The equilibria that are associate with the equations of K inst for each of the given complex ions are to be written. The equations for the K inst of each of the complex ions are to be written. Concept Introduction: According to the law of chemical equilibrium , the equilibrium constant for an equilibrium reaction is the ratio of the product of the molar concentration of products to the product of the molar concentration of the reactants, each raised to the power of their stoichiometric coefficient in the overall balanced equilibrium reaction. For a general equilibrium reaction, aA + bB ⇄ cC+dD , the equilibrium constant will be represented as: K = [C] c [D] d [A] a [B] b The instability constant is reciprocal of the formation constant for an equilibrium reaction. The relation between these two is shown as follows: K inst = 1 K form Here, K inst is the instability constant and K form is the formation constant.
The equilibria that are associate with the equations of K inst for each of the given complex ions are to be written. The equations for the K inst of each of the complex ions are to be written. Concept Introduction: According to the law of chemical equilibrium , the equilibrium constant for an equilibrium reaction is the ratio of the product of the molar concentration of products to the product of the molar concentration of the reactants, each raised to the power of their stoichiometric coefficient in the overall balanced equilibrium reaction. For a general equilibrium reaction, aA + bB ⇄ cC+dD , the equilibrium constant will be represented as: K = [C] c [D] d [A] a [B] b The instability constant is reciprocal of the formation constant for an equilibrium reaction. The relation between these two is shown as follows: K inst = 1 K form Here, K inst is the instability constant and K form is the formation constant.
Definition Definition Number that is expressed before molecules, ions, and atoms such that it balances out the number of components present on either section of the equation in a chemical reaction. Stoichiometric coefficients can be a fraction or a whole number and are useful in determining the mole ratio among the reactants and products. In any equalized chemical equation, the number of components on either side of the equation will be the same.
Chapter 17, Problem 104RQ
Interpretation Introduction
Interpretation:
The equilibria that are associate with the equations of Kinst for each of the given complex ions are to be written. The equations for the Kinst of each of the complex ions are to be written.
Concept Introduction:
According to the law of chemical equilibrium, the equilibrium constant for an equilibrium reaction is the ratio of the product of the molar concentration of products to the product of the molar concentration of the reactants, each raised to the power of their stoichiometric coefficient in the overall balanced equilibrium reaction.
For a general equilibrium reaction, aA + bB ⇄cC+dD, the equilibrium constant will be represented as:
K = [C]c[D]d[A]a[B]b
The instability constant is reciprocal of the formation constant for an equilibrium reaction. The relation between these two is shown as follows:
Kinst=1Kform
Here, Kinst is the instability constant and Kform is the formation constant.
+
In aqueous solution the Ag ion forms a complex with two ammonia molecules.
Write the formation constant expression for the equilibrium between the hydrated metal ion and the aqueous complex. Under that, write the balanced chemical
equation for the first step in the formation of the complex.
Kƒ
+
Ag
(NH3)2]
g(H₂º)₂]*[N
NH
Write the First Step:
First Step:
Ag(H₂O), (aq) + 2NH¸(aq) → Ag(NH3)2(aq) + 2H₂O(1)
☑
5
Calculate the molar solubility of Cr(OH)3 in 0.50M NaOH; Kf for [Cr(OH)4]- is 8 x 10^29.
In aqueous solution the Co
ion forms a complex with six ammonia molecules.
Write the formation constant expression for the equilibrium between the hydrated metal ion and the aqueous complex. Under that, write the balanced chemical
equation for the first step in the formation of the complex.
K;
Write the First Step:
First Step:||
믐
?
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell
Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; Darrell