Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card
15th Edition
ISBN: 9781119231318
Author: Morris Hein
Publisher: Wiley (WileyPLUS Products)
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Chapter 17, Problem 10RQ

(a)

Interpretation Introduction

Interpretation:

More reactive metal in Mg and Ca has to be determined.

Concept Introduction:

Oxidation process represents loss of electrons. Reduction process represents gain of electrons. Oxidation numbers are the part of system that is formed to track electrons in reaction.

Series formed after arrangment of elements in increasing order of standard reduction potential is called electrochemical series.

Metals placed above in electrochemical series from hydrogen have very negative reduction potential and thus they are better reducing agent. Metals placed below from hydrogen in electrochemical series have positive reduction potential and thus they tend to act as an oxidizing agent in a redox reaction.

(b)

Interpretation Introduction

Interpretation:

More reactive metal in Fe and Ag has to be determined.

Concept Introduction:

Refer to part (a).

(c)

Interpretation Introduction

Interpretation:

More reactive metal in Zn and H has to be determined.

Concept Introduction:

Refer to part (a).

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AG/F-2° V 3. Before proceeding with this problem you may want to glance at p. 466 of your textbook where various oxo-phosphorus derivatives and their oxidation states are summarized. Shown below are Latimer diagrams for phosphorus at pH values at 0 and 14: -0.93 +0.38 -0.50 -0.51 -0.06 H3PO4 →H4P206 →H3PO3 →→H3PO₂ → P → PH3 Acidic solution Basic solution -0.28 -0.50 3--1.12 -1.57 -2.05 -0.89 PO HPO H₂PO₂ →P → PH3 -1.73 a) Under acidic conditions, H3PO4 can be reduced into H3PO3 directly (-0.28V), or via the formation and reduction of H4P206 (-0.93/+0.38V). Calculate the values of AG's for both processes; comment. (3 points) 0.5 PH P 0.0 -0.5 -1.0- -1.5- -2.0 H.PO, -2.3+ -3 -2 -1 1 2 3 2 H,PO, b) Frost diagram for phosphorus under acidic conditions is shown. Identify possible disproportionation and comproportionation processes; write out chemical equations describing them. (2 points) H,PO 4 S Oxidation stale, N
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2. Calculate the overall formation constant for [Fe(CN)6]³, given that the overall formation constant for [Fe(CN)6] 4 is ~1032, and that: Fe3+ (aq) + e = Fe²+ (aq) E° = +0.77 V [Fe(CN)6]³ (aq) + e¯ = [Fe(CN)6] (aq) E° = +0.36 V (4 points)

Chapter 17 Solutions

Foundations of College Chemistry 15e Binder Ready Version + WileyPLUS Registration Card

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