Explanation Result used: Complex Conjugate Root Theorem: “If the coefficients of the equation f ( x ) = 0 and real and a + b j ( b ≠ 0 ) is a complex root, then its conjugate, a − b j , is also a root”. Description: Note that, the third degree polynomial function has three zeros

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Author: Washington

Publisher: PEARSON

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Chapter 15.2, Problem 27E

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To explain: The reason behind that a third-degree polynomial function with real coefficient cannot have zeros of 1, 2 and j.

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Chapter 15.2, Problem 26E

Chapter 15.2, Problem 28E

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a. f(x) = 3 — — x 13. Which of the following has a horizontal asymptote at y = 0 ? 1 - X c. f(x) = 1 b. f(x) == X+2 1 = d. all of the above 17x+4 1 14. What is true about the function f(x)= as x∞o? x+4 a. f(x)0 from above b. f(x)0 from below c. f(x) → 1/1/1 d. f(x)→ ∞ 15. Which function is always positive? a. f(x)= 2 5x+4 1 1 b. f(x)= c. f(x)= d. B and C x²-2x-15 (x-5)²

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Chapter 15 Solutions

Basic Technical Mathematics

Ch. 15.1 - Use the factor theorem to determine whether t − 2...Ch. 15.1 - Prob. 2PE Ch. 15.1 - Prob. 3PE Ch. 15.1 - Prob. 4PE Ch. 15.1 - Prob. 1E Ch. 15.1 - Prob. 2E Ch. 15.1 - In Exercises 1–4, make the given changes in the...Ch. 15.1 - Prob. 4E Ch. 15.1 - Prob. 5E Ch. 15.1 - Prob. 6E

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The reason behind that a third-degree polynomial function with real coefficient cannot have zeros of 1, 2 and j .

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Chapter 15 Solutions