Chapter 16, Problem 53E

Interpretation Introduction

Interpretation:

The added volume of the base, $\text{0}\text{.1014}\text{M}$ $\text{KOH}$ titrated with a $\text{20}\text{.0}\text{mL}$ sample of $\text{0}\text{.115}\text{M}$ sulfurous acid is to be calculated.

Concept introduction: The titration between a strong base and a strong acid results in a $\text{pH}$ of $7$ at equivalence point because at the equivalence point equal concentrations of ${\text{H}}^{+}$ ions and ${\text{OH}}^{-}$ ions combines to form water that is neutral in nature.

To determine: The added volume of the base, $\text{0}\text{.1014}\text{M}$ $\text{KOH}$ titrated with a $\text{20}\text{.0}\text{mL}$ sample of $\text{0}\text{.115}\text{M}$ sulfurous acid.