Explanation Given: The constant angular velocity of the arm A B is ω A B = 2 rad/s . The constant angular velocity of the car relative to the arm is ω ' = ( − 0.5 k ) rad/s . Draw the free body diagram of system as shown in Figure 1. Refer Figure (1). Write the formula for velocity of the car measured from the x , y , z reference. v C = v B + Ω × r C / B + ( v C / B ) x y z (I) Here, v C velocity vector of car C measured from the X , Y , Z reference, v B is the velocity vector of the origin B (end of the arm where the car is connected) measured from the X , Y , Z reference, ( v C / B ) x y z is the velocity vector of passenger at the car C with respect to arm end B measured by an observer attached to the rotating x , y , z reference, Ω is the angular velocity of the x , y , z reference measured from the X , Y , Z reference and r C / B is the position vector of the passenger at car C with respect to arm end B . Write the formula for acceleration of the car measured from the x , y , z reference a C = a B + Ω ˙ × r C / B + Ω × ( Ω × r C / B ) + 2 Ω × ( v C / B ) x y z + ( a C / B ) x y z (II) Here, a C acceleration vector of car C measured from the X , Y , Z reference, a B is the acceleration vector of the origin B (end of the arm where the car is connected) measured from the X , Y , Z reference, ( v C / B ) x y z , ( a C / B ) x y z is the velocity and acceleration vector of the passenger at car C with respect to arm end B measured by an observer attached to the rotating x , y , z reference, Ω ˙ is the angular acceleration due to the rotation of x , y , z reference, Ω is the angular velocity of the x , y , z reference measured from the X , Y , Z reference and r C / B is the position vector of the passenger at car C with respect to arm end B . Write the formula for velocity at B of the arm A B . v B = ω A B × r B / A (III) Here, ω A B is the angular velocity of the arm A B and r B / A is the position vector arm end B with respect to arm end A . Write the formula for acceleration at B of the arm A B . a B = α A B × r B / A − ω A B 2 r B / A (IV) Here, α A B is the angular acceleration of the arm A B . Conclusion: Refer Figure (1). Write the position vector ( r B / A ) directed from A to B .s r B / A = ( 10 cos 30 ° ) i + ( 10 sin 30 ° ) j = 8 .66i + 5 j Write the position vector ( r C / B ) directed from B to C . r C / B = 0 i − 2 j = − 2 j The angular velocity vector of the arm A B is ω A B = 2 k . Calculate the velocity at B of the arm A B . Substitute 2 k for ω A B and 8.66 i + 5 j for r B / A in Equation (III). v B = 2 k × ( 8.66 i + 5 j ) = | i j k 0 0 2 8.66 5 0 | = i ( 0 − 10 ) − j ( 0 − 17.321 ) + k ( 0 − 0 ) = ( − 10 i + 17.32 j ) ft/s Here, the arm has constant angular velocity, hence the angular acceleration of the arm A B is α A B = 0 . Calculate the velocity at B of the arm A B . Substitute 0 for α A B , 2 for ω A B and 8

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Chapter 16.8, Problem 145P

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The velocity and acceleration of the passenger at C .

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Chapter 16.8, Problem 144P

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