BIO Basal Metabolic Rate. The basal metabolic rate is the rate at which energy is produced in the body when a person is at rest. A 75-kg (165-lb) person of height 1.83 m (6 ft) has a body surface area of approximately 2.0 m 2 . (a) What is the net amount of heat this person could radiate per second into a room at 18°C (about 65°F) if his skin’s surface temperature is 30°C? (At such temperatures, nearly all the heat is infrared radiation , for which the body’s emissivity is 1.0, regardless of the amount of pigment.) (b) Normally, 80% of the energy produced by metabolism goes into heat, while the rest goes into things like pumping blood and repairing cells. Also normally, a person at rest can get rid of this excess heat just through radiation. Use your answer to part (a) to find this person’s basal metabolic rate.
BIO Basal Metabolic Rate. The basal metabolic rate is the rate at which energy is produced in the body when a person is at rest. A 75-kg (165-lb) person of height 1.83 m (6 ft) has a body surface area of approximately 2.0 m 2 . (a) What is the net amount of heat this person could radiate per second into a room at 18°C (about 65°F) if his skin’s surface temperature is 30°C? (At such temperatures, nearly all the heat is infrared radiation , for which the body’s emissivity is 1.0, regardless of the amount of pigment.) (b) Normally, 80% of the energy produced by metabolism goes into heat, while the rest goes into things like pumping blood and repairing cells. Also normally, a person at rest can get rid of this excess heat just through radiation. Use your answer to part (a) to find this person’s basal metabolic rate.
BIO Basal Metabolic Rate. The basal metabolic rate is the rate at which energy is produced in the body when a person is at rest. A 75-kg (165-lb) person of height 1.83 m (6 ft) has a body surface area of approximately 2.0 m2. (a) What is the net amount of heat this person could radiate per second into a room at 18°C (about 65°F) if his skin’s surface temperature is 30°C? (At such temperatures, nearly all the heat is infrared radiation, for which the body’s emissivity is 1.0, regardless of the amount of pigment.) (b) Normally, 80% of the energy produced by metabolism goes into heat, while the rest goes into things like pumping blood and repairing cells. Also normally, a person at rest can get rid of this excess heat just through radiation. Use your answer to part (a) to find this person’s basal metabolic rate.
Chemical pathways by which living things function, especially those that provide cellular energy, such as the transformation of energy from food into the energy of ATP. Metabolism also focuses on chemical pathways involving the synthesis of new biomolecules and the elimination of waste.
In the Donkey Kong Country video games you often get around by shooting yourself out of barrel cannons. Donkey Kong wants to launch out of one barrel and land in a different one that is a distance in x of 9.28 m away. To do so he launches himself at a velocity of 22.6 m/s at an angle of 30.0°. At what height does the 2nd barrel need to be for Donkey Kong to land in it? (measure from the height of barrel 1, aka y0=0)
For which value of θ is the range of a projectile fired from ground level a maximum?
90° above the horizontal
45° above the horizontal
55° above the horizontal
30° above the horizontal
60° above the horizontal
A map from The Legend of Zelda: The Breath of the Wild shows that Zora's Domain is 7.55 km in a direction 25.0° north of east from Gerudo Town. The same map shows that the Korok Forest is 3.13 km in a direction 55.0° west of north from Zora's Domain. The figure below shows the location of these three places. Modeling Hyrule as flat, use this information to find the displacement from Gerudo Town to Korok Forest. What is the magnitude of the displacement? Find the angle of the displacement. Measure the angle in degrees north of east of Gerudo Town.
Chemistry: An Introduction to General, Organic, and Biological Chemistry (13th Edition)
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.