Concept explainers
To find:The event.
Answer to Problem 6WE
The event is {(2,1),(3,1),(3,2),(4,1),(4,2),(4,3),(5,1),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3),(6,4),(6,5)}.
Explanation of Solution
Given:
The number showing on the road die is greater than the number showing on the blue die.
Calculation:
In the experiment, two dice thrown one is red and the other is blue.
The possible numbers on the dice are 1, 2, 3, 4, 5, 6.
There are 36 possible combinations there, out of which the number showing on the road die is greater than the number showing on the blue die, the required event is
{(2,1),(3,1),(3,2),(4,1),(4,2),(4,3),(5,1),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3),(6,4),(6,5)}
Thus, the event is {(2,1),(3,1),(3,2),(4,1),(4,2),(4,3),(5,1),(5,2),(5,3),(5,4),(6,1),(6,2),(6,3),(6,4),(6,5)}.
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Algebra and Trigonometry: Structure and Method, Book 2
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