Chapter 16, Problem 1OQ

To determine

The value of pressure.

Answer to Problem 1OQ

Option (d)

Explanation of Solution

Write the expression from the ideal gas law.

$\begin{array}{c}\frac{P_1{V}_1}{T_1}=\frac{P_2{V}_2}{T_2}\\ P_2=\frac{P_1{V}_1{T}_2}{T_1{V}_2}\\ =P_1\left(\frac{V_1}{V_2}\right)\left(\frac{T_2}{T_1}\right)\end{array}$        (I)

In the given problem, final volume is doubles of initial and the final temperature is quadrupled of initial temperature.

Rewrite the expression from equation (I).

$\begin{array}{c}{P}_2=P_1\left(\frac{1}{2}\right)\left(\frac{4}{1}\right)\\ =2P_1\end{array}$

Hence the final pressure will be doubled.

Conclusion:

Since, the final pressure will be doubled. Thus, the correct option is (d).

Since, the final pressure is not remains same. The incorrect option is (a).

Since, final pressure is not decrease by factor 2. The incorrect option is (b).

Since, final pressure is not decrease by factor 4. Thus, the incorrect option is (c).

Since, final pressure is not increases by factor 4. Thus, the incorrect option is (e).