The a l d o h e x o s e s and ketohexoses that are formed when D − t a g a t o s e is added to a basic aqueous solution are to be identified. Concept Introduction: In the enediol rearrangement of a monosaccharide, the base removes the proton from the α -carbon resulting in the formation of enolate ion. After the deprotonation, enediol is formed resulting in the formation of aldohexose and ketohexose by the base-catalyzed conversion.

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Answer 1

Question

Chapter 16, Problem 21P

Interpretation Introduction

Interpretation:

The aldohexoses and ketohexoses that are formed when D−tagatose is added to a basic aqueous solution are to be identified.

Concept Introduction:

In the enediol rearrangement of a monosaccharide, the base removes the proton from the α-carbon resulting in the formation of enolate ion. After the deprotonation, enediol is formed resulting in the formation of aldohexose and ketohexose by the base-catalyzed conversion.

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Answer 2

Question

Chapter 16, Problem 21P

Interpretation Introduction

Interpretation:

The aldohexoses and ketohexoses that are formed when D−tagatose is added to a basic aqueous solution are to be identified.

Concept Introduction:

In the enediol rearrangement of a monosaccharide, the base removes the proton from the α-carbon resulting in the formation of enolate ion. After the deprotonation, enediol is formed resulting in the formation of aldohexose and ketohexose by the base-catalyzed conversion.

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Answer 3

Question

Chapter 16, Problem 21P

Interpretation Introduction

Interpretation:

The aldohexoses and ketohexoses that are formed when D−tagatose is added to a basic aqueous solution are to be identified.

Concept Introduction:

In the enediol rearrangement of a monosaccharide, the base removes the proton from the α-carbon resulting in the formation of enolate ion. After the deprotonation, enediol is formed resulting in the formation of aldohexose and ketohexose by the base-catalyzed conversion.

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Answer 4

Question

Chapter 16, Problem 21P

Interpretation Introduction

Interpretation:

The aldohexoses and ketohexoses that are formed when D−tagatose is added to a basic aqueous solution are to be identified.

Concept Introduction:

In the enediol rearrangement of a monosaccharide, the base removes the proton from the α-carbon resulting in the formation of enolate ion. After the deprotonation, enediol is formed resulting in the formation of aldohexose and ketohexose by the base-catalyzed conversion.

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Answer 5

Chapter 16, Problem 21P

Interpretation Introduction

Interpretation:

The aldohexoses and ketohexoses that are formed when D−tagatose is added to a basic aqueous solution are to be identified.

Concept Introduction:

In the enediol rearrangement of a monosaccharide, the base removes the proton from the α-carbon resulting in the formation of enolate ion. After the deprotonation, enediol is formed resulting in the formation of aldohexose and ketohexose by the base-catalyzed conversion.

Answer 6

Chapter 16, Problem 21P

Interpretation Introduction

Interpretation:

The aldohexoses and ketohexoses that are formed when D−tagatose is added to a basic aqueous solution are to be identified.

Concept Introduction:

In the enediol rearrangement of a monosaccharide, the base removes the proton from the α-carbon resulting in the formation of enolate ion. After the deprotonation, enediol is formed resulting in the formation of aldohexose and ketohexose by the base-catalyzed conversion.

Answer 7

Chapter 16, Problem 21P

Interpretation Introduction

Interpretation:

The aldohexoses and ketohexoses that are formed when D−tagatose is added to a basic aqueous solution are to be identified.

Concept Introduction:

In the enediol rearrangement of a monosaccharide, the base removes the proton from the α-carbon resulting in the formation of enolate ion. After the deprotonation, enediol is formed resulting in the formation of aldohexose and ketohexose by the base-catalyzed conversion.

Answer 8

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Answer 11

Ch. 16.1 - Prob. 1P Ch. 16.2 - Prob. 2P Ch. 16.3 - Prob. 3P Ch. 16.3 - Prob. 4P Ch. 16.4 - Prob. 5P Ch. 16.4 - Prob. 6P Ch. 16.5 - Prob. 7P Ch. 16.5 - Prob. 8P Ch. 16.6 - Prob. 10P Ch. 16.8 - Prob. 12P

Solution Summary: The author explains the formation of aldohexoses and ketose by the base-catalyzed conversion of a monosaccharide.

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Chapter 16 Solutions