Explanation Description: The given equation is 64 d 3 − 144 d 2 + 108 d − 27 = 0 . Solve the equation 64 d 3 − 144 d 2 + 108 d − 27 = 0 graphically. Press the button “ Y = ” to access equation editor Y = and then write Y 1 = 64 X ^ 3 − 144 X ^ 2 + 108 X − 27 . Now, set the viewing window size as follows. X min = 0 , X max = 40 , and X s c l = 5 Y min = − 5 , 000 , Y max = 5 , 000 , Y s c l = 10000 and X r e s = 1 Press the button “ 2nd ” then “TRACE”, then select “ZERO” to find the x -intercept. For the left bound, move the cursor to the left of the intercept then hit ENTER will place a marker on screen. From the above screenshot, it is observed that y 1 = 0 at x ≈ 0.75 . Thus, the root of the equation is 3 4 Begin with 3 4 , perform synthetic division as follows

11th Edition

ISBN: 9780134437705

Author: Washington

Publisher: PEARSON

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Chapter 15, Problem 61RE

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To solve: The equation 64d3−144d2+108d−27=0 for the diameter d.

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Chapter 15, Problem 60RE

Chapter 15, Problem 62RE

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Chapter 15 Solutions

Basic Technical Mathematics

Ch. 15.1 - Use the factor theorem to determine whether t − 2...Ch. 15.1 - Prob. 2PE Ch. 15.1 - Prob. 3PE Ch. 15.1 - Prob. 4PE Ch. 15.1 - Prob. 1E Ch. 15.1 - Prob. 2E Ch. 15.1 - In Exercises 1–4, make the given changes in the...Ch. 15.1 - Prob. 4E Ch. 15.1 - Prob. 5E Ch. 15.1 - Prob. 6E

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The equation 64 d 3 − 144 d 2 + 108 d − 27 = 0 for the diameter d .

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To solve: The equation 64d3−144d2+108d−27=0 for the diameter d.

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Chapter 15 Solutions