Chapter 16, Problem 47E

Interpretation Introduction

Interpretation:

The various questions based on the given titration of a $\text{25}\text{.0}\text{mL}$ sample of $\text{0}\text{.175}\text{M}$ ${\text{CH}}_{\text{3}}{\text{NH}}_{\text{2}}$ with $\text{0}\text{.150}\text{M}$ $\text{HBr}$ are to be answered.

Concept introduction: The titration between a strong base and a strong acid titration results in a $\text{pH}$ of $7$ at equivalence point because at the equivalence point equal concentrations of ${\text{H}}^{+}$ ions and ${\text{OH}}^{-}$ ions combines to form water that is neutral in nature.

To determine: The various questions based on the given titration of a $\text{25}\text{.0}\text{mL}$ sample of $\text{0}\text{.175}\text{M}$ ${\text{CH}}_{\text{3}}{\text{NH}}_{\text{2}}$ with $\text{0}\text{.150}\text{M}$ $\text{HBr}$ .