Student's Solutions Manual for Organic Chemistry
Student's Solutions Manual for Organic Chemistry
9th Edition
ISBN: 9780134160375
Author: Leroy G. Wade, Jan W. Simek
Publisher: PEARSON
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Chapter 16.7, Problem 16.9P

(a)

Interpretation Introduction

Interpretation:

The energy diagram for the MOs of a planar cyclooctatetraenyl system using the polygon rule is to be drawn.

Concept introduction:

The conditions that a molecule must follow to be an aromatic are shown below.

  • The given compound must be cyclic in nature.
  • It must be planar.
  • There must be no sp3 hybridized carbon in the given compound.
  • The compound must follow Huckel’s rule of aromaticity that is (4n+2)π electron system must be present.

If the given compound follows first three conditions but it follows 4nπ electron system, then it is antiaromatic in nature. If the given compound fails to follow any of the above conditions then it is non-aromatic in nature.

(b)

Interpretation Introduction

Interpretation:

The filling of eight pi electrons for cyclooctatetraene, the nature of electronic configuration as aromatic or antiaromatic and the possibility of attaining aromaticity by the gain or loss of electrons is to be stated.

Concept introduction:

The conditions that a molecule must follow to be an aromatic are shown below.

  • The given compound must be a cyclic in nature.
  • It must be planar.
  • There must be no sp3 hybridized carbon in the given compound.
  • The compound must follow Huckel’s rule of aromaticity that is (4n+2)π electron system must be present.

If the given compound follows first three conditions but it follows 4nπ electrons, then it is antiaromatic in nature. If the given compound fails to follow any of the above conditions then it is non-aromatic in nature.

(c)

Interpretation Introduction

Interpretation:

The pictorial representations for the three bonding and the two non-bonding MOs of cyclooctatetraene are to be drawn.

Concept introduction:

Molecular orbital diagrams are used for determining the bonding in molecules using linear combination of atomic orbitals. Number of molecular orbitals formed is equal to the number of atomic orbitals that combine with each other.

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Chapter 16 Solutions

Student's Solutions Manual for Organic Chemistry

Ch. 16.8A - Repeat Problem16-10 for the cyclopentadienyl ions....Ch. 16.8C - Explain why each compound or ion should be...Ch. 16.8C - The following hydrocarbon has an unusually large...Ch. 16.8C - Prob. 16.14PCh. 16.8C - Prob. 16.15PCh. 16.9B - Prob. 16.16PCh. 16.9C - Show which of the nitrogen atoms in purine are...Ch. 16.9C - The proton NMR spectrum of 2-pyridone gives the...Ch. 16.9D - Prob. 16.19PCh. 16.9D - Prob. 16.20PCh. 16.10 - Prob. 16.21PCh. 16.12 - Ciprofloxacin is a member of the fluoroquinolone...Ch. 16.13 - Draw and name all the chlorinated benzenes having...Ch. 16.13 - Name the following compounds:Ch. 16.15 - The UV spectrum of 1-phenylprop-2-en-1-ol shows an...Ch. 16 - Prob. 16.26SPCh. 16 - Name the following compounds:Ch. 16 - Draw and name all the methyl, dimethyl, and...Ch. 16 - Four pairs of compounds are shown. In each pair,...Ch. 16 - One of the following hydrocarbons is much more...Ch. 16 - In Kekuls time cyclohexane was unknown, and there...Ch. 16 - Prob. 16.32SPCh. 16 - Azulene is a deep-blue hydrocarbon with resonance...Ch. 16 - Prob. 16.34SPCh. 16 - Prob. 16.35SPCh. 16 - Prob. 16.36SPCh. 16 - Prob. 16.37SPCh. 16 - Prob. 16.38SPCh. 16 - Prob. 16.39SPCh. 16 - Biphenyl has the following structure. a. Is...Ch. 16 - Anions of hydrocarbons are rare, and dianions of...Ch. 16 - How would you convert the following compounds to...Ch. 16 - Prob. 16.43SPCh. 16 - Prob. 16.44SPCh. 16 - A student found an old bottle labeled thymol on...Ch. 16 - Prob. 16.46SPCh. 16 - Prob. 16.47SPCh. 16 - Prob. 16.48SPCh. 16 - The proton NMR chemical shifts of the hydrogens in...Ch. 16 - Prob. 16.50SPCh. 16 - NMR has been used to probe many molecular...
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