ORGANIC CHEMISTRY (LL) W/WILEYPLUS NEXT
12th Edition
ISBN: 9781119664635
Author: Solomons
Publisher: WILEY
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Question
Chapter 16, Problem 19PP
Interpretation Introduction
Interpretation:
The steps involved in the mechanism for the conversion of benzaldehyde to benzoic acid are to be determined.
Concept Introduction:
>Electrophiles are electron deficient species which has positive or partially positive charge. Lewis acids are electrophiles which accept electron pair.
>Nucleophiles are electron rich species which has negative or partially negative charge. Lewis bases are nucleophiles which donate electron pair.
>Nucleophilic addition reaction is a addition reaction where electron deficient or electrophilic double or triple bond reacts with electron rich species (nucleophile), with disappearance of the double bond and creation of two single bonds.
>In the presence of peroxy acids, the oxygen atom enters the phenylic carbon and leads to the oxidation of the compound.
>Peroxy acid are the acids which contains an acidic
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Retry
Curved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow
the arrows to draw the reactant and missing intermediates involved in this reaction.
Include all lone pairs and charges as appropriate. Ignore inorganic byproducts.
Incorrect, 6 attempts remaining
:0:
Draw the Reactant
H
H3CO
H-
HIO:
Ö-CH3
CH3OH2*
protonation
H.
a
H
(+)
H
Ο
CH3OH2
O:
H3C
protonation
CH3OH
deprotonation
>
CH3OH
nucleophilic addition
H.
HO
0:0
Draw Intermediate
a
X
Can I please get the blank spaces answered/answers?
1. Identify the following alkenes as E or Z
NH₂
Br
2. Draw the structures based on the IUPAC names
(3R,4R)-3-bromo-4-fluoro-
1-hexene
(Z)-4-bromo-2-iodo-3-ethyl-
3-heptene
تر
3. For the following, predict all possible elimination product(s) and circle the major product.
HO
H₂SO4
Heat
80
F4
OH
H2SO4
Heat
어요
F5
F6
1
A
DII
4
F7
F8
F9
%
&
5
6
7
* ∞
8
BAB
3
E
R
T
Y
U
9
F
D
G
H
J
K
O
A
F11
F10
Chapter 16 Solutions
ORGANIC CHEMISTRY (LL) W/WILEYPLUS NEXT
Ch. 16 - PRACTICE PROBLEM 16.1 (a) Give IUPAC substitutive...Ch. 16 - Prob. 2PPCh. 16 - Prob. 3PPCh. 16 - Practice Problem 16.4
Provide the reagents and...Ch. 16 - Prob. 5PPCh. 16 - Prob. 6PPCh. 16 - Prob. 7PPCh. 16 - Prob. 8PPCh. 16 - Prob. 9PPCh. 16 - Practice Problem 16.10
Shown below is the...
Ch. 16 - Prob. 11PPCh. 16 - Practice Problem 16.12
What product would be...Ch. 16 - Prob. 13PPCh. 16 - Practice Problem 16.14
Dihydropyran reacts readily...Ch. 16 - Practice Problem 16.15 Show how you might use...Ch. 16 - Practice Problem 16.16 (a) Show how you might...Ch. 16 - Practice Problem 16.17
In addition to...Ch. 16 - Practice Problem 16.18
Triphenylphosphine can be...Ch. 16 - Prob. 19PPCh. 16 - PRACTICE PROBLEM 16.20
Give the structure of the...Ch. 16 - PRACTICE PROBLEM 16.21 What would be the major...Ch. 16 - Prob. 22PCh. 16 - 16.23 Write structural formulas for the products...Ch. 16 - Give structural formulas for the products formed...Ch. 16 - 16.25 What products would be obtained when...Ch. 16 - Predict the major organic product from each of the...Ch. 16 - 16.27 Predict the major product from each of the...Ch. 16 - 16.28 Predict the major product from each of the...Ch. 16 - Prob. 29PCh. 16 - 16.30 Write detailed mechanisms for each of the...Ch. 16 - Prob. 31PCh. 16 - Prob. 32PCh. 16 - Show how you would convert benzaldehyde into each...Ch. 16 - 16.34 Show how ethyl phenyl ketone could be...Ch. 16 - Show how benzaldehyde could be synthesized from...Ch. 16 - Give structures for compounds AE. Cyclohexanol...Ch. 16 - Prob. 37PCh. 16 - Prob. 38PCh. 16 - Prob. 39PCh. 16 - Prob. 40PCh. 16 - Prob. 41PCh. 16 - Prob. 42PCh. 16 - 16.43 The structure of the sex pheromone...Ch. 16 - Provide reagents that would accomplish each of the...Ch. 16 - Write a detailed mechanism for the following...Ch. 16 - Prob. 46PCh. 16 - Dutch elm disease is caused by a fungus...Ch. 16 - Prob. 48PCh. 16 - Compounds W and X are isomers; they have the...Ch. 16 - Compounds Y and Z are isomers with the molecular...Ch. 16 - Compound A (C9H18O) forms a phenylhydrazone, but...Ch. 16 - Compound B (C8H12O2) shows a strong carbonyl...Ch. 16 - Prob. 53PCh. 16 - Prob. 54PCh. 16 - Prob. 55PCh. 16 - (a) What would be the frequencies of the two...Ch. 16 - Prob. 57PCh. 16 - Prob. LGP
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