Explanation The graph of the quadratic equation y = a x 2 + b x + c is carried by find the ordered pair solution of the given equation by choosing some appropriate value of x , thereby finding the value of y , then plot the ordered pairs and joined the plots which gives, the graph of y = a x 2 + b x + c is a smooth curve through the plotted points. This curve is called a parabola. Find the vertex: The vertex considered by the lowest point on a parabola in opening upward and the highest point on a parabola in opening downward and the vertex formula of the parabola y = a x 2 + b x + c has x -coordinates − b 2 a . Find the intercepts: Let x = 0 and solve for y to find the y -intercepts. Let y = 0 and solve for x to find the x -intercepts. 2) Calculation: Given, y = 3 x 2 − x − 2 Find the ordered pair solutions of the above equation by choosing some appropriate value of x , there by finding the value of y . When x = − 4 , y = 3 ( − 4 ) 2 − ( − 4 ) − 2 = 3 ( 16 ) + ( 4 − 2 ) = 48 + 2 y = 50 Thus, the ordered pair is ( − 4 , 50 ) When x = − 3 , y = 3 ( − 3 ) 2 − ( − 3 ) − 2 = 3 ( 9 ) + 3 − 2 = 27 + 3 − 2 y = 28 Thus, the ordered pair is ( − 3 , 28 ) When, x = − 2 , y = 3 ( − 2 ) 2 − ( − 2 ) − 2 = 3 ( 4 ) + 2 − 2 = 12 + 2 − 2 = 14 − 2 y = 12 Thus, the ordered pair is ( − 2 , 12 ) When x = − 1 , y = 3 ( − 1 ) 2 − ( − 1 ) − 2 = 3 ( 1 ) + 1 − 2 = 3 + 1 − 2 = 4 − 2 y = 2 Thus, the ordered pair is ( − 1 , 2 ) When x = 0 , y = 3 ( 0 ) 2 − ( 0 ) − 2 = 0 − 0 − 2 y = − 2 Thus, the ordered pair is ( 0 , − 2 ) When x = 1 , y = 3 ( 1 ) 2 − ( 1 ) − 2 = 3 ( 1 ) − 1 − 2 = 3 − 1 − 2 = 3 − 3 y = 0 Thus, the ordered pair is ( 1 , 0 ) When x = 2 , y = 3 ( 2 ) 2 − 2 − 2 = 3 ( 4 ) − 2 − 2 = 12 − 4 y = 8 Thus, the ordered pair is ( 2 , 8 ) When x = 3 , y = 3 ( 3 ) 2 − 3 − 2 = 3 ( 9 ) − 3 − 2 = 27 − 5 y = 22 Thus, the ordered pair is ( 3 , 22 ) When x = 4 , y = 3 ( 4 ) 2 − 4 − 2 = 3 ( 16 ) − 4 − 2 = 48 − 6 y = 42 Thus, the ordered pair is ( 4 , 42 ) The obtained pairs tabulated as x y − 4 50 − 3 28 − 2 12 − 1 2 0 − 2 1 0 2 8 3 22 4 42 Thus, we need to plot the following ordered pairs to obtain the graph

Prealgebra & Introductory Algebra (5th Edition) (What's New in Developmental Math)

5th Edition

ISBN: 9780134707631

Author: Elayn Martin-Gay

Publisher: PEARSON

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Question

Chapter 16.CR, Problem 48CR

To determine

To graph:

y=3x2−x−2

Table the vertex and the intercepts with their coordinates.

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Chapter 16.CR, Problem 47CR

Chapter 16.CR, Problem 49CR

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The graph of f(x) is given below. Select each true statement about the continuity of f(x) at x = 1. Select all that apply: ☐ f(x) is not continuous at x = 1 because it is not defined at x = 1. ☐ f(x) is not continuous at x = 1 because lim f(x) does not exist. x+1 ☐ f(x) is not continuous at x = 1 because lim f(x) ‡ f(1). x+→1 ☐ f(x) is continuous at x = 1.

Chapter 16 Solutions

Prealgebra & Introductory Algebra (5th Edition) (What's New in Developmental Math)

Ch. 16.1 - Prob. 1P Ch. 16.1 - Prob. 2P Ch. 16.1 - Prob. 3P Ch. 16.1 - Prob. 4P Ch. 16.1 - Prob. 5P Ch. 16.1 - Prob. 6P Ch. 16.1 - Prob. 7P Ch. 16.1 - Prob. 8P Ch. 16.1 - Prob. 9P Ch. 16.1 - Prob. 1E

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To graph: y = 3 x 2 − x − 2 Table the vertex and the intercepts with their coordinates.

To graph: y=3x2−x−2 Table the vertex and the intercepts with their coordinates.

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Chapter 16 Solutions

To graph:

y=3x2−x−2

Table the vertex and the intercepts with their coordinates.