Essential Organic Chemistry, Global Edition
3rd Edition
ISBN: 9781292089034
Author: Paula Yurkanis Bruice
Publisher: PEARSON
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 16, Problem 41P
Interpretation Introduction
Interpretation:
The explanation corresponding to the given statement that
Concept Introduction:
The chair conformers are stable forms of cyclic compounds. In chair conformation, substituent’s prefers to place at equatorial positions. This is due to unwanted interactions between those substituent’s that are placed at axial positions. These interactions cause repulsion and that leads to the un-stability in molecule. The general interactions that occur between axial substituents are
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The most stable conformation of the pyranose ring of most D-aldohexoses places the largest group, CH2OH, in the equatorial
position. An exception to this is the aldohexose D-idose. Draw the two possible chair conformations of either the a or B anomer
of D-idose. Explain why the more stable conformation has the CH2OH group in the axial position.
The most stable conformation of the pyranose ring of most Daldohexosesplaces the largest group, CH2OH, in the equatorial position.An exception to this is the aldohexose D-idose. Draw the two possiblechair conformations of either the α or β anomer of D-idose. Explain whythe more stable conformation has the CH2OH group in the axial position .
Trehalose and isomaltose are both dimers of glucose. However, they have considerablydifferent reactivities. Concisely explain why these differences are observed.
Chapter 16 Solutions
Essential Organic Chemistry, Global Edition
Ch. 16.1 - Prob. 1PCh. 16.2 - Prob. 2PCh. 16.3 - Prob. 3PCh. 16.3 - Prob. 4PCh. 16.4 - Prob. 5PCh. 16.4 - Prob. 6PCh. 16.5 - Prob. 7PCh. 16.5 - Prob. 8PCh. 16.6 - Prob. 10PCh. 16.8 - Prob. 12P
Ch. 16.8 - Prob. 14PCh. 16.9 - Prob. 15PCh. 16.10 - Prob. 16PCh. 16.11 - Refer to Figure 16.4 to answer the following...Ch. 16 - Prob. 18PCh. 16 - Prob. 19PCh. 16 - Prob. 20PCh. 16 - Prob. 21PCh. 16 - Prob. 22PCh. 16 - Prob. 23PCh. 16 - Prob. 24PCh. 16 - Prob. 25PCh. 16 - Name the following compounds:Ch. 16 - Prob. 28PCh. 16 - Prob. 29PCh. 16 - Prob. 31PCh. 16 - Prob. 32PCh. 16 - Prob. 33PCh. 16 - Prob. 34PCh. 16 - Prob. 35PCh. 16 - Prob. 36PCh. 16 - Prob. 37PCh. 16 - Draw the mechanism for the acid-catalyzed...Ch. 16 - Prob. 39PCh. 16 - Prob. 40PCh. 16 - Prob. 41P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.Similar questions
- Trehalose and maltose are both dimers of glucose. However, they have considereably different reactivities. Concisely explain why these differences are observed. но но HO HO но "HO он но он OH O HO OHOH но trehalose maltose 1. Malthose is a reducing sugar while trehalose is not. 2. Trehalose is very resistant to acid hydrolysis while maltose can be acid-hydrolyzed with ease.arrow_forward4. An iterative approach to oligosaccharide synthesis involves the use of protected glycals (sugars with C1-C2 double bond) as shown below. The product from the reaction of the first glycal with DMDO under anhydrous conditions is treated with another suitably-protected glycal to form a disaccharide glycal, and the process can be repeated to form a trisaccharide glycal, and so on... Crucial to the success of this approach is the stereoselective formation of the intermediate A in the scheme below. Draw the structure of A. DMDO CH₂Cl2 A OH ZnCl₂, THF OHarrow_forward(with explanation )arrow_forward
- C. Trehalose and maltose are both dimers of glucose. However, they have considereably different reactivities. Concisely explain why these differences are observed. HO НО НО HO Но HO OH Он HO OHOH Но trehalose maltose 1. Malthose is a reducing sugar while trehalose is not. 2. Trehalose is very resistant to acid hydrolysis while maltose can be acid-hydrolyzed with ease.arrow_forwardThe Fischer Projection of Talose is shown below. Draw its methyl glycoside in its lowest energy chair conformation CHO но но H. но HO. ČH,OHarrow_forward5. Provide suitable responses for questions (a) – (). 6 CH2OH 4 OH OH 3 OH (a) What is the relative configuration of the above monosaccharide? (b) Which labeled carbon is the anomeric carbon? (c) Trace and identify the acetal in the above monosaccharide. (d) Draw the hemiacetal that results from above acetal. (e) Draw the open chain equivalent of the sugar in part (d). (f) Classify the monosaccharide below as a D-sugar or an L-sugar. H. OH O. OH CH,OH OH OHarrow_forward
- The structure of D-glucose is shown below. Predict the number of the OH groups (not CH₂OH) that occupy equatorial positions in the most stable chair conformation of D- glucose. HO,, HO OH "OH OH D-glucosearrow_forward1. For lactose (below), OH OH НО НО OH 0 -ОН ОН OH (A) Circle and label any acetal groups (B) Circle and label any hemiacetal groups (C) Use an arrow to point to any glycoside bonds (D) What is the configuration (o or B) at the anomeric carbon of the "left" (E) Which ring (left or right) is in equilibrium with an open-chain form?arrow_forward(g) Using appropriate prefixes/infixes/suffixes (ketoheptose, aldoheptose, etc.), classify each of the monosaccharides shown below. CHO CH2OH Но IH но- HO- HO- HO H. CH2OH CH2OH I II (h) Identify B-D-altrose and a-D-altrose from the monosaccharides shown below. CH2OH CH2OH CH2OH CH2OH OH OH OH ОН OH ОН ОН OH OH OH OH OH OH OH OH OH I II II IV (i) Identify B-D-altrose and a-D-altrose from the monosaccharides shown below. VI I CH2OH O CH2OH II H V ОН, III IV OH OH Harrow_forward
- Fischer projections for 2 D-aldohexosearrow_forwardD-glucose exists as two epimeric cyclic hemiacetals: a-D-glucopyranose (left, labeled hydroxy group is in the axial position) and B-D-glucopyranose (right, the labeled hydroxy group is in equatorial position). The two anomers equilibrate via the open aldehyde form. Draw the curved arrows to show the complete reaction mechanism for the conversion of one anomer to the other under acidic catalysis. HOH HOH Ho HO HO HO HO- H H HO- OH!-- H H OH H OHI Harrow_forwardProvide suitable responses for questions (a) –(j).| 6 CH2OH 4 ОН OH OH 2.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage LearningChemistry for Today: General, Organic, and Bioche...ChemistryISBN:9781305960060Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. HansenPublisher:Cengage Learning
Organic Chemistry
Chemistry
ISBN:9781305580350
Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. Foote
Publisher:Cengage Learning
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning