio for tube 1 is 5.06%_.

Calculate the inside diameter (Di) for tube 2 using the relation as follows:

Substitute 76.2mm for (Do) and 1.65mm for t in Equation (1).

(Di)=76.21.65=74.55mm

Find the area ratio for (Ar) tube 2 using the Equation as follows:

Substitute 76.2mm for Do and 74.55mm for Di in Equation (2).

Ar(%)=76.2274.55274.552×100=5,806.445,557.75,557.7×100=248.745,557.7×100=4.47%10%

Thus, the area ratio for tube 2 is 4.47%_.

Calculate the inside diameter (Di) for tube 3 using the relation as follows:

Substitute 127mm for (Do) and 3.05mm for t in Equation (1).

(Di)=1273.05=123.95mm

Find the area ratio for (Ar) tube 3 using the Equation as follows:

Substitute 127mm for Do and 123.95mm for Di in Equation (2).

Ar(%)=1272123.952123.952×100=16,12915,363.6015,363.60×100=4.98%10%

Thus, the area ratio for tube 3 is 4.98%_.

A soil sample usually can be considered undisturbed if the area ratio is less than or equal to 10%.

  • All the given three samples are considered as undisturbed sample, hence, it is suitable for consolidation and unconfined compression test.
  • The Grain size distribution, atterberg limits are conducted only when the soil on remolded or disturbed soil, hence, sample disturbance is not a factor.

Thus, the all three samples are appropriate for all tests.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
Example 5.2: Design Example of a Square Foundation for a Colum Figure A.3a shows a square column foundation with the followin conditions: Live load=L=675 kN Dead load D= 1125 kN Allowable gross soil-bearing capacity 145 kN/m² Column size-0.5 m x 0.5 m -20.68 MN/m² 1,413.7 MN/m² Let it be required to design the column foundation. 1.25m-D L-675 AN D-1125 AN (a) Column section- 05 m x 0.5m
Example 5.3: Design Example of a Rectangular Foundation for Column This section describes the design of a rectangular foundation to support a column having dimensions of 0.4 m x 0.4 m in cross section. Other details are as follows: Dead load D= 290 kN Live load L= 110 kN Depth from the ground surface to the top of the foundation = 1.2 m Allowable gross soil-bearing capacity = 120 kN/m² Maximum width of foundation = B = 1.5 m f, = 413.7 MN/m² f=20.68 MN/m² Unit weight of soil = y = 17.27 kN/m³ Unit weight of concrete = y₁ = 22.97 kN/m³ General Considerations For this design, let us assume a foundation thickness of 0.45 m (Figure A.4a). The weight of foundation/m² = 0.45 y = (0.45) (22.97) = 10.34 kN/m², and the weight of soil above the foundation/m² = (1.2)y = (1.2) (17.27) = 20.72 kN/m² Hence, the net allowable soil- bearing capacity Iqata] =120-10.34-20.72 = 88.94 kN/m² The required area of the foundation = (D+L)/4(all) = (290 + 110)/88.94 = 4.5 m². Hence, the length of the foundation…
Problem 1 You are in the process of designing a water supply system for the whole lligan City, and the design life of your system is to end in the year 2070. The population in the town has been measured every 10 years since 1980 by the Philippine Statistics Authority, and the reported populations are tabulated below. Estimate the population in the town using (a) arithmetic growth projection, (b) geometric growth projection (exponential formula), (c) declining growth projection (assuming a saturation concentration of 480,000 people), and (d) logistic curve projection. Year Population 1980 167,358 1990 226,568 2000 285,061 2010 322,821 2020 342,618
Knowledge Booster
Background pattern image
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Principles of Geotechnical Engineering (MindTap C...
Civil Engineering
ISBN:9781305970939
Author:Braja M. Das, Khaled Sobhan
Publisher:Cengage Learning