ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM
ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM
3rd Edition
ISBN: 9781264452545
Author: SMITH
Publisher: MCG
bartleby

Videos

Question
Book Icon
Chapter 16, Problem 16.69P
Interpretation Introduction

(a)

Interpretation:

The functional groups in the following compound should be labeled as an alcohol, ether, acetal or hemiacetal:

ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 16, Problem 16.69P , additional homework tip  1

Concept Introduction:

The addition of one molecule of alcohol to an aldehyde or ketone results in a hemiacetal. Here, the C=O double bond breaks and single bonds are formed. If the hemiacetal is acyclic, it is not stable. Acyclic hemiacetal reacts with a second alcohol molecule and forms acetal.

ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 16, Problem 16.69P , additional homework tip  2

Even though acetals contain C-O-R bond, acetals are not ethers. Acetals have 2 OR groups attached to a single C atom. But an ether has one O atom which is bonded to 2 carbons.

Alcohols are compounds which have OH groups.

Interpretation Introduction

(b)

Interpretation:

The functional groups in the following compound should be labeled as an alcohol, ether, acetal or hemiacetal:

ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 16, Problem 16.69P , additional homework tip  3

Concept Introduction:

The addition of one molecule of alcohol to an aldehyde or ketone results in a hemiacetal. Here, the C=O double bond breaks and single bonds are formed. If the hemiacetal is acyclic, it is not stable. Acyclic hemiacetal reacts with a second alcohol molecule and forms acetal.

ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM, Chapter 16, Problem 16.69P , additional homework tip  4

Even though acetals contain C-O-R bond, acetals are not ethers. Acetals have 2 OR groups attached to a single C atom. But an ether has one O atom which is bonded to 2 carbons.

Alcohols are compounds which have OH groups.

Blurred answer
Students have asked these similar questions
Synthesis of 1-metilbenzotriazole.
Indicate the formula of the compound, that is the result of the N- alquilación (nucleofílic substitution), in which an additional lateral chain was formed (NH-CH2-COOMe). F3C. CF3 NH NH2 Br о OMe K2CO3, DABCO, DMF
Identify the mechanism through which the following reaction will proceed and draw the major product. Part 1 of 2 Br KOH EtOH Through which mechanism will the reaction proceed? Select the single best answer. E1 E2 neither Part: 1/2 Part 2 of 2 Draw the major product formed as a result of the reaction. Click and drag to start drawing a structure. X

Chapter 16 Solutions

ALEKS 360 ACCESS CARD F/GEN. ORG.CHEM

Ch. 16.5 - What product is formed when each carbonyl compound...Ch. 16.5 - Prob. 16.12PCh. 16.5 - Prob. 16.13PCh. 16.6 - What alcohol is formed when each compound is...Ch. 16.6 - Prob. 16.15PCh. 16.6 - Prob. 16.16PCh. 16.7 - Prob. 16.17PCh. 16.7 - Prob. 16.18PCh. 16.8 - Prob. 16.19PCh. 16.8 - Prob. 16.20PCh. 16.8 - Prob. 16.21PCh. 16.8 - Label the three acetals in solanine, the toxic...Ch. 16.8 - Prob. 16.23PCh. 16.8 - Prob. 16.24PCh. 16 - Prob. 16.25PCh. 16 - Prob. 16.26PCh. 16 - Prob. 16.27PCh. 16 - Prob. 16.28PCh. 16 - Prob. 16.29PCh. 16 - Prob. 16.30PCh. 16 - Prob. 16.31PCh. 16 - Prob. 16.32PCh. 16 - Prob. 16.33PCh. 16 - Prob. 16.34PCh. 16 - Give an acceptable name for each ketone. a. b. c....Ch. 16 - Prob. 16.36PCh. 16 - Prob. 16.37PCh. 16 - Draw the structure corresponding to each name. a....Ch. 16 - Prob. 16.39PCh. 16 - Prob. 16.40PCh. 16 - Prob. 16.41PCh. 16 - Prob. 16.42PCh. 16 - Draw out the structure of benzaldehyde, including...Ch. 16 - Prob. 16.44PCh. 16 - Which compound in each pair has the higher boiling...Ch. 16 - Prob. 16.46PCh. 16 - Prob. 16.47PCh. 16 - Prob. 16.48PCh. 16 - Prob. 16.49PCh. 16 - Prob. 16.50PCh. 16 - Prob. 16.51PCh. 16 - Prob. 16.52PCh. 16 - Prob. 16.53PCh. 16 - Prob. 16.54PCh. 16 - Prob. 16.55PCh. 16 - Consider the following ball-and-stick model....Ch. 16 - Prob. 16.57PCh. 16 - Prob. 16.58PCh. 16 - Prob. 16.59PCh. 16 - Prob. 16.60PCh. 16 - Prob. 16.61PCh. 16 - Prob. 16.62PCh. 16 - Prob. 16.63PCh. 16 - Prob. 16.64PCh. 16 - Prob. 16.65PCh. 16 - Prob. 16.66PCh. 16 - Prob. 16.67PCh. 16 - Prob. 16.68PCh. 16 - Prob. 16.69PCh. 16 - Label the functional group(s) in each compound as...Ch. 16 - Prob. 16.71PCh. 16 - Prob. 16.72PCh. 16 - What acetal is formed when each aldehyde or ketone...Ch. 16 - What acetal is formed when each aldehyde or ketone...Ch. 16 - Prob. 16.75PCh. 16 - Prob. 16.76PCh. 16 - Prob. 16.77PCh. 16 - Prob. 16.78PCh. 16 - Prob. 16.79PCh. 16 - Prob. 16.80PCh. 16 - Prob. 16.81PCh. 16 - Prob. 16.82PCh. 16 - Prob. 16.83PCh. 16 - Answer each question about phenylacetaldehyde,...Ch. 16 - Prob. 16.85PCh. 16 - Prob. 16.86PCh. 16 - Prob. 16.87PCh. 16 - Prob. 16.88PCh. 16 - Three constitutional isomers of molecular formula...Ch. 16 - Identify A—C in the following reaction sequenceCh. 16 - Androsterone is a male sex hormone that controls...Ch. 16 - Prob. 16.92PCh. 16 - Prob. 16.93PCh. 16 - Prob. 16.94PCh. 16 - Prob. 16.95PCh. 16 - Paraldehyde, a hypnotic and sedative once commonly...Ch. 16 - Prob. 16.97PCh. 16 - Prob. 16.98PCh. 16 - Prob. 16.99CPCh. 16 - Prob. 16.100CP
Knowledge Booster
Background pattern image
Chemistry
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, chemistry and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Chemistry for Today: General, Organic, and Bioche...
Chemistry
ISBN:9781305960060
Author:Spencer L. Seager, Michael R. Slabaugh, Maren S. Hansen
Publisher:Cengage Learning
Text book image
Chemistry: Principles and Practice
Chemistry
ISBN:9780534420123
Author:Daniel L. Reger, Scott R. Goode, David W. Ball, Edward Mercer
Publisher:Cengage Learning
Text book image
Introductory Chemistry: An Active Learning Approa...
Chemistry
ISBN:9781305079250
Author:Mark S. Cracolice, Ed Peters
Publisher:Cengage Learning
07 Physical Properties of Organic Compounds; Author: Mindset;https://www.youtube.com/watch?v=UjlSgwq4w6U;License: Standard YouTube License, CC-BY