Explanation The graph of the quadratic equation y = a x 2 + b x + c is carried by find the ordered pair solution of the given equation by choosing some appropriate value of x . thereby finding the value of y . then plot the ordered pairs and joined the plots which gives, the graph of y = a x 2 + b x + c is a smooth curve through the plotted points. This curve is called a parabola. Find the vertex: The vertex considered by the lowest point on a parabola in opening upward and the highest point on a parabola in opening downward and the vertex formula of the parabola y = a x 2 + b x + c has x -coordinates − b 2 a . Find the intercepts: Let x = 0 and solve for y to find the y -intercepts. Let y = 0 and solve for x to find the x -intercepts. Calculation: Given, y = x 2 + 6 x Find the ordered pair’s solutions of the above equation by choosing some appropriate value for x, thereby finding the value of y. When, x = − 4 y = ( − 4 ) 2 + 6 ( − 4 ) = ( − 4 ⋅ − 4 ) + ( − 24 ) = 16 − 24 = − 8 Thus, the ordered pair solution is ( − 4 , − 8 ) When, x = − 3 y = ( − 3 ) 2 + 6 ( − 3 ) = ( − 3 ⋅ − 3 ) + ( − 18 ) = 9 − 18 = − 9 Thus, the ordered pair solution is ( − 3 , − 9 ) When, x = − 2 y = ( − 2 ) 2 + 6 ( − 2 ) = ( − 2 ⋅ − 2 ) + ( − 12 ) = 4 − 12 = − 8 Thus, the ordered pair solution is ( − 2 , − 8 ) When, x = − 1 y = ( − 1 ) 2 + 6 ( − 1 ) = ( − 1 ⋅ − 1 ) 2 + ( − 6 ) = 1 − 6 = − 5 Thus, the ordered pair solution is ( − 1 , − 5 ) When, x = 0 y = ( 0 ) 2 + 6 ( 0 ) y = 0 + 0 y = 0 Thus, the ordered pair solution is ( 0 , 0 ) When, x = 1 y = ( 1 ) 2 + 6 ( 1 ) = ( 1 ⋅ 1 ) + 6 = 1 + 6 = 7 Thus, the ordered pair solution is ( 1 , 7 ) When, x = 2 y = ( 2 ) 2 + 6 ( 2 ) = ( 2 ⋅ 2 ) + 12 = 4 + 12 = 16 Thus, the ordered pair solution is ( 2 , 16 ) When, x = 3 y = ( 3 ) 2 + 6 ( 3 ) = ( 3 ⋅ 3 ) + 18 = 9 + 18 = 27 Thus, the ordered pair solution is ( 3 , 27 ) When, x = 4 y = ( 4 ) 2 + 6 ( 4 ) = ( 4 ⋅ 4 ) + 24 = 16 + 24 = 40 Thus, the ordered pair solution ( 4 , 40 ) The obtained ordered pair is tabulated as

Prealgebra & Introductory Algebra (5th Edition) (What's New in Developmental Math)

5th Edition

ISBN: 9780134707631

Author: Elayn Martin-Gay

Publisher: PEARSON

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Chapter 16.4, Problem 19E

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To sketch:

To sketch the graph

y=x2+6x

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Chapter 16.4, Problem 18E

Chapter 16.4, Problem 20E

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Chapter 16 Solutions

Prealgebra & Introductory Algebra (5th Edition) (What's New in Developmental Math)

Ch. 16.1 - Prob. 1P Ch. 16.1 - Prob. 2P Ch. 16.1 - Prob. 3P Ch. 16.1 - Prob. 4P Ch. 16.1 - Prob. 5P Ch. 16.1 - Prob. 6P Ch. 16.1 - Prob. 7P Ch. 16.1 - Prob. 8P Ch. 16.1 - Prob. 9P Ch. 16.1 - Prob. 1E

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To sketch the graph y = x 2 + 6 x

To sketch: To sketch the graph y=x2+6x

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Chapter 16 Solutions

To sketch:

To sketch the graph

y=x2+6x