Big Java, Binder Ready Version: Early Objects
6th Edition
ISBN: 9781119056447
Author: Cay S. Horstmann
Publisher: WILEY
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Expert Solution & Answer
Chapter 16, Problem 15RE
Explanation of Solution
Improvement of big-Oh estimate of element access in a doubly-linked list:
- The big-Oh efficiency of locating the kth element in the linked list doesn’t improves because to get any randomly selected element, the starting point should be either at the front or at the back...
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Students have asked these similar questions
Exercise 1 Function and Structure [30 pts]
Please debug the following program and answer the following questions. There is a cycle in a linked
list if some node in the list can be reached again by continuously following the next pointer.
#include
typedef struct node {
int value;
struct node *next;
} node;
int 11_has_cycle (node *first)
if (first
==
node *head =
{
NULL) return 0;
first;
while (head->next != NULL) {
}
if (head
first) {
return 1; }
head = head->next;
return 0;
void test ll_has_cycle () {
int i;
node nodes [6];
for (i = 0; i < 6; i++) {
nodes [i] .next = NULL;
nodes [i].value = i;
}
nodes [0] .next
=
&nodes [1];
nodes [1] .next
=
&nodes [2];
nodes [2] .next
=
&nodes [3];
nodes [3] .next
nodes [4] .next
&nodes [4];
NULL;
nodes [5] .next = &nodes [0];
printf("1. Checking first list for cycles. \n Function 11_has_cycle says it
has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no");
printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle
says it has %s…
how to read log logs
Discrete Mathematics for Computer Engineering
Chapter 16 Solutions
Big Java, Binder Ready Version: Early Objects
Ch. 16.1 - Prob. 1SCCh. 16.1 - Prob. 2SCCh. 16.1 - Prob. 3SCCh. 16.1 - Prob. 4SCCh. 16.1 - Prob. 5SCCh. 16.1 - Prob. 6SCCh. 16.1 - Prob. 7SCCh. 16.2 - Prob. 8SCCh. 16.2 - Prob. 9SCCh. 16.2 - Prob. 10SC
Ch. 16.2 - Prob. 11SCCh. 16.2 - Prob. 12SCCh. 16.3 - Prob. 13SCCh. 16.3 - Prob. 14SCCh. 16.3 - Prob. 15SCCh. 16.3 - Prob. 16SCCh. 16.3 - Prob. 17SCCh. 16.3 - Prob. 18SCCh. 16.4 - Prob. 19SCCh. 16.4 - Prob. 20SCCh. 16.4 - Prob. 21SCCh. 16.4 - Prob. 22SCCh. 16.4 - Prob. 23SCCh. 16.4 - Prob. 24SCCh. 16 - Prob. 1RECh. 16 - Prob. 2RECh. 16 - Prob. 3RECh. 16 - Prob. 4RECh. 16 - Prob. 5RECh. 16 - Prob. 6RECh. 16 - Prob. 7RECh. 16 - Prob. 8RECh. 16 - Prob. 9RECh. 16 - Prob. 10RECh. 16 - Prob. 11RECh. 16 - Prob. 12RECh. 16 - Prob. 13RECh. 16 - Prob. 14RECh. 16 - Prob. 15RECh. 16 - Prob. 16RECh. 16 - Prob. 17RECh. 16 - Prob. 18RECh. 16 - Prob. 19RECh. 16 - Prob. 20RECh. 16 - Prob. 21RECh. 16 - Prob. 22RECh. 16 - Prob. 23RECh. 16 - Prob. 24RECh. 16 - Prob. 25RECh. 16 - Prob. 26RECh. 16 - Prob. 1PECh. 16 - Prob. 2PECh. 16 - Prob. 3PECh. 16 - Prob. 4PECh. 16 - Prob. 5PECh. 16 - Prob. 6PECh. 16 - Prob. 7PECh. 16 - Prob. 8PECh. 16 - Prob. 9PECh. 16 - Prob. 10PECh. 16 - Prob. 11PECh. 16 - Prob. 12PECh. 16 - Prob. 13PECh. 16 - Prob. 14PECh. 16 - Prob. 15PECh. 16 - Prob. 16PECh. 16 - Prob. 17PECh. 16 - Prob. 18PECh. 16 - Prob. 19PECh. 16 - Prob. 20PECh. 16 - Prob. 21PECh. 16 - Prob. 1PPCh. 16 - Prob. 2PPCh. 16 - Prob. 3PPCh. 16 - Prob. 4PPCh. 16 - Prob. 5PPCh. 16 - Prob. 6PPCh. 16 - Prob. 7PPCh. 16 - Prob. 8PPCh. 16 - Prob. 9PPCh. 16 - Prob. 10PPCh. 16 - Prob. 11PPCh. 16 - Prob. 12PPCh. 16 - Prob. 13PPCh. 16 - Prob. 14PPCh. 16 - Prob. 15PPCh. 16 - Prob. 16PPCh. 16 - Prob. 17PP
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