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Chapter 16 Solutions
Introductory Chemistry: An Active Learning Approach
- A soluble iodide was dissolved in water. Then an excess of silver nitrate, AgNO3, was added to precipitate all of the iodide ion as silver iodide, AgI. If 1.545 g of the soluble iodide gave 2.185 g of silver iodide, how many grams of iodine are in the sample of soluble iodide? What is the mass percentage of iodine, I, in the compound?arrow_forwardA 1.345-g sample of a compound of barium and oxygen was dissolved in hydrochloric acid to give a solution of barium ion, which was then precipitated with an excess of potassium chromate to give 2.012 g of barium chromate, BaCrO4. What is the formula of the compound?arrow_forwardWhat is the molarity of a solution of sodium hydrogen sulfate that is prepared by dissolving 9.21 g NaHSO4 in enough water to form 2.00-L solution? What is the molarity of each ion in the solution?arrow_forward
- Write a balanced equation for the reaction of hydroiodic acid, HI, with calcium hydroxide, Ca(OH)2. Then, write the balanced complete ionic equation and the net ionic equation for this neutralization reaction.arrow_forward1. Sometimes a reaction can fall in more than one category. Into what category (or categories) does the reaction of Ba(OH)2(aq) + H+PO4(aq) fit? acid-base and oxidation-reduction oxidation-reduction acid-base and precipitation precipitationarrow_forwardPotassium permanganate (KMnO4) solutions are used for the determination of Fe2+ in samples of unknown concentration. As a laboratory assistant, you are supposed to prepare 500 mL of a 0.1000 M KMnO4 solution. What mass of KMnO4, in grams, do you need?arrow_forward
- Arsenic acid, H3AsO4, is a poisonous acid that has been used in the treatment of wood to prevent insect damage. Arsenic acid has three acidic protons. Say you take a 25.00-mL sample of arsenic acid and prepare it for titration with NaOH by adding 25.00 mL of water. The complete neutralization of this solution requires the addition of 53.07 mL of 0.6441 M NaOH solution. Write the balanced chemical reaction for the titration, and calculate the molarity of the arsenic acid sample.arrow_forwardWhen 10. L of water is added to 3.0 L of 6.0 M H2SO4, what is the molarity of the resulting solution? Assume the volumes are additive.arrow_forwardTwenty-five mL of a 0.388 M solution of Na2SO4 is mixed with 35.3 mL of 0.229 M Na2SO4. What is the molarity of the resulting solution? Assume that the volumes are additive.arrow_forward
- Vitamin C is ascorbic acid, HC6H7O6, which can be titrated with a strong base. HC6H7O6(aq) + NaOH(aq) NaC6H7O6(aq) + H2O() A student dissolved a 500.0-mg vitamin C tablet in 200.0 mL water and then titrated it with 0.1250-M NaOH. It required 21.30 mL of the base to reach the equivalence point. Calculate the mass percentage of the tablet that is impurity.arrow_forwardChlorisondamine chloride (C14H20Cl6N2) is a drug used in the treatment of hypertension. A 1.28-g sample of a medication containing the drug was treated to destroy the organic material and to release all the chlorine as chloride ion. When the filtered solution containing chloride ion was treated with an excess of silver nitrate, 0.104 g silver chloride was recovered. Calculate the mass percent of chlorisondamine chloride in the medication, assuming the drug is the only source of chloride.arrow_forwardA 0.608-g sample of fertilizer contained nitrogen as ammonium sulfate, (NH4)2SO4. It was analyzed for nitrogen by heating with sodium hydroxide. (NH4)2SO4(s)+2NaOH(aq)Na2SO4(aq)+2H2O(l)+2NH3(g) The ammonia was collected in 46.3 mL of 0.213 M HCl (hydrochloric acid), with which it reacted. NH3(g)+HCl(aq)NH4Cl(aq) This solution was titrated for excess hydrochloric acid with 44.3 mL of 0.128 M NaOH. NaOH(aq)+HCl(aq)NaCl(aq)+H2O(l) What is the percentage of nitrogen in the fertilizer?arrow_forward
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