Genetics: A Conceptual Approach
Genetics: A Conceptual Approach
6th Edition
ISBN: 9781319127121
Author: Pierce
Publisher: MAC HIGHER
Question
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Chapter 15.2, Problem 22AQP

(a)

Summary Introduction

To determine:

The amino acids specified by the given bacterial mRNA sequences.

Introduction:

Amino acids are the crucial component of all protein molecules. All amino acids are specified by a unique codon called genetic code. The genetic code is made up of nucleotide bases that form in groups to specify amino acids. The genetic code consists of a triplet code, in which three nucleotides encode a single amino acid in a protein. The genetic code has sixty-one codons that specify the twenty amino acids. The three codons are stop codons or nonsense codons that do not encode any amino acid.

(a)

Expert Solution
Check Mark

Explanation of Solution

By referring to figure 15.10 in the textbook, amino acids can be determined for the given mRNA sequence.

(a) 5'-AUGUUUAAAUUUAAAUUUUGA-3'

5'-AUGMet-UUUPhe-AAALys-UUUPhe-AAALys-UUUPhe-UGAstop-3'

The amino acids that are specified by this bacterial mRNA sequenceare:

Methionine-Phenylalanine-Lysine-Phenylalanine-Lysine-Phenylalanine-Stop

(b)

Summary Introduction

To determine:

The amino acids specified by the given bacterial mRNA sequences.

Introduction:

Amino acids are the crucial component of all protein molecules. All amino acids are specified by a unique codon called genetic code. The genetic code is made up of nucleotide bases that form in groups to specify amino acids. The genetic code consists of a triplet code, in which three nucleotides encode a single amino acid in a protein. The genetic code has sixty-one codons that specify the twenty amino acids. The three codons are stop codons or nonsense codons that do not encode any amino acid.

(b)

Expert Solution
Check Mark

Explanation of Solution

By referring to figure 15.10 in the textbook, amino acids can be determined for the given mRNA sequence.

(b) 5'-AGGGAAAUCAGAUGUAUAUAUAUAUAUGA-3'

5'-AGGArg-GAAGlu-AUCIle-AGAArg-UGUCys-AUAIle-UAUTyr-AUAIle-UAUTyr-GA-3'

The amino acids that are specified by this bacterial mRNA sequence are:

Arginine-Glutamate-Isoleucine-Arginine-Cysteine-Isoleucine-Tyrosine-Isoleucine Tyrosine. The last two nucleotides, GA will not encode any amino acid because it does not form a full codon.

(c)

Summary Introduction

To determine:

The amino acids specified by the given bacterial mRNA sequences.

Introduction:

Amino acids are the crucial component of all protein molecules. All amino acids are specified by a unique codon called genetic code. The genetic code is made up of nucleotide bases that form in groups to specify amino acids. The genetic code consists of a triplet code, in which three nucleotides encode a single amino acid in a protein. The genetic code has sixty-one codons that specify the twenty amino acids. The three codons are stop codons or nonsense codons that do not encode any amino acid.

(c)

Expert Solution
Check Mark

Explanation of Solution

By referring to figure 15.10 in the textbook, amino acids can be determined for the given mRNA sequence.

(c) 5'-UUUGGAUUGAGUGAAACGAUGGAUGAAAGAUUUCUCGCUUGA-3'

(5'-UUUPhe-GGAGly-UUGLeu-AGUSer-GAAGlu-ACGThr-AUGMet-GAUAsp-GAAGlu-AGAArg-UUUPhe-CUCLeu-GCUAla-UGAstop-3')

The amino acids that are specified by this bacterial mRNA sequence are:

Phenylalanine-Glycine-Leucine-Serine-Glutamate-Threonine-Methionine-Aspartate-Glutamate-Arginine-Phenylalanine-Leucine-Alanine-Stop.

(d)

Summary Introduction

To determine:

The amino acids specified by the given bacterial mRNA sequences.

Introduction:

Amino acids are the crucial component of all protein molecules. All amino acids are specified by a unique codon called genetic code. The genetic code is made up of nucleotide bases that form in groups to specify amino acids. The genetic code consists of a triplet code, in which three nucleotides encode a single amino acid in a protein. The genetic code has sixty-one codons that specify the twenty amino acids. The three codons are stop codons or nonsense codons that do not encode any amino acid.

(d)

Expert Solution
Check Mark

Explanation of Solution

By referring to figure 15.10 in the textbook, amino acids can be determined for the given mRNA sequence.

(d) 5'-GUACUAAGGAGGUUGUAUGGGUUAGGGGACAUCAUUUUGA-3'

(5'-GUAVal-CUALeu-AGGArg-AGGArg-UUGLeu-UAUTyr-GGGGly-UUALeu-GGGGly-GACAsp-AUCIle-AUUIle-UUGLeu-A-3')

The amino acids that are specified by this bacterial mRNA sequence are:

Valine-Leucine-Arginine-Arginine-Leucine-Tyrosine-Glycine-Leucine-Glycine-Aspartate-Isoleucine-Isoleucine-Leucine.

Conclusion:

Each codon consists of three nucleotides that encode a particular amino acid. There is one initiation codon AUG and three termination codons, UAA, UGA, and UAG.

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Amino Acid Coclow TABle 3' Gly Phe Leu (G) (F) (L) 3- Val (V) Arg (R) Ser (S) Ala (A) Lys (K) CAG G Glu Asp (E) (D) Ser (S) CCCAGUCAGUCAGUCAG 0204 C U A G C Asn (N) G 4 A AGU C GU (5) AC C UGA A G5 C CUGACUGACUGACUGAC Thr (T) Met (M) lle £€ (1) U 4 G Tyr Σε (Y) U Cys (C) C A G Trp (W) 3' U C A Leu בוט His Pro (P) ££ (H) Gin (Q) Arg 흐름 (R) (L) Start Stop 8. Transcription and Translation Practice: (Video 10-1 and 10-2) A. Below is the sense strand of a DNA gene. Using the sense strand, create the antisense DNA strand and label the 5' and 3' ends. B. Use the antisense strand that you create in part A as a template to create the mRNA transcript of the gene and label the 5' and 3' ends. C. Translate the mRNA you produced in part B into the polypeptide sequence making sure to follow all the rules of translation. 5'-AGCATGACTAATAGTTGTTGAGCTGTC-3' (sense strand) 4
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