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- Given the following information: My confidence intervals: 90% confidence interval = (2.33, 2.56), and 99% confidence interval = (2.26, 2.63) My peer's confidence intervals: 90% confidence interval at ( 2.37 , 2.61 ) and 99% confidence interval at ( 2.31 , 2.67). How do their confidence intervals compare with yours? If the population standard deviation is unknown and the sample size is not sufficiently large, would you still use the Normal distribution to calculate these confidence intervals, or would you choose another distribution? If the latter, which distribution would you choose?arrow_forwardIf a 95% confidence interval for two population proportions pi – p2 is a range of positive numbers, then what does this imply? With 95% confidence, the first population proportion is less than the second. With 95% confidence, there is no difference in the population proportions. O With 95% confidence, the first population proportion is greater than the second. O The relative size of the population proportions cannot be determined.arrow_forwardChapter 08, Section 8.2, Problem 011 For a data set obtained from a sample, n = 82 and I = 45.30. It is known that o = 3.8. a. What is the point estimate of u? The point estimate is b. Make a 97% confidence interval for u. Round your answers to two decimal places. c. What is the margin of error of estimate for part b? Round your answer to three decimal places.arrow_forward
- Chapter 08, Section 8.2, Problem 011 For a data set obtained from a sample, n = 79 and I = 49.05. It is known that o = 4.3. a. What is the point estimate of u? The point estimate is b. Make a 97% confidence interval for u. Round your answers to two decimal places. c. What is the margin of error of estimate for part b? Round your answer to three decimal places. E =arrow_forwardChapter 08, Section 8.3, Problem 044 The mean time taken to design a house plan by 38 architects was found to be 17 hours with a standard deviation of 3.30 hours. a. Construct a 95% confidence interval for the population mean u. Round your answers to two decimal places. to hours b. Suppose the confidence interval obtained in part a is too wide. Select all of the ways the width of this interval can be reduced. O Increasing the confidence level O Lowering the sample size Increasing the sample size O Lowering the confidence level Privacy Policy © 2000-2020 John Wiley & Sons, Inc. All Rights Reserved. A Division of John Wiley & Sons, Inc. MacBook Air 80 888 FB F9 F10 F1 * F2 F3 F4 * @ # $ 3 4 5 6. 7 8. 9 W T Y S D F G J K V B N M O,O O 0arrow_forwardI need help with solving parts 2 l, 3 and 6arrow_forward
- ES Chapter 09, Section 9.2, Problem 029a X Incorrect. Lazurus Steel Corporation produces iron rods that are supposed to be 36 inches long. The machine that makes these rods does not produce each rod exactly 36 inches long. The lengths of the rods are normally distributed and vary slightly. It is known that when the machine is working properly, the mean length of the rods is 36 inches. The standard deviation of the lengths of all rods produced on this machine is always equal to 0.035 inch. The quality control department at the company takes a sample of 20 such rods every week, calculates the mean length of these rods, and tests the null hypothesis, u = 36 inches, against the alternative hypothesis, u # 36 inches. If the null hypothesis is rejected, the machine is stopped and adjusted. A recent sample of 20 rods produced a mean length of 36.015 inches. Calculate the p-value for this test of hypothesis. Based on this p-value, will the quality control inspector decide to stop the machine…arrow_forward2) Parts A B C Darrow_forwardPrevious research showed that 15% percent of teenagers between the ages of 13 and 17 smoke. A study was conducted to examine the current proportion of US teenagers between the ages of 13 and 17 who smoke. A survey asked a random sample of 785 teenagers between the ages of 13 to 17 if they smoke. 71 of the surveyed teenagers responded that they smoke. The information above is for the question below.arrow_forward
- A sociologist plans to conduct a survey to estimate the percentage of healthcare professionals who believe in astrology. How many healthcare professionals must be surveyed if we want a confidence level of 92% and a margin of error of three percentage points? (NOTE: All areas are to four decimal places and all z-scores are to two decimal places except the two special cases at the bottom of the table) Insert the following values from the question: CL = Answer% E = Answer% = Answer What area relates to the confidence level? A = Answer What is the value of α? Answer What is the value of α/2? Answer What area value will you use on the z-score table? Answer What is the zα/2 value associated with that area? Answer Use the appropriate formula to find the number of people that must be tested (round up to a whole number): Answerarrow_forwardReview Example 8.5 and answer the following questions. EXAMPLE 8.5 Problem The average earnings per share (EPS) for 10 industrial stocks randomly selected from those listed on the Dow-Jones Industrial Average was found to be X = 1.85 with a standard deviation of s=0.395. Calculate a 99% confidence interval for the average EPS of all the industrials listed on the DJIA. 8 tra (M) SUSI+W₂ (√) tva I-tv,a a. A confidence interval is a type of estimator. What are we estimating in this example? b. Name each symbol in the confidence interval given and explain the use of the symbol. c Suppose you were conducting a two-tailed hypothesis test: Ho: m = 3.0 at a = .01. What do you conclude?arrow_forwardSection 10.4 Step 1 of 2 : Calculate a confidence interval for the mean sodium content in Oriental Spice Sauce. Round your answers to two decimal places. Step 2 of 2 : Using the confidence interval approach, is there evidence that the sodium content is different from what the nutrition label states?arrow_forward
- Glencoe Algebra 1, Student Edition, 9780079039897...AlgebraISBN:9780079039897Author:CarterPublisher:McGraw Hill