Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Chapter 16, Problem 16.12P
Design simply supported timber beams (S4S) for the following uniformly distributed line loads and spans:
a. eastern white pine, 5.0 kN/m, 7-m span length
b. southern pine, 6.3 kN/m, 8-m span length
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Students have asked these similar questions
Compute the initial deflection of the beam at midspan under service loads with the following specifications: f'c = 4000 psi, 36-inch height, depth of rebar assumed to be 3 inches less than the height, 16-inch width, 4 #9 bars (tension), Grade 60 rebar, 30' clear spans, service loads of: DL = 0.25k/ft, LL = 1.2k/ft.
The DL does NOT include self-weight of the beam or of the precast concrete deck planks that have a weight of 60 PSF. The beam picks up a tributary width of 12 feet. Also, note that this beam is continuous and is the middle beam of 5 equal spans.
Check the initial deflections against the ACI deflection requirements. Then calculate the long-term deflections and check those against the ACI requirements. For both situations, assume that finish materials will be attached to the beam.
Last: Instead of performing a structural analysis to determine the maximum deflection in the beam, conservatively figure that the maximum deflection will be 60% of what it would have been for a…
2. Design a timber beam (S4S) made of Douglas fir to support the load shown
below.
500 lbs/ft
Ju
12'-0
Analysis and design of continuous beams:
Q1/ Draw the load pattern for the beams B1&B2, If imposed dead
load equal to (2.5 kN/m?), and live load equal to (4.8 kN/m?),are
applied on the floor ,Assume all beams have the same dimensions and
the beams supports as a simply span? Y. = 24 kN / m' ,all columns are
(400*400) mm
the secondary beam in the middle of span B2?
8m
180mm
B1
5m
300mm
200mm
B2
Chapter 16 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 16 - Prob. 16.1PCh. 16 - A simply supported beam is to support a uniformly...Ch. 16 - Rework Problem 16.1 given a load of 1.0 kip/ft and...Ch. 16 - Select the lightest W shape to support a...Ch. 16 - Select the lightest W shape to support a...Ch. 16 - 16.6 A simply supported beam is to span 15 ft. It...Ch. 16 - 16.7 A simply supported beam is to span 24 ft. It...Ch. 16 - 16.8 Design a timber beam of hem-fir (S4S) to...Ch. 16 - Select simply supported timber beams (S4S) for the...Ch. 16 - 16.10 Select a southern pine (S4S) timber beam for...
Ch. 16 - 16.11 Select simply supported hem-fir (S4S) joists...Ch. 16 - Design simply supported timber beams (S4S) for the...Ch. 16 - For the following computer problems, any...Ch. 16 - 16.16 Select the lightest W shape to support a...Ch. 16 - 16.17 Select the lightest W shape for the beam...Ch. 16 - Select the lightest W shape for the cantilever...Ch. 16 - 16.19 Select the lightest W shape to support a...Ch. 16 - 16.20 Select the lightest W shape for the beams...Ch. 16 - 16.21 The structural steel floor system shown is...Ch. 16 - 16.22 The structural steel framing plan shown...Ch. 16 - 16.23 Select the lightest steel wide-flange...Ch. 16 - 16.24 Select the lightest steel wide-flange...Ch. 16 - 16.25 Design the lightest W-shape beams to support...Ch. 16 - 16.26 In Problem 16.18, assume that the 500 lb/ft...Ch. 16 - 16.27 Select a southern pine (S4S) simply...Ch. 16 - 16.28 A redwood beam is to support a uniformly...Ch. 16 - 16.29 A partial plan view for a residential floor...Ch. 16 - 16.30 For the floor framing of Problem 16.29,...Ch. 16 - 16.31 Select a Douglas fir (S4S) beam for the...Ch. 16 - 16.32 Select southern pine (S4S) simply supported...Ch. 16 - 16.33 Rework Problem 16.32 using joists spaced 12...Ch. 16 - 16.34 Select Douglas fir (S4S) simply supported...Ch. 16 - 16.35 Select southern pine (S4S) simply supported...Ch. 16 - 16.36 A 15-ft-span simply supported hem-fir (S4S)...Ch. 16 - 16.37 Select a timber beam (S4S) of Southern pine...Ch. 16 - 16.38 A series of 14-ft-long Douglas fir (S4S)...Ch. 16 - 16.39 A cantilever beam 3 m long is to be made...Ch. 16 - 16.40 Select an eastern white pine (S4S) beam for...
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- Design a timber beam of hem-fir (S4S) to support a uniformly distributed line load of 250 Ib/ft on a simply supported span of 6 ft. Deflection is not to exceed span/300. 1. SIMPLE BEAM: UNIFORMLY DISTRIBUTED LOAD TABLE E.1 U.S. Customary units R=V Nominal Size in. Dressed Size in. A in.2 Wt. Ib/ft I, in.4 S, in. 2 x 4 1} × 3} 5.25 1.46 5.36 3.06 V, x 5 x 7 x 6 8.25 2.29 20.8 7.56 M max (at center) x 8 10.9 3.02 47.6 13.1 x 10 13.9 3.85 98.9 21.4 M, Shear x 11 x 13 x 12 16.9 4.68 178 31.6 Amux (at center). 384EI x 14 19.9 5.52 291 43.9 M max x 16 x 15 22.9 6.35 443 58.2 4, 24 Moment x 18 x 17 25.9 7.17 642 74.5 3 x 4 2} x 3) 8.75 2.42 8.93 5.10 x 5} x 7 TABLE F.1 U.S. Customary units x 6 13.8 3.82 34.7 12.6 x 8 18.1 5.04 79.4 21.9 Allowable Stress" (psi) Modulus of x 10 x9} 23.1 6.42 165 35.6 Elasticity E (ksi) Species Fc F, Fo F, x 12 x 11} 28.1 7.81 297 52.7 x 13 x 15 x 17 Douglas fir 1050 550 625 900 180 1700 x 14 33.1 9.20 485 73.2 Southern pine 1250 410 825 1400 175 1700 x 16 38.1…arrow_forwardA 10 × 10 beam of Douglas fir–larch select structural gradesupports a single concentrated load of 10 kips at the center of the span. Investigate the beam for sheararrow_forwardSelect the lightest wide flange steel section for simple beam of 10 ft span that will carry a uniform load of 10 kips/ft. Use A36 and assume that the beam is supported laterally for its entire length. [Hint: V max = WL/2; M max = L WL²/8]arrow_forward
- need clear ans and solve very very fast in 20 min and thank you | ᴅʏʙᴀʟᴀ ?✨؛arrow_forwardWhat are the W shapes that would be used for unbraced lengths? A W shape is to be used for a uniformly loaded simple beamcarrying a total dead load of 26 kips and a total live load of 26 kips on a36-ft span. Select the lightest weight shape for unbraced lengths of (1) 9 ft, (2) 12 ft, and (3) 18 ft. A W shape is to be used for a uniformly loaded simple beamcarrying a total dead load of 30 kips and a total live load of 40 kips on a 24-ft span. Select the lightest weight shape for unbraced lengths of (1) 6 ft, (2) 8 ft, and (3) 12 ft.arrow_forwardFully show how to get the answer using the table provided, thank you. A W shape is to be used for a uniformly loaded simple beam carrying a total dead load of 27 kips and a total live load of 50 kips on a 45-ft span. Select the lightest weight shape for unbraced lengths of 22.2ft. Use the tables below for Lp, Mp, Lr, and Mr Mp-(Mp-Mr)(Lb-Lp/Lr-Lp)arrow_forward
- 4arrow_forwardFigure 14.20 Full Alternative Text 14.21 A solid rectangular simply supported timber beam 6 in. wide, 20 in. deep, and 10 ft long carries a concentrated load of 16,000 lb at midspan. Use nominal dimensions. a. Compute the maximum horizontal shear stress at the neutral axis. b. Compute the shear stress 4 in. and 8 in. above and below the neutral axis. Neglect the weight of the beam.arrow_forwardA W shape is to be used for a uniformly loaded simple beam carrying a total dead load of 27 kips and a total live load of 50 kips on a 45-ft span. Select the lightest weight shape for unbraced lengths of (2) 15 ft. Fully show how to get the answer using the table provided, thank you.arrow_forward
- I need the answer as soon as possiblearrow_forwardA simply supported beam of length 7m is carrying a uniformly distributed load of 1.25N/m for its entire length. What will be the total load on the beam? Select one: a. 8.75N b. 5.75N c. 87.5m d. 8.75marrow_forwardi need the answer quicklyarrow_forward
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