It is given that, sulfur undergoes a phase change from the rhombic crystal structure to the monoclinic crystal form at temperatures above 95 ° C . The sign of Δ S and Δ H is to be predicted for this change. The form of sulfur that has the more ordered crystalline structure is to be identified. Concept introduction: Entropy is the measure of degree of disorder or randomness. The value of Δ S is calculated using the formula, Δ S = Δ H T .
It is given that, sulfur undergoes a phase change from the rhombic crystal structure to the monoclinic crystal form at temperatures above 95 ° C . The sign of Δ S and Δ H is to be predicted for this change. The form of sulfur that has the more ordered crystalline structure is to be identified. Concept introduction: Entropy is the measure of degree of disorder or randomness. The value of Δ S is calculated using the formula, Δ S = Δ H T .
Solution Summary: The author explains that sulfur undergoes a phase change from the rhombic crystal structure to the monoclinic crystal form.
Interpretation: It is given that, sulfur undergoes a phase change from the rhombic crystal structure to the monoclinic crystal form at temperatures above
95°C. The sign of
ΔS and
ΔH is to be predicted for this change. The form of sulfur that has the more ordered crystalline structure is to be identified.
Concept introduction: Entropy is the measure of degree of disorder or randomness. The value of
ΔS is calculated using the formula,
ΔS=ΔHT.
(b)
Interpretation Introduction
Interpretation: It is given that, sulfur undergoes a phase change from the rhombic crystal structure to the monoclinic crystal form at temperatures above
95°C. The sign of
ΔS and
ΔH is to be predicted for this change. The form of sulfur that has the more ordered crystalline structure is to be identified.
Concept introduction: Entropy is the measure of degree of disorder or randomness. The value of
ΔS is calculated using the formula,
E17E.2(a) The following mechanism has been proposed for the decomposition
of ozone in the atmosphere:
03 → 0₂+0
k₁
O₁₂+0 → 03
K
→>
2
k₁
Show that if the third step is rate limiting, then the rate law for the
decomposition of O3 is second-order in O3 and of order −1 in O̟.
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Calorimetry Concept, Examples and Thermochemistry | How to Pass Chemistry; Author: Melissa Maribel;https://www.youtube.com/watch?v=nSh29lUGj00;License: Standard YouTube License, CC-BY