Chapter 1.6, Problem 1P

What is the weight in newtons of an object that has a mass of (a) 8 kg, (b) 0.04 kg, and (c) 760 Mg?

To determine

To convert:

The weight in newtons of an object that has a mass in $\text{kg}$.

Answer to Problem 1P

The weight in newtons of an object that has a mass of $\text{8}\text{kg}$ is $\underset{\_}{\text{78}\text{.5}\text{N}}$.

Explanation of Solution

Given:

The mass of the object is $\text{8}\text{kg}$.

Write the conversion for the quantity.

$\text{8}\text{kg}$

Write the conversion formula.

$\text{kg}=9.81\text{N}$

Conclusion:

Convert the weight in newtons from $\text{kg}$.

$\begin{array}{c}W=8\text{kg}\times \frac{9.81\text{N}}{\text{kg}}\\ =78.5\text{N}\end{array}$

Thus, the weight in newtons of an object is $\underset{\_}{\text{78}\text{.5}\text{N}}$.

To determine

To convert:

The weight in newtons of an object that has a mass in $\text{kg}$.

Answer to Problem 1P

The weight in newtons of an object that has a mass of $\text{0}\text{.04}\text{kg}$ is $\underset{\_}{\text{0}\text{.392}\text{N}}$.

Explanation of Solution

Given:

The mass of the object is $\text{0}\text{.44}\text{kg}$.

Write the conversion for the quantity.

$0.44\text{kg}$

Write the conversion formula.

$\text{kg}=9.81\text{N}$

Conclusion:

Convert the weight in newtons from $\text{kg}$.

$\begin{array}{c}W=0.04\text{kg}\times \frac{9.81\text{N}}{\text{kg}}\\ =0.392\text{N}\end{array}$

Thus, the weight in newtons of an object is $\underset{\_}{\text{0}\text{.392}\text{N}}$.

To determine

To convert:

The weight in newtons of an object that has a mass in $\text{Mg}$.

Answer to Problem 1P

The weight in newtons of an object that has a mass of $\text{760}\text{Mg}$ is $\underset{\_}{\text{7}\text{.458}\text{MN}}$.

Explanation of Solution

Given:

The mass of the object is $\text{760}\text{Mg}$

Write the conversion for the quantity.

$\text{760}\text{Mg}$

Write the conversion formula.

$\text{Mg}=9806.65\text{N}$

Conclusion:

Convert the weight in newtons from $\text{Mg}$.

$\begin{array}{c}W=760\text{Mg}\times \frac{9806.65\text{N}}{\text{Mg}}\\ =\left(7.458\times {10}^6\text{N}\right)\times \frac{{\text{10}}^{-6}\text{MN}}{\text{N}}\\ =\text{7}\text{.458}\text{MN}\end{array}$

Thus, the weight in newtons of an object is $\underset{\_}{\text{7}\text{.458}\text{MN}}$.