(a)
Interpretation:
The structure of ( R )-alanine or enantiomer of ( S )-alanine needs to be drawn.
Concept introduction:
The R and S notational system is used for the organic compounds with a chiral center. As alanine has a chiral center, this classification can be used.
In this classification, first thing is to assign priorities for each bonded group surrounding the stereocenter. The priorities are assigned by considering the atomic weight of the atom, which is directly connected to the chiral center, in each bonded group. When 2 atomic groups are having the same first atom, the
Then the lowest priority group should be located in a backward direction, out of the plane of the page. Usually this lowest priority group is denoted with a dashed line.
Then the remaining 1, 2, 3 priorities should be directed from lowest to highest. A counterclockwise direction is S configuration. A clockwise direction is R.
(b)
Interpretation:
The melting point of (R)-alanine needs to be determined.
Concept introduction:
Enantiomers are a part of stereoisomers. In chemistry, enantiomers are two stereoisomers that are mirror images of each other. As they are mirror images, they are non-superimposable which means not identical.
(c)
Interpretation:
The specific rotation of (R)-alanine needs to be determined.
Concept introduction:
Depending on the rotating side of the plane of polarized light a classification exits among optical isomers. If a molecule rotates the plane of polarized light to the right [clockwise, or (+)], it is classified as dextrorotatory (d) compound. In contrast, if a molecule rotates the plane of polarized light to the left [anti-clockwise, or (-)], it is classified as levorotatory (l) compound.

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Chapter 15 Solutions
GENERAL,ORGANIC, & BIOLOGICAL CHEM-ACCES
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- 20.17 Predict the structure of the major product formed by 1,2-addition of HBr to 3-methylenecyclohexene. 3-Methylenecyclohexene 20.18 Predict the major product formed by 1,4-addition of HBr to 3-methylenecyclohexene.arrow_forward+ Draw a vicinal alkyl bromide that would produce the following alkene in an E2 elimination. Use a dash or wedge bond to indicate stereochemistry on asymmetric centers, where applicable. Ignore any inorganic byproducts. Br Drawing Strong Base H Q Atoms, Bonds Charges and Rings Draw or tap a new bond to see suggestions. Remove Done 語 Reset Undo + Drag To Panarrow_forwardDraw a vicinal alkyl bromide that would produce the following alkene in an E2 elimination. Use a dash or wedge bond to indicate stereochemistry on asymmetric centers, where applicable. Ignore any inorganic byproducts. + Drawing Į Strong Base H Br Q Atoms, Bonds and Rings Charges Draw or tap a new bond to see suggestions. Undo Reset 謂 Remove Done Drag To Pan +arrow_forward
- Draw the product of the E2 reaction shown below. Include the correct stereochemistry. Ignore any inorganic byproducts. + Br CH3 Q Strong Base Drawing Atoms, Bonds and Rings Charges Undo Reset H "Br H N Br. Remove Done .N. Drag To Panarrow_forwardCurved arrows are used to illustrate the flow of electrons. Use the reaction conditions provided and follow the curved arrows to draw the product of this elementary step in an elimination mechanism. Include all lone pairs and charges as appropriate. Ignore stereochemistry. Ignore byproducts. + Br: .. 8 0.01 M NaOH heat Drawing Q Atoms, Bonds and Rings Charges and Lone Pairs Draw or tap a new bond to see suggestions. Undo Reset Remove Done + Drag To Panarrow_forward+ Draw the product of the E2 reaction shown below. Include the correct stereochemistry. Ignore any inorganic byproducts. Ph CH2CH3 H H3C H Br DBN [૪] Drawing Atoms, Bonds and Rings H | OH Charges ―00 H. C | Undo Reset Br I Remove Done Drag To Pan +arrow_forward
- Reaction A Now the production A Œ In the product of reaction i 12 Dear the product of actionarrow_forwardMacmillan Learnin When an unknown amine reacts with an unknown acid chloride, an amide with a molecular mass of 163 g/mol (M* = 163 m/z) is formed. In the infrared spectrum, important absorptions appear at 1661, 750 and 690 cm-1. The 13C NMR and DEPT spectra are provided. Draw the structure of the product as the resonance contributor lacking any formal charges. 13C NMR DEPT 90 200 160 120 80 40 0 200 160 120 80 DEPT 135 200 160 120 80 40 0 Draw the unknown amide. 40 40 0arrow_forwardDraw the major product karmed when I reach with the epoxide. Use walge dah bonds, including hydrogen al alcach genic center, to show the chemistry of the product Beeldraw any hydrogen akams on coxygen where applicablearrow_forward
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