(a)
Interpretation:
Whether carbon dioxide can be used to interpret alcoholic fermentation should be determined.
Concept introduction:
Alcoholic fermentation is the anaerobic pathway, which uses sugar such as glucose, fructose, and sucrose to convert into alcohol and carbon dioxides. During this process energy is released in the form of ATP. Overall in this process, 2 moles of glucose are converted to 2 moles of ethanol and 2 mole of carbon dioxide, yielding 2 moles of ATP.
(b)
Interpretation:
The reason of dependence of glucose fermentation on phosphate is to be determined.
Concept introduction:
Alcoholic fermentation is the anaerobic pathway, which uses sugar such as glucose, fructose, and sucrose to convert into alcohol and carbon dioxides. During this process energy is released in the form of ATP. Overall in this process, 2 moles of glucose are converted to 2 moles of ethanol and 2 mole of carbon dioxide, yielding 2 moles of ATP.
(c)
Interpretation:
The reason why more phosphate can lead to more yield of carbon dioxide during alcohol fermentation is to be determined.
Concept introduction:
Alcoholic fermentation is the anaerobic pathway, which uses sugar such as glucose, fructose, and sucrose to convert into alcohol and carbon dioxides. During this process energy is released in the form of ATP. Overall in this process, 2 moles of glucose are converted to 2 moles of ethanol and 2 mole of carbon dioxide, yielding 2 moles of ATP.
(d)
Interpretation:
The ratio of carbon dioxide to phosphate during fermentation is to be determined.
Concept introduction:
Alcoholic fermentation is the anaerobic pathway, which uses sugar such as glucose, fructose, and sucrose to convert into alcohol and carbon dioxides. During this process, energy is released in the form of ATP. Overall in this process, 2 moles of glucose are converted to 2 moles of ethanol and 2 mole of carbon dioxide, yielding 2 moles of ATP.
(e)
Interpretation:
The hexose bisphosphate compound accumulated when fermentation is stopped.
Concept introduction:
Alcoholic fermentation is the anaerobic pathway, which uses sugar such as glucose, fructose, and sucrose to convert into alcohol and carbon dioxides. During this process, energy is released in the form of ATP. Overall in this process, 2 moles of glucose are converted to 2 moles of ethanol and 2 mole of carbon dioxide, yielding 2 moles of ATP.
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Chapter 16 Solutions
BIOCHEMISTRY W/1 TERM ACHEIVE ACCESS
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- Penicillin is hydrolyzed and thereby rendered inactive by penicillinase (also known as ẞ-lactamase), an enzyme present in some penicillin-resistant bacteria. The mass of this enzyme in Staphylococcus aureus is 29.6 kDa. The amount of penicillin hydrolyzed in 1 minute in a 10.0 mL. solution containing 1.00 x 10 g of purified penicillinase was measured as a function of the concentration of penicillin. Assume that the concentration of penicillin does not change appreciably during the assay. Plots of V versus [S] and 1/V versus 1/[S] for these data are shown. Vo (* 10 M minute"¹) 7.0 6.0 5.0 4.0 3.0 20 1.0 0.0 о 10 20 30 1/Vo (* 10 M1 minute) 20 103 90 BO 70 50 [S] (* 100 M) 40 50 60 y=762x+1.46 × 10" [Penicillin] (M) Amount hydrolyzed (uM) 1 0.11 3 0.25 5 0.34 10 0.45 30 0.58 50 0.61arrow_forwardConsider the four graphs shown. In each graph, the solid blue curve represents the unmodified allosteric enzyme and the dashed green curve represents the enzyme in the presence of the effector. Identify which graphs correctly illustrate the effect of a negative modifier (allosteric inhibitor) and a positive modifier (allosteric activator) on the velocity curve of an allosteric enzyme. Place the correct graph in the set of axes for each type of modifier. Negative modifier Reaction velocity - Positive modifier Substrate concentration - Reaction velocity →→→→ Substrate concentration Answer Bankarrow_forwardConsider the reaction: phosphoglucoisomerase Glucose 6-phosphate: glucose 1-phosphate After reactant and product were mixed and allowed to reach at 25 °C, the concentration of each compound at equilibrium was measured: [Glucose 1-phosphate] = 0.01 M [Glucose 6-phosphate] = 0.19 M Calculate Keq and AG°'. Код .0526 Incorrect Answer 7.30 AG°' kJ mol-1 Incorrect Answerarrow_forward
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