Basic Technical Mathematics
11th Edition
ISBN: 9780134437705
Author: Washington
Publisher: PEARSON
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Chapter 15.3, Problem 16E
To determine
The roots of the equation without the help of calculator.
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4. (5 pts) Conduct a chi-square contingency test (test of independence) to assess whether
there is an association between the behavior of the elderly person (did not stop to talk,
did stop to talk) and their likelihood of falling. Below, please state your null and
alternative hypotheses, calculate your expected values and write them in the table,
compute the test statistic, test the null by comparing your test statistic to the critical
value in Table A (p. 713-714) of your textbook and/or estimating the P-value, and
provide your conclusions in written form. Make sure to show your work.
Did not stop walking to talk
Stopped walking to talk
Suffered a fall
12
11
Totals
23
Did not suffer a fall | 2
Totals
35
37
14
46
60
T
Question 2
Parts manufactured by an injection molding process are subjected to a compressive strength test. Twenty samples
of five parts each are collected, and the compressive strengths (in psi) are shown in Table 2.
Table 2: Strength Data for Question 2
Sample Number
x1
x2
23
x4
x5
R
1
83.0
2
88.6 78.3 78.8
3
85.7
75.8
84.3
81.2 78.7 75.7 77.0
71.0 84.2
81.0
79.1
7.3
80.2 17.6
75.2
80.4
10.4
4
80.8
74.4
82.5
74.1 75.7 77.5
8.4
5
83.4
78.4
82.6 78.2
78.9
80.3
5.2
File Preview
6
75.3
79.9
87.3 89.7
81.8
82.8
14.5
7
74.5
78.0 80.8
73.4
79.7
77.3
7.4
8
79.2
84.4 81.5 86.0
74.5
81.1
11.4
9
80.5
86.2
76.2 64.1
80.2
81.4
9.9
10
75.7
75.2
71.1 82.1
74.3
75.7
10.9
11
80.0 81.5
78.4 73.8
78.1
78.4
7.7
12
80.6
81.8
79.3
73.8
81.7 79.4
8.0
13
82.7
81.3
79.1
82.0 79.5 80.9
3.6
14
79.2
74.9
78.6 77.7
75.3
77.1
4.3
15
85.5 82.1
82.8 73.4
71.7
79.1
13.8
16
78.8 79.6
80.2 79.1
80.8 79.7
2.0
17
82.1
78.2
18
84.5
76.9
75.5
83.5 81.2
19
79.0 77.8
20
84.5
73.1
78.2 82.1
79.2 81.1 7.6
81.2 84.4 81.6 80.8…
Name:
Lab Time:
Quiz 7 & 8 (Take Home) - due Wednesday, Feb. 26
Contingency Analysis (Ch. 9)
In lab 5, part 3, you will create a mosaic plot and conducted a chi-square contingency test to
evaluate whether elderly patients who did not stop walking to talk (vs. those who did stop)
were more likely to suffer a fall in the next six months. I have tabulated the data below.
Answer the questions below. Please show your calculations on this or a separate sheet.
Did not stop walking to talk
Stopped walking to talk Totals
Suffered a fall
Did not suffer a fall
Totals
12
11
23
2
35
37
14
14
46
60
Quiz 7:
1. (2 pts) Compute the odds of falling for each group. Compute the odds ratio for those
who did not stop walking vs. those who did stop walking. Interpret your result verbally.
Chapter 15 Solutions
Basic Technical Mathematics
Ch. 15.1 - Use the factor theorem to determine whether t − 2...Ch. 15.1 - Prob. 2PECh. 15.1 - Prob. 3PECh. 15.1 - Prob. 4PECh. 15.1 - Prob. 1ECh. 15.1 - Prob. 2ECh. 15.1 - In Exercises 1–4, make the given changes in the...Ch. 15.1 - Prob. 4ECh. 15.1 - Prob. 5ECh. 15.1 - Prob. 6E
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