Programmable Logic Controllers
5th Edition
ISBN: 9780073373843
Author: Frank D. Petruzella
Publisher: McGraw-Hill Education
expand_more
expand_more
format_list_bulleted
Question
Chapter 15.4, Problem 5RQ
Program Plan Intro
a.
Counter:
- It is similar to timer concept.
- It is used to count the changes that are produced by the state of an outside trigger signal.
- It is a programmable logic controller (PLC) instruction that either counting up or counting down an integer value when produced by the change of a bit from “0” to “1” or “false” to “true”.
- In PLC, counter contains three types.
- Up counters.
- Down counters.
- Up/Down counters.
Explanation of Solution
b.
Counter bits set for DN:
- DN is represented as count-up done bit.
- This status bit returns the result as a Boolean value...
Explanation of Solution
c.
Counter bits set for CD:
- CD is represented as count-down enable bit.
- This status bit returns the result as a Boolean value...
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Send me the lexer and parser
Here is my code please draw a transition diagram and nfa on paper
public class Lexer
{
private static final char EOF = 0;
private static final int BUFFER_SIZE = 10;
private Parser yyparser; // parent parser object
private java.io.Reader reader; // input stream
public int lineno; // line number
public int column; // column
// Double buffering implementation
private char[] buffer1;
private char[] buffer2;
private boolean usingBuffer1;
private int currentPos;
private int bufferLength;
private boolean endReached;
// Keywords
private static final String[] keywords = {
"int", "print", "if", "else", "while", "void"
};
public Lexer(java.io.Reader reader, Parser yyparser) throws Exception
{
this.reader = reader;
this.yyparser = yyparser;
this.lineno = 1;
this.column = 0;
// Initialize double buffering
buffer1 = new char[BUFFER_SIZE];
buffer2 = new char[BUFFER_SIZE];
usingBuffer1 = true;
currentPos = 0;
bufferLength = 0;
endReached = false;
// Initial buffer fill
fillBuffer();
}
private…
If integer x is divisible by 3, can you prove that ceil(x/2) + floor(x/6) = floor(x/2) + ceil(x/6)
Chapter 15 Solutions
Programmable Logic Controllers
Ch. 15.1 - Prob. 1RQCh. 15.1 - Prob. 2RQCh. 15.1 - Prob. 3RQCh. 15.1 - Prob. 4RQCh. 15.1 - Prob. 5RQCh. 15.1 - Prob. 6RQCh. 15.1 - Prob. 7RQCh. 15.1 - Prob. 8RQCh. 15.1 - Prob. 9RQCh. 15.1 - Prob. 10RQ
Ch. 15.1 - Prob. 11RQCh. 15.1 - Compare the accessibility of program scope and...Ch. 15.1 - Prob. 13RQCh. 15.1 - What is the difference between a produced tag and...Ch. 15.1 - Prob. 15RQCh. 15.1 - State the data type used for each of the...Ch. 15.1 - Describe the make-up of a predefined structure.Ch. 15.1 - Describe the make-up of a module-defined...Ch. 15.1 - Describe the make-up of a user-defined structure.Ch. 15.1 - Prob. 20RQCh. 15.1 - Prob. 21RQCh. 15.1 - Prob. 22RQCh. 15.1 - Prob. 23RQCh. 15.2 - Prob. 1RQCh. 15.2 - Prob. 2RQCh. 15.2 - Prob. 3RQCh. 15.2 - Prob. 4RQCh. 15.2 - Prob. 5RQCh. 15.2 - Prob. 6RQCh. 15.2 - Prob. 7RQCh. 15.2 - Prob. 8RQCh. 15.2 - Prob. 9RQCh. 15.2 - Prob. 10RQCh. 15.2 - Prob. 11RQCh. 15.2 - Extend control of the original ControlLogix...Ch. 15.2 - Prob. 3PCh. 15.3 - Prob. 1RQCh. 15.3 - Prob. 2RQCh. 15.3 - Prob. 3RQCh. 15.3 - Prob. 4RQCh. 15.3 - Prob. 5RQCh. 15.3 - Prob. 6RQCh. 15.3 - Prob. 7RQCh. 15.3 - Prob. 8RQCh. 15.3 - Prob. 9RQCh. 15.3 - Prob. 10RQCh. 15.3 - Prob. 11RQCh. 15.3 - Prob. 12RQCh. 15.3 - Modify the original CLX ten-second TON timer...Ch. 15.3 - Prob. 2PCh. 15.3 - Prob. 3PCh. 15.3 - Prob. 4PCh. 15.3 - Prob. 5PCh. 15.3 - Prob. 6PCh. 15.4 - Prob. 1RQCh. 15.4 - Prob. 2RQCh. 15.4 - Prob. 3RQCh. 15.4 - Prob. 4RQCh. 15.4 - Prob. 5RQCh. 15.4 - Prob. 6RQCh. 15.4 - Prob. 7RQCh. 15.4 - Prob. 1PCh. 15.4 - Prob. 2PCh. 15.5 - Prob. 1RQCh. 15.5 - Prob. 2RQCh. 15.5 - Prob. 3RQCh. 15.5 - Prob. 4RQCh. 15.5 - Prob. 5RQCh. 15.5 - Construct a ControlLogix ladder rung with compare...Ch. 15.5 - Prob. 2PCh. 15.5 - A single pole switch is used in place of the two...Ch. 15.6 - Prob. 1RQCh. 15.6 - Name the four basic elements of an FBD.Ch. 15.6 - Prob. 3RQCh. 15.6 - Prob. 4RQCh. 15.6 - Prob. 5RQCh. 15.6 - Prob. 6RQCh. 15.6 - Prob. 7RQCh. 15.6 - Prob. 8RQCh. 15.6 - Prob. 9RQCh. 15.6 - Prob. 10RQCh. 15.6 - Prob. 11RQCh. 15.6 - How is a function block feedback loop created?Ch. 15.6 - Prob. 13RQCh. 15.6 - Prob. 14RQCh. 15.6 - Prob. 1PCh. 15.6 - Prob. 2PCh. 15.6 - Prob. 3PCh. 15.6 - Prob. 4PCh. 15.6 - Prob. 5P
Knowledge Booster
Similar questions
- Draw the NFA for thisarrow_forwardWhat are three examples each of closed-ended, open-ended, and range-of-response questions? thank youarrow_forwardCreate 2 charts using this data. One without using wind speed and one including max speed in mph. Write a Report and a short report explaining your visualizations and design decisions. Include the following: Lead Story: Identify the key story or insight based on your visualizations. Shaffer’s 4C Framework: Describe how you applied Shaffer’s 4C principles in the design of your charts. External Data Integration: Explain the second data and how you integrated it with the Halloween dataset. Compare the two datasets. Attach screenshots of the two charts (Bar graph or Line graph) The Shaffer 4 C’s of Data Visualization Clear - easily seen; sharply defined• who's the audience? what's the message? clarity more important than aestheticsClean - thorough; complete; unadulterated, labels, axis, gridlines, formatting, right chart type, colorchoice, etc.Concise - brief but comprehensive. not minimalist but not verboseCaptivating - to attract and hold by beauty or excellence does it capture…arrow_forward
- How can I resolve the following issue?arrow_forwardI need help to resolve, thank you.arrow_forwardLet the user choose encryption or decryption. For encryption, let user input the key in Hexadecimal number, the plain text in Hexadecimal number, output the ciphertext (in hexadecimal numbers). For decryption, let user input the key in Hexadecimal number, the ciphertext (in hexadecimal numbers), output the decrypted message (Hexadecimal number). Both encryption and decryption should output the different operation results for each round like the following: For example: Round 1: E(R0) = ...... (Hex or Binary) K1 = …… E(Ro) xor K1 = S-box outputs = …… f(Ro1, K1) = ….. L2 =R1 =……. La = Ra Round 2: .....• No Encryption/Decryption libraries or functions provided by the third party are allowed. Submit your program codes to Moodle with the notes of how to compile and run your program.arrow_forward
- When the given integer variable numberOfPackages is: greater than 12, output "Needs more than one box". between 5 inclusive and 12 inclusive, output "Large box". between 0 exclusive and 4 inclusive, output "Small box". less than or equal to 0, output "Invalid input". End with a newline.arrow_forwardsummarize in a short paragraph how to Advance Incident Response and Automation in ML home based security systemsarrow_forward1.[30 pts] Computers generate color pictures on a video screen or liquid crystal display by mixing three different colors of light: red, green, and blue. Imagine a simple scheme, with three different lights, each of which can be turned on or off, projecting onto a glass screen: We can create eight different colors based on the absence (0) or presence (1) of light sources R,G and B: R G B Color 0 0 0 Black 0 0 1 Blue 0 1 0 Green 0 1 1 Cyan 1 0 0 Red 1 0 1 Magenta 1 1 1 0 Yellow 1 White 1 Each of these colors can be represented as a bit vector of length 3, and we can apply Boolean operations to them. a. The complement of a color is formed by turning off the lights that are on and turning on the lights that are off. What would be the complement of each of the eight colors listed above? b. Describe the effect of applying Boolean operations on the following colors: Λ 1. Red(100) ^ Magenta(101)= Blue(001) 2. Bue(001) | Green(010)= 3. Yellow(100) & Cyan(011)= 2.[30 pts] Perform the following…arrow_forward
- D. S. Malik, Data Structures Using C++, 2nd Edition, 2010arrow_forwardMethods (Ch6) - Review 1. (The MyRoot method) Below is a manual implementation of the Math.sqrt() method in Java. There are two methods, method #1 which calculates the square root for positive integers, and method #2, which calculates the square root of positive doubles (also works for integers). public class SquareRoot { public static void main(String[] args) { } // implement a loop of your choice here // Method that calculates the square root of integer variables public static double myRoot(int number) { double root; root=number/2; double root old; do { root old root; root (root_old+number/root_old)/2; } while (Math.abs(root_old-root)>1.8E-6); return root; } // Method that calculates the square root of double variables public static double myRoot(double number) { double root; root number/2; double root_old; do { root old root; root (root_old+number/root_old)/2; while (Math.abs (root_old-root)>1.0E-6); return root; } } Program-it-Yourself: In the main method, create a program that…arrow_forwardI would like to know the main features about the following 3 key concepts:1. Backup Domain Controller (BDC)2. Access Control List (ACL)3. Dynamic Memoryarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Systems ArchitectureComputer ScienceISBN:9781305080195Author:Stephen D. BurdPublisher:Cengage Learning
A+ Guide to Hardware (Standalone Book) (MindTap C...Computer ScienceISBN:9781305266452Author:Jean AndrewsPublisher:Cengage Learning
A+ Guide To It Technical SupportComputer ScienceISBN:9780357108291Author:ANDREWS, Jean.Publisher:Cengage,
Programming Logic & Design ComprehensiveComputer ScienceISBN:9781337669405Author:FARRELLPublisher:Cengage
Enhanced Discovering Computers 2017 (Shelly Cashm...Computer ScienceISBN:9781305657458Author:Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Mark Frydenberg, Jennifer T. CampbellPublisher:Cengage Learning
Comptia A+ Core 1 Exam: Guide To Computing Infras...Computer ScienceISBN:9780357108376Author:Jean Andrews, Joy Dark, Jill WestPublisher:Cengage Learning
Systems Architecture
Computer Science
ISBN:9781305080195
Author:Stephen D. Burd
Publisher:Cengage Learning
A+ Guide to Hardware (Standalone Book) (MindTap C...
Computer Science
ISBN:9781305266452
Author:Jean Andrews
Publisher:Cengage Learning
A+ Guide To It Technical Support
Computer Science
ISBN:9780357108291
Author:ANDREWS, Jean.
Publisher:Cengage,
Programming Logic & Design Comprehensive
Computer Science
ISBN:9781337669405
Author:FARRELL
Publisher:Cengage
Enhanced Discovering Computers 2017 (Shelly Cashm...
Computer Science
ISBN:9781305657458
Author:Misty E. Vermaat, Susan L. Sebok, Steven M. Freund, Mark Frydenberg, Jennifer T. Campbell
Publisher:Cengage Learning
Comptia A+ Core 1 Exam: Guide To Computing Infras...
Computer Science
ISBN:9780357108376
Author:Jean Andrews, Joy Dark, Jill West
Publisher:Cengage Learning