
Big Java, Binder Ready Version: Early Objects
6th Edition
ISBN: 9781119056447
Author: Cay S. Horstmann
Publisher: WILEY
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Question
Chapter 16, Problem 2PP
Program Plan Intro
The methods “get()” and “set()” and a recursive helper method “getNode()”
Program plan:
- In a file “ListIterator.java”, create an interface “ListIterator”,
- Declare the method “next()” that moves the iterator past the next element.
- Declare the method “hasNext()” that check if there is an element after the iterator position.
- Declare the method “add()” that adds an element before the position of the iterator and moves the iterator past the added element.
- Declare the method “remove()” that removes the last traversed element.
- Declare the method “set()” to set the last traversed element to a previous value.
- In a file “LinkedList.java”, import the package and create a class “LinkedList”,
- Declare the object variable.
- Declare the necessary variable.
- Define the constructor to create an empty linked list.
- Define the method “size()” that returns the size of linked list.
- Define the method “getFirst()” that returns the first element in the linked list.
- Define the method “removeFirst()” to remove the first element in the linked list.
- Define the method “addFirst()” that adds an element to the linked list.
- Define the method “get()” to get the object to the given index.
- Define the method “set()” to set the object to the given index.
- Define the method “getNode()”,
- Check whether the distance is less than or equal to “0” or start contains null value,
- If it is true, returns start value.
- Call the method “getNode()” recursively.
-
- Define the method “listIterator” of type “ListIterator”, that returns an iterator for iterating through the list.
- Create a class “Node”,
-
- Declare the object variable for “Object”, and “Node”.
- Create a class “LinkedListIterator”,
-
- Declare the necessary object variables.
- Define the constructor to create an iterator that points to the front of the linked list.
- Define the method “next()”,
- If there is no next element then throws an exception.
- Assign the position to the front of the linked list.
- Check if position is null, set the first element to the position.
- Otherwise, set the next position to the current position.
- Define the method “hasNext()” that check whether there is next element.
- Define the method “add()”,
- If position is null, call the method “addFirst()”.
- Set the first to the position.
- Otherwise, create a new node.
- Assign the element to the new node.
- Set the next position to the next pointer of the new node.
- Set the new node value to the next position.
- Set the new node as the position.
- Increment the size.
- Set the position to the previous node.
- If position is null, call the method “addFirst()”.
- Define the method “remove()”,
- If position is same as the previous, throws an exception.
- If the position is the first position, call the method “removeFirst()”.
- Otherwise, set the position to the previous position.
- Increment the size.
- Set the previous position to the position.
- Define the method “set()”,
- If position is null, throw an exception.
- Set the value to the position.
-
- Check whether the distance is less than or equal to “0” or start contains null value,
- In a file “ListTest.java”, create a class “ListTest”,
- Define the “main()” method.
- Create “LinkedList” object.
- Add the element “Tony” to the linked list.
- Add the element “Juliet” to the linked list.
- Add the element “Harris” to the linked list.
- Add the element “David” to the linked list.
- Print the element returned from the method “get()”.
- Print new line.
- Print expected result.
- Call the method “set()” to set the element “Jerry” to “2”.
- Print the element returned from the method “get()”.
- Print new line.
- Print expected result.
- Define the “main()” method.
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I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
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• No row may contain the same value twice.
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To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
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Chapter 16 Solutions
Big Java, Binder Ready Version: Early Objects
Ch. 16.1 - Prob. 1SCCh. 16.1 - Prob. 2SCCh. 16.1 - Prob. 3SCCh. 16.1 - Prob. 4SCCh. 16.1 - Prob. 5SCCh. 16.1 - Prob. 6SCCh. 16.1 - Prob. 7SCCh. 16.2 - Prob. 8SCCh. 16.2 - Prob. 9SCCh. 16.2 - Prob. 10SC
Ch. 16.2 - Prob. 11SCCh. 16.2 - Prob. 12SCCh. 16.3 - Prob. 13SCCh. 16.3 - Prob. 14SCCh. 16.3 - Prob. 15SCCh. 16.3 - Prob. 16SCCh. 16.3 - Prob. 17SCCh. 16.3 - Prob. 18SCCh. 16.4 - Prob. 19SCCh. 16.4 - Prob. 20SCCh. 16.4 - Prob. 21SCCh. 16.4 - Prob. 22SCCh. 16.4 - Prob. 23SCCh. 16.4 - Prob. 24SCCh. 16 - Prob. 1RECh. 16 - Prob. 2RECh. 16 - Prob. 3RECh. 16 - Prob. 4RECh. 16 - Prob. 5RECh. 16 - Prob. 6RECh. 16 - Prob. 7RECh. 16 - Prob. 8RECh. 16 - Prob. 9RECh. 16 - Prob. 10RECh. 16 - Prob. 11RECh. 16 - Prob. 12RECh. 16 - Prob. 13RECh. 16 - Prob. 14RECh. 16 - Prob. 15RECh. 16 - Prob. 16RECh. 16 - Prob. 17RECh. 16 - Prob. 18RECh. 16 - Prob. 19RECh. 16 - Prob. 20RECh. 16 - Prob. 21RECh. 16 - Prob. 22RECh. 16 - Prob. 23RECh. 16 - Prob. 24RECh. 16 - Prob. 25RECh. 16 - Prob. 26RECh. 16 - Prob. 1PECh. 16 - Prob. 2PECh. 16 - Prob. 3PECh. 16 - Prob. 4PECh. 16 - Prob. 5PECh. 16 - Prob. 6PECh. 16 - Prob. 7PECh. 16 - Prob. 8PECh. 16 - Prob. 9PECh. 16 - Prob. 10PECh. 16 - Prob. 11PECh. 16 - Prob. 12PECh. 16 - Prob. 13PECh. 16 - Prob. 14PECh. 16 - Prob. 15PECh. 16 - Prob. 16PECh. 16 - Prob. 17PECh. 16 - Prob. 18PECh. 16 - Prob. 19PECh. 16 - Prob. 20PECh. 16 - Prob. 21PECh. 16 - Prob. 1PPCh. 16 - Prob. 2PPCh. 16 - Prob. 3PPCh. 16 - Prob. 4PPCh. 16 - Prob. 5PPCh. 16 - Prob. 6PPCh. 16 - Prob. 7PPCh. 16 - Prob. 8PPCh. 16 - Prob. 9PPCh. 16 - Prob. 10PPCh. 16 - Prob. 11PPCh. 16 - Prob. 12PPCh. 16 - Prob. 13PPCh. 16 - Prob. 14PPCh. 16 - Prob. 15PPCh. 16 - Prob. 16PPCh. 16 - Prob. 17PP
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