Explanation The graph of the quadratic equation y = a x 2 + b x + c is carried by find the ordered pair solution of the given equation by choosing some appropriate value of x , thereby finding the value of y , then plot the ordered pairs and joined the plots which gives, the graph of y = a x 2 + b x + c is a smooth curve through the plotted points. This curve is called a parabola. Find the vertex: The vertex considered by the lowest point on a parabola in opening upward and the highest point on a parabola in opening downward and the vertex formula of the parabola y = a x 2 + b x + c has x -coordinates − b 2 a . Find the intercepts: Let x = 0 and solve for y to find the y -intercepts. Let y = 0 and solve for x to find the x -intercepts. Calculation: Given, Find the ordered pairs solution of the above equation by choosing some appropriate value of x . thereby finding the value of y . When x = − 4 y = 4 − x 2 y = 4 − ( − 4 ) 2 y = 4 − 16 y = − 12 Thus, the ordered pair solution is ( − 4 , − 12 ) When x = − 3 y = 4 − x 2 = 4 − ( − 3 ) 2 = 4 − 9 y = − 5 Thus, the ordered pair solution is ( − 3 , − 5 ) When x = − 2 y = 1 − ( − 2 ) 2 y = 4 − 4 y = 0 Thus, the ordered pair solution is ( − 2 , 0 ) When, x = − 1 y = 4 − ( − 1 ) 2 y = 4 − 1 y = 3 Thus, the ordered pair solution is ( − 1 , 3 ) When x = 0 y = 4 − x 2 y = 4 − ( 0 ) 2 y = 4 − 0 y = 4 Thus, the ordered pair solution is ( 0 , 4 ) When x = 1 y = 4 − ( 1 ) 2 y = 4 − 1 y = 3 Thus, the ordered pair solution is ( 1 , 3 ) When x = 2 y = 4 − ( 2 ) 2 y = 4 − 4 y = 0 Thus, the ordered pair solution is ( 2 , 0 ) When x = 3 y = 4 − ( 3 ) 2 y = 4 − 9 y = − 5 Thus, the ordered pair solution is ( 3 , − 5 ) When x = 4 y = 4 − ( 4 ) 2 y = 4 − 16 y = − 12 Thus, the ordered pair solution is ( 4 , − 12 ) The obtained ordered pair solution tabulated as x y − 4 − 12 − 3 − 5 − 2 0 − 1 3 0 4 1 3 2 0 3 − 5 4 − 12 Thus, we need to plot the following ordered pairs to obtain the graph

Prealgebra & Introductory Algebra (5th Edition) (What's New in Developmental Math)

5th Edition

ISBN: 9780134707631

Author: Elayn Martin-Gay

Publisher: PEARSON

See similar textbooks

Question

Chapter 16.CR, Problem 69CR

To determine

To graph:

y=4−x2

Label the vertex and the intercepts with their co-ordinates.

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Chapter 16.CR, Problem 68CR

Chapter 16.CR, Problem 70CR

Students have asked these similar questions

18. If m n compute the gcd (a² + 1, a² + 1) in terms of a. [Hint: Let A„ = a² + 1 and show that A„|(Am - 2) if m > n.]

2. (5 points) Let f(x) = = - - - x² − 3x+7. Find the local minimum and maximum point(s) of f(x), and write them in the form (a, b), specifying whether each point is a minimum or maximum. Coordinates should be kept in fractions. Additionally, provide in your answer if f(x) has an absolute minimum or maximum over its entire domain with their corresponding values. Otherwise, state that there is no absolute maximum or minimum. As a reminder, ∞ and -∞ are not considered absolute maxima and minima respectively.

Let h(x, y, z) = — In (x) — z y7-4z - y4 + 3x²z — e²xy ln(z) + 10y²z. (a) Holding all other variables constant, take the partial derivative of h(x, y, z) with respect to x, 2 h(x, y, z). მ (b) Holding all other variables constant, take the partial derivative of h(x, y, z) with respect to y, 2 h(x, y, z).

Chapter 16 Solutions

Prealgebra & Introductory Algebra (5th Edition) (What's New in Developmental Math)

Ch. 16.1 - Prob. 1P Ch. 16.1 - Prob. 2P Ch. 16.1 - Prob. 3P Ch. 16.1 - Prob. 4P Ch. 16.1 - Prob. 5P Ch. 16.1 - Prob. 6P Ch. 16.1 - Prob. 7P Ch. 16.1 - Prob. 8P Ch. 16.1 - Prob. 9P Ch. 16.1 - Prob. 1E

Knowledge Booster

To graph: y = 4 − x 2 Label the vertex and the intercepts with their co-ordinates.

To graph: y=4−x2 Label the vertex and the intercepts with their co-ordinates.

Want to see the full answer?

Chapter 16 Solutions

To graph:

y=4−x2

Label the vertex and the intercepts with their co-ordinates.