Introductory Chemistry: An Active Learning Approach
Introductory Chemistry: An Active Learning Approach
6th Edition
ISBN: 9781305079250
Author: Mark S. Cracolice, Ed Peters
Publisher: Cengage Learning
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Chapter 16, Problem 9PE
Interpretation Introduction

(a)

Interpretation:

The equivalent mass of HI in the reaction Ca(OH)2+2HICaI2+2H2O is to be determined.

Concept introduction:

In a chemical reaction, one equivalent of an acid is defined as the quantity that yields one mole of hydrogen ion. One equivalent of base is defined as the quantity that reacts with one mole of hydrogen ion. The number of grams per equivalent is called equivalent mass. The unit of equivalent mass is g/eq.

Expert Solution
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Answer to Problem 9PE

The equivalent mass of HI in the given reaction Ca(OH)2+2HICaI2+2H2O is 128g/eq.

Explanation of Solution

The given chemical reaction is shown below.

Ca(OH)2+2HICaI2+2H2O

In the above reaction each mole of HI gives one mole of hydrogen ion and one mole of hydrogen ion is one equivalent of acid. The equivalent mass is calculated by dividing the molar mass by equivalents per mole.

Therefore,

Equivalent mass ofHI=MolarmassofHIequivalentspermoleofHI…(1)

The molar mass of HI is calculated by using the formula as given below.

MolarmassofHI=(Molarmassofhydrogen+Molarmassofiodine)…(2)

The molar mass of hydrogen is 1g/mol.

The molar mass of iodine is 127g/mol.

Substitute the values of molar masses of hydrogen and iodine in equation (2).

MolarmassofHI=(1g/mol+127g/mol)=128g/mol

Substitute the values of molar mass and equivalents per mole of HI in equation (1).

Equivalent mass ofHI=128g/mol1eq/mol=128g/eq

Therefore, the equivalent mass of HI in the given reaction is 128g/eq.

Conclusion

The equivalent mass of HI in the given reaction is 128g/eq.

Interpretation Introduction

(b)

Interpretation:

The equivalent mass of H3C9H8NO3 in the reaction NaOH+H3C9H8NO3NaH2C9H8NO3+H2O is to be determined.

Concept introduction:

In a chemical reaction one equivalent of an acid is defined as the quantity that yields one mole of hydrogen ion. One equivalent of base is defined as the quantity that reacts with one mole of hydrogen ion. The number of grams per equivalent is called equivalent mass. The unit of equivalent mass is g/eq.

Expert Solution
Check Mark

Answer to Problem 9PE

The equivalent mass of H3C9H8NO3 in the given reaction NaOH+H3C9H8NO3NaH2C9H8NO3+H2O is 181g/eq.

Explanation of Solution

The chemical reaction is given below.

NaOH+H3C9H8NO3NaH2C9H8NO3+H2O

In the above reaction one mole of hydroxide ion reacts with one mole of hydrogen ion of the molecule H3C9H8NO3, and results in the formation of one mole of water molecule. Since, one mole of hydrogen ion is one equivalent of acid. Therefore, there is one eq/mol of acid H3C9H8NO3. The equivalent mass is calculated by dividing the molar mass by equivalents per mole.

Therefore,

Equivalent mass ofH3C9H8NO3=MolarmassofH3C9H8NO3equivalentspermoleofH3C9H8NO3…(1)

The molar mass of H3C9H8NO3 is calculated by using the formula as given below.

MolarmassofH3C9H8NO3=(11×Molarmassofhydrogen+Molarmassofnitrogen+9×Molarmassofcarbon+3×Molarmassofoxygen)…(2)

The molar mass of hydrogen is 1g/mol.

The molar mass of carbon is 12g/mol.

The molar mass of nitrogen is 14g/mol.

The molar mass of oxygen is 16g/mol.

Substitute the values of molar masses of hydrogen, Carbon, nitrogen and oxygen in equation (2).

MolarmassofH3C9H8NO3=( 11×1g/mol+14g/mol+9×12g/mol+3×16g/mol)=(11+14+108+48)g/mol=181g/mol

Substitute the values of molar mass and equivalents per mole of H3C9H8NO3 in equation (1).

Equivalent mass ofH3C9H8NO3=181g/mol1eq/mol=181g/eq

Therefore, the equivalent mass of H3C9H8NO3 in the given reaction is 181g/eq.

Conclusion

The equivalent mass of H3C9H8NO3 in the given reaction is 181g/eq.

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Chapter 16 Solutions

Introductory Chemistry: An Active Learning Approach

Ch. 16 - Prob. 11ECh. 16 - Prob. 12ECh. 16 - Prob. 13ECh. 16 - Prob. 14ECh. 16 - Prob. 15ECh. 16 - What does it mean to say that a solute particle is...Ch. 16 - Prob. 17ECh. 16 - Prob. 18ECh. 16 - Describe the changes that occur between the time...Ch. 16 - Prob. 20ECh. 16 - Prob. 21ECh. 16 - Prob. 22ECh. 16 - Prob. 23ECh. 16 - Prob. 24ECh. 16 - Prob. 25ECh. 16 - Prob. 26ECh. 16 - Prob. 27ECh. 16 - Which of the following solutes do you expect to be...Ch. 16 - Prob. 29ECh. 16 - Prob. 30ECh. 16 - Prob. 31ECh. 16 - Prob. 32ECh. 16 - Prob. 33ECh. 16 - Prob. 34ECh. 16 - Prob. 35ECh. 16 - Prob. 36ECh. 16 - Prob. 37ECh. 16 - A student weighs out a 4.80-g sample of aluminum...Ch. 16 - Prob. 39ECh. 16 - Prob. 40ECh. 16 - Prob. 41ECh. 16 - Prob. 42ECh. 16 - Potassium hydroxide is used in making liquid soap....Ch. 16 - You need to make an aqueous solution of 0.123M...Ch. 16 - What volume of concentrated sulfuric acid, which...Ch. 16 - Prob. 46ECh. 16 - Prob. 47ECh. 16 - Prob. 48ECh. 16 - Prob. 49ECh. 16 - Prob. 50ECh. 16 - Despite its intense purple color, potassium...Ch. 16 - Prob. 52ECh. 16 - 53. The density of 3.30M potassium nitrate is...Ch. 16 - Prob. 54ECh. 16 - Prob. 55ECh. 16 - Prob. 56ECh. 16 - Prob. 57ECh. 16 - Prob. 58ECh. 16 - Prob. 59ECh. 16 - Prob. 60ECh. 16 - Prob. 61ECh. 16 - Prob. 62ECh. 16 - Prob. 63ECh. 16 - Prob. 64ECh. 16 - Prob. 65ECh. 16 - Prob. 66ECh. 16 - Prob. 67ECh. 16 - Prob. 68ECh. 16 - What are the equivalent mass of Cu(OH)2 and...Ch. 16 - Prob. 70ECh. 16 - Prob. 71ECh. 16 - Prob. 72ECh. 16 - Prob. 73ECh. 16 - Prob. 74ECh. 16 - Prob. 75ECh. 16 - Prob. 76ECh. 16 - Prob. 77ECh. 16 - Prob. 78ECh. 16 - Prob. 79ECh. 16 - Prob. 80ECh. 16 - Prob. 81ECh. 16 - Prob. 82ECh. 16 - What is the molarity of the acetic acid solution...Ch. 16 - Prob. 84ECh. 16 - Prob. 85ECh. 16 - Prob. 86ECh. 16 - Prob. 87ECh. 16 - Prob. 88ECh. 16 - Prob. 89ECh. 16 - Prob. 90ECh. 16 - Prob. 91ECh. 16 - Prob. 92ECh. 16 - Calculate the mass of calcium phosphate that will...Ch. 16 - How many milliliters of 0.464M nitric acid...Ch. 16 - Prob. 95ECh. 16 - Prob. 96ECh. 16 - What volume of 0.842M sodium hydroxide solution...Ch. 16 - Prob. 98ECh. 16 - The equation for a reaction by which a solution of...Ch. 16 - Potassium hydrogen phthalate is a solid,...Ch. 16 - Prob. 101ECh. 16 - Oxalic acid dihydrate is a solid, diprotic acid...Ch. 16 - A student finds that 37.80mL of a 0.4052MNaHCO3...Ch. 16 - Prob. 104ECh. 16 - Prob. 105ECh. 16 - Prob. 106ECh. 16 - Prob. 107ECh. 16 - Prob. 108ECh. 16 - Prob. 109ECh. 16 - Prob. 110ECh. 16 - Prob. 111ECh. 16 - Prob. 112ECh. 16 - Prob. 113ECh. 16 - Prob. 114ECh. 16 - Prob. 115ECh. 16 - Prob. 116ECh. 16 - Prob. 117ECh. 16 - The specific gravity of a solution of KCl is...Ch. 16 - A student dissolves 27.2g of aniline, C6H5NH2, in...Ch. 16 - Prob. 120ECh. 16 - Prob. 121ECh. 16 - Prob. 122ECh. 16 - Prob. 123ECh. 16 - Prob. 124ECh. 16 - Prob. 125ECh. 16 - Prob. 126ECh. 16 - When 12.4g of an unknown solute is dissolved in...Ch. 16 - Prob. 128ECh. 16 - Prob. 129ECh. 16 - When 19.77g of glucose, C6H12O6(180.2g/mol), is...Ch. 16 - Prob. 131ECh. 16 - Prob. 132ECh. 16 - When you heat water on a stove, small bubbles...Ch. 16 - Antifreeze is put into the water in an automobile...Ch. 16 - Prob. 135ECh. 16 - Prob. 136ECh. 16 - Prob. 137ECh. 16 - Prob. 138ECh. 16 - Prob. 139ECh. 16 - Prob. 140ECh. 16 - The density of 18.0%HCl is 1.09g/mL. Calculate its...Ch. 16 - Prob. 142ECh. 16 - Prob. 143ECh. 16 - Prob. 144ECh. 16 - Prob. 145ECh. 16 - A student adds 25.0mL of 0.350M sodium hydroxide...Ch. 16 - Prob. 147ECh. 16 - An analytical procedure for finding the chloride...Ch. 16 - Prob. 149ECh. 16 - Prob. 150ECh. 16 - Prob. 151ECh. 16 - A chemist combines 60.0mL of 0.322M potassium...Ch. 16 - A solution is defined as a homogeneous mixture. Is...Ch. 16 - Prob. 154ECh. 16 - Prob. 16.1TCCh. 16 - 0.100gof A is dissolved in 1.00 103mL of water,...Ch. 16 - Prob. 16.3TCCh. 16 - If you are given the structural formulas of two...Ch. 16 - Prob. 1CLECh. 16 - Prob. 2CLECh. 16 - Write a brief description of the relationships...Ch. 16 - Prob. 4CLECh. 16 - Prob. 5CLECh. 16 - Write a brief description of the relationships...Ch. 16 - Prob. 1PECh. 16 - What mass of sodium chloride and what volume of...Ch. 16 - Prob. 3PECh. 16 - Prob. 4PECh. 16 - Prob. 5PECh. 16 - Prob. 6PECh. 16 - Prob. 7PECh. 16 - Determine the number of equivalents of acid and...Ch. 16 - Prob. 9PECh. 16 - Prob. 10PECh. 16 - Prob. 11PECh. 16 - Prob. 12PECh. 16 - Prob. 13PECh. 16 - Prob. 14PECh. 16 - Prob. 15PECh. 16 - Prob. 16PECh. 16 - What volume of 0.105M lithium nitrate must be...Ch. 16 - Prob. 18PECh. 16 - Prob. 19PECh. 16 - Prob. 20PECh. 16 - Prob. 21PECh. 16 - Prob. 22PECh. 16 - The freezing point of cyclohexane is 6.50C, and...
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